1064. Complete Binary Search Tree (30)

时间限制
100 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

  • The left subtree of a node contains only nodes with keys less than the node's key.
  • The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
  • Both the left and right subtrees must also be binary search trees.

A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.

Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<=1000). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.

Output Specification:

For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input:

10
1 2 3 4 5 6 7 8 9 0

Sample Output:

6 3 8 1 5 7 9 0 2 4

提交代码

 #include<cstdio>
#include<stack>
#include<algorithm>
#include<iostream>
#include<stack>
#include<set>
#include<map>
#include<cmath>
using namespace std;
int line[],tree[];
void Build(int *line,int *tree,int n,int cur){
if(!n){
return;
}
int h=log(n)/log();
int x=n-(pow(,h)-); //cout<<"x: "<<x<<endl; if(x>pow(,h-)){
x=pow(,h-);
} //cout<<"x: "<<x<<endl; int l=pow(,h-)+x-; //cout<<"l: "<<l<<endl; tree[cur]=line[l];
Build(line,tree,l,cur*+);
Build(line+l+,tree,n-l-,cur*+);
}
int main(){
//freopen("D:\\INPUT.txt","r",stdin);
int n,i;
scanf("%d",&n);
for(i=;i<n;i++){
scanf("%d",&line[i]);
}
sort(line,line+n);
Build(line,tree,n,);
printf("%d",tree[]);
for(i=;i<n;i++){
printf(" %d",tree[i]);
}
printf("\n");
return ;
}

pat1064. Complete Binary Search Tree (30)的更多相关文章

  1. PAT题库-1064. Complete Binary Search Tree (30)

    1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHE ...

  2. pat04-树8. Complete Binary Search Tree (30)

    04-树8. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHE ...

  3. pat 甲级 1064. Complete Binary Search Tree (30)

    1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHE ...

  4. PTA 04-树6 Complete Binary Search Tree (30分)

    题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/669 5-7 Complete Binary Search Tree   (30分) A ...

  5. 1064. Complete Binary Search Tree (30)【二叉树】——PAT (Advanced Level) Practise

    题目信息 1064. Complete Binary Search Tree (30) 时间限制100 ms 内存限制65536 kB 代码长度限制16000 B A Binary Search Tr ...

  6. PAT 甲级 1064 Complete Binary Search Tree (30 分)(不会做,重点复习,模拟中序遍历)

    1064 Complete Binary Search Tree (30 分)   A Binary Search Tree (BST) is recursively defined as a bin ...

  7. PAT甲级:1064 Complete Binary Search Tree (30分)

    PAT甲级:1064 Complete Binary Search Tree (30分) 题干 A Binary Search Tree (BST) is recursively defined as ...

  8. PAT1064. Complete Binary Search Tree

    1064. Complete Binary Search Tree 题目大意 给定一个序列, 求其 生成Complete BST 的层序遍历. 思路 最开始把这个题想复杂了, 还想着建立结构体, 其实 ...

  9. 04-树6 Complete Binary Search Tree (30 分)

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following propertie ...

随机推荐

  1. 十六、xx.xx.xx格式版本号大小比较

    DELIMITER $$ USE `deshangshidai`$$ DROP FUNCTION IF EXISTS `STRCMP_MY_VERSION`$$ CREATE DEFINER=`roo ...

  2. js中的Number方法

    1.Number.toExponential(fractionDigits) 把number转换成一个指数形式的字符串.可选参数控制其小数点后的数字位数.它必须在0~20之间. 例如: documen ...

  3. [hdu4960]Another OCD Patient(区间dp)

    题意:给出n个数,把这n个数合成一个对称的集合.每个数只能合并一次. 解题关键:区间dp,dp[l][r]表示l-r区间内满足条件的最大值.vi是大于0的,所以可以直接双指针确定. 转移方程:$dp[ ...

  4. [51nod1058]求N!的长度

    法1:stirling公式近似 $n! \approx \sqrt {2\pi n} {(\frac{n}{e})^n}$ (如果怕n不够大下式不成立,可以当数小于10000时用for求阶层) 也可以 ...

  5. Luogu 4317 花神的数论题

    披着数论题外衣的数位dp. 相当于数一数$[1,n]$范围内$1$的个数是$1,2,3,4,...log(n)$的数各有多少个,直接在二进制下数位dp. 然而我比较sb地把(1e7 + 7)当成了质数 ...

  6. 8、泛型程序设计与c++标准模板库5.函数对象

    1.函数对象 函数对象是STL提供的第四类主要组件,它使得STL的应用更加灵活方便,从而增强了算法的通用性.大多数STL算法可以用一个函数对象作为参数.所谓“函数对象”其实就是一个行为类似函数的对象, ...

  7. Struts2学习第二课 Struts2概述

    Struts2是一个用来开发MVC应用程序的框架,它提供了Web应用程序开发过程中的一些常见问题飞解决方案: -对来自用户的输入数据进行合法性验证 -统一的布局 -可扩展性 -国际化和本地化 -支持A ...

  8. 1.1 sql注入分类与详解

    1.基于报错的 SQL 盲注------构造 payload 让信息通过错误提示回显出来     这里来讲一下报错注入的原理(floor型爆错注入): 0x01:报错过程: 1.rand()用于产生一 ...

  9. 【C#】清除webBrowser 缓存和Cookie的解决方案

    试了很多方法,最后发现万剑大哥的方法管用,转载一下 转自:https://www.cnblogs.com/midcn/p/3527123.html 通过测试webBrowser与IE缓存和Cookie ...

  10. [Xcode 实际操作]四、常用控件-(16)为MKMapView指定地理坐标

    目录:[Swift]Xcode实际操作 本文将演示如何自定义地图视图的的地理坐标 在项目导航区,打开视图控制器的代码文件[ViewController.swift] import UIKit //首先 ...