java.util.ConcurrentModificationException(如何避免ConcurrentModificationException)
java.util.ConcurrentModificationException is a very common exception when working with java collection classes. Java Collection classes are fail-fast, which means if the Collection will be changed while some thread is traversing over it using iterator, the iterator.next() will throw ConcurrentModificationException. Concurrent modification exception can come in case of multithreaded as well as single threaded java programming environment.
Table of Contents [hide]
java.util.ConcurrentModificationException

Let’s see the concurrent modification exception scenario with an example.
Copy
package com.journaldev.ConcurrentModificationException;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
public class ConcurrentModificationExceptionExample {
<span class="hljs-function"><span class="hljs-keyword">public</span> <span class="hljs-keyword">static</span> <span class="hljs-keyword">void</span> <span class="hljs-title">main</span>(<span class="hljs-params">String args[]</span>) </span>{
List<String> myList = <span class="hljs-keyword">new</span> ArrayList<String>();
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"1"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"2"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"3"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"4"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"5"</span>);
Iterator<String> it = myList.iterator();
<span class="hljs-keyword">while</span> (it.hasNext()) {
String <span class="hljs-keyword">value</span> = it.next();
System.<span class="hljs-keyword">out</span>.println(<span class="hljs-string">"List Value:"</span> + <span class="hljs-keyword">value</span>);
<span class="hljs-keyword">if</span> (<span class="hljs-keyword">value</span>.<span class="hljs-keyword">equals</span>(<span class="hljs-string">"3"</span>))
myList.<span class="hljs-keyword">remove</span>(<span class="hljs-keyword">value</span>);
}
Map<String, String> myMap = <span class="hljs-keyword">new</span> HashMap<String, String>();
myMap.put(<span class="hljs-string">"1"</span>, <span class="hljs-string">"1"</span>);
myMap.put(<span class="hljs-string">"2"</span>, <span class="hljs-string">"2"</span>);
myMap.put(<span class="hljs-string">"3"</span>, <span class="hljs-string">"3"</span>);
Iterator<String> it1 = myMap.keySet().iterator();
<span class="hljs-keyword">while</span> (it1.hasNext()) {
String key = it1.next();
System.<span class="hljs-keyword">out</span>.println(<span class="hljs-string">"Map Value:"</span> + myMap.<span class="hljs-keyword">get</span>(key));
<span class="hljs-keyword">if</span> (key.<span class="hljs-keyword">equals</span>(<span class="hljs-string">"2"</span>)) {
myMap.put(<span class="hljs-string">"1"</span>, <span class="hljs-string">"4"</span>);
<span class="hljs-comment">// myMap.put("4", "4");</span>
}
}
}
}
Above program will throw java.util.ConcurrentModificationException when executed, as shown in below console logs.
Copy
List Value:1
List Value:2
List Value:3
Exception in thread "main" java.util.ConcurrentModificationException
at java.base/java.util.ArrayList$Itr.checkForComodification(ArrayList.java:937)
at java.base/java.util.ArrayList$Itr.next(ArrayList.java:891)
at com.journaldev.ConcurrentModificationException.ConcurrentModificationExceptionExample.main(ConcurrentModificationExceptionExample.java:22)
From the output stack trace, its clear that the concurrent modification exception is coming when we call iterator next() function. If you are wondering how Iterator checks for the modification, its implementation is present in AbstractList class where an int variable modCount is defined. modCount provides the number of times list size has been changed. modCount value is used in every next() call to check for any modifications in a function checkForComodification().
Now comment the list part and run the program again. You will see that there is no ConcurrentModificationException being thrown now.
Output will be:
Copy
Map Value:3
Map Value:2
Map Value:4
Since we are updating the existing key value in the myMap, its size has not been changed and we are not getting ConcurrentModificationException. Note that the output may differ in your system because HashMap keyset is not ordered like list. If you will uncomment the statement where I am adding a new key-value in the HashMap, it will cause ConcurrentModificationException.
To Avoid ConcurrentModificationException in multi-threaded environment
- You can convert the list to an array and then iterate on the array. This approach works well for small or medium size list but if the list is large then it will affect the performance a lot.
- You can lock the list while iterating by putting it in a synchronized block. This approach is not recommended because it will cease the benefits of multithreading.
- If you are using JDK1.5 or higher then you can use ConcurrentHashMap and CopyOnWriteArrayList classes. This is the recommended approach to avoid concurrent modification exception.
To Avoid ConcurrentModificationException in single-threaded environment
You can use the iterator remove() function to remove the object from underlying collection object. But in this case you can remove the same object and not any other object from the list.
Let us run an example using Concurrent Collection classes:
Copy
package com.journaldev.ConcurrentModificationException;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.concurrent.ConcurrentHashMap;
import java.util.concurrent.CopyOnWriteArrayList;
public class AvoidConcurrentModificationException {
public static void main(String[] args) {
List<String> myList = new CopyOnWriteArrayList<String>();
myList.add("1");
myList.add("2");
myList.add("3");
myList.add("4");
myList.add("5");
Iterator<String> it = myList.iterator();
while (it.hasNext()) {
String value = it.next();
System.out.println("List Value:" + value);
if (value.equals("3")) {
myList.remove("4");
myList.add("6");
myList.add("7");
}
}
System.out.println("List Size:" + myList.size());
Map<String, String> myMap = new ConcurrentHashMap<String, String>();
myMap.put("1", "1");
myMap.put("2", "2");
myMap.put("3", "3");
Iterator<String> it1 = myMap.keySet().iterator();
while (it1.hasNext()) {
String key = it1.next();
System.out.println("Map Value:" + myMap.get(key));
if (key.equals("1")) {
myMap.remove("3");
myMap.put("4", "4");
myMap.put("5", "5");
}
}
System.out.println("Map Size:" + myMap.size());
}
}
Output of above program is shown below. You can see that there is no ConcurrentModificationException being thrown by the program.
Copy
List Value:1
List Value:2
List Value:3
List Value:4
List Value:5
List Size:6
Map Value:1
Map Value:2
Map Value:4
Map Value:5
Map Size:4
From the above example its clear that:
- Concurrent Collection classes can be modified safely, they will not throw ConcurrentModificationException.
- In case of CopyOnWriteArrayList, iterator doesn’t accommodate the changes in the list and works on the original list.
- In case of ConcurrentHashMap, the behaviour is not always the same.
For condition:
Copyif(key.equals("1")){
myMap.remove("3");}
Output is:
CopyMap Value:1
Map Value:null
Map Value:4
Map Value:2
Map Size:4
It is taking the new object added with key “4” but not the next added object with key “5”.
Now if I change the condition to below.
Copyif(key.equals("3")){
myMap.remove("2");}
Output is:
CopyMap Value:1
Map Value:3
Map Value:null
Map Size:4
In this case its not considering the new added objects.
So if you are using ConcurrentHashMap then avoid adding new objects as it can be processed depending on the keyset. Note that the same program can print different values in your system because HashMap keyset is not ordered.
Use for loop to avoid java.util.ConcurrentModificationException
If you are working on single-threaded environment and want your code to take care of the extra added objects in the list then you can do so using for loop rather than iterator.
Copy
for(int i = 0; i<myList.size(); i++){
System.out.println(myList.get(i));
if(myList.get(i).equals("3")){
myList.remove(i);
i--;
myList.add("6");
}
}
Note that I am decreasing the counter because I am removing the same object, if you have to remove the next or further far object then you don’t need to decrease the counter. Try it yourself.
java.util.ConcurrentModificationException(如何避免ConcurrentModificationException)的更多相关文章
- java.util.ConcurrentModificationException 解决办法(转载)
今天在项目的中有一个需求,需要在一个Set类型的集合中删除满足条件的对象,这时想当然地想到直接调用Set的remove(Object o)方法将指定的对象删除即可,测试代码: public cla ...
- java.util.ConcurrentModificationException --map
key:3-key key:/v1.02-key Exception in thread "main" java.util.ConcurrentModificationExcept ...
- 偶遇到 java.util.ConcurrentModificationException 的异常
今天在调试程序 遇到了如此问题 贴上代码来看看稍后分析 List<String> list = null;boolean isUpdate = false;try { list = JSO ...
- 对ArrayList操作时报错java.util.ConcurrentModificationException null
用iterator遍历集合时要注意的地方:不可以对iterator相关的地方做添加或删除操作.否则会报java.util.ConcurrentModificationException 例如如下代码: ...
- LinkedList - java.util.ConcurrentModificationException
package com.test.io; import java.io.BufferedReader; import java.io.FileNotFoundException; import jav ...
- java.util.ConcurrentModificationException 解决办法
在使用iterator.hasNext()操作迭代器的时候,如果此时迭代的对象发生改变,比如插入了新数据,或者有数据被删除. 则使用会报以下异常:Java.util.ConcurrentModific ...
- Iterator之java.util.ConcurrentModificationException
在运行以下代码时,会报java.util.ConcurrentModificationException异常, public class Demo { public static void main( ...
- java.util.ConcurrentModificationException 解决办法(转)
今天在项目的中有一个需求,需要在一个Set类型的集合中删除满足条件的对象,这时想当然地想到直接调用Set的remove(Object o)方法将指定的对象删除即可,测试代码: public cla ...
- java集合--java.util.ConcurrentModificationException异常
ConcurrentModificationException 异常:并发修改异常,当方法检测到对象的并发修改,但不允许这种修改时,抛出此异常.一个线程对collection集合迭代,另一个线程对Co ...
- list删除操作 java.util.ConcurrentModificationException
首先大家先看一段代码: public static void main(String[] args) { List<String> listStr = new ArrayList<S ...
随机推荐
- JavaLearning:日期操作类
package org.fun.classdemo; import java.util.Calendar; import java.util.GregorianCalendar; public cla ...
- eXtremeDB相关问题解答(3)
> 1. Could our database support multi-database under one single instance? > > 2. ...
- 基于TI Davinci架构的多核/双核开发高速扫盲(以OMAP L138为例),dm8168多核开发參考以及达芬奇系列资料user guide整理
基于TI Davinci架构的双核嵌入式应用处理器OMAPL138开发入门 原文转自http://blog.csdn.net/wangpengqi/article/details/8115614 感谢 ...
- Razor数组数据
控制器层 public ActionResult DemoArray() { Product[] array = { new Product {Name = "Kayak", Pr ...
- Vectorized implementation
Vectorization Vectorization refers to a powerful way to speed up your algorithms. Numerical computin ...
- NewtonSoft对象转json时,把 NULL 转 "" , 过滤 NULL, DateTime 时间类型去除 T
IsoDateTimeConverter timeConverter = new IsoDateTimeConverter(); timeConverter.DateTimeFormat = &quo ...
- Android网络通信Volley框架源代码浅析(一)
尊重原创http://blog.csdn.net/yuanzeyao/article/details/25837897 从今天開始,我打算为大家呈现关于Volley框架的源代码分析的文章,Volley ...
- POJ 1101 The Game(BFS+判方向)
The Game Description One morning, you wake up and think: "I am such a good programmer. Why ...
- Android学习笔记进阶十三获得本地全部照片
这是Intent的一个用法. 在ActivityAction里面有一个“ACTION_GET_CONTENT”字符串常量,该常量让用户选择特定类型的数据. intent.setType("i ...
- Shelled-out Commands In Golang
http://nathanleclaire.com/blog/2014/12/29/shelled-out-commands-in-golang/ Shelled-out Commands In Go ...