Instructions

In this kata, you must create a digital root function.

A digital root is the recursive sum of all the digits in a number. Given n, take the sum of the digits of n. If that value has more than one digit, continue reducing in this way until a single-digit number is produced. This is only applicable to the natural numbers.

Here's how it works:

digital_root(16)
=> 1 + 6
=> 7 digital_root(942)
=> 9 + 4 + 2
=> 15 ...
=> 1 + 5
=> 6 digital_root(132189)
=> 1 + 3 + 2 + 1 + 8 + 9
=> 24 ...
=> 2 + 4
=> 6 digital_root(493193)
=> 4 + 9 + 3 + 1 + 9 + 3
=> 29 ...
=> 2 + 9
=> 11 ...
=> 1 + 1
=> 2

My solution:

def digital_root(n):
lst = [int(x) for x in str(n)]
result = sum(lst)
if result < 10:
return result
else:
return digital_root(result)

Best solution:

def digital_root(n):
return n if n < 10 else digital_root(sum(map(int,str(n))))

[codewars_python]Sum of Digits / Digital Root的更多相关文章

  1. Sum of Digits / Digital Root

    Sum of Digits / Digital Root In this kata, you must create a digital root function. A digital root i ...

  2. digital root问题

    问题阐述会是这样的: Given a non-negative integer num, repeatedly add all its digits until the result has only ...

  3. 快速切题 sgu118. Digital Root 秦九韶公式

    118. Digital Root time limit per test: 0.25 sec. memory limit per test: 4096 KB Let f(n) be a sum of ...

  4. Codeforces Beta Round #10 C. Digital Root 数学

    C. Digital Root 题目连接: http://www.codeforces.com/contest/10/problem/C Description Not long ago Billy ...

  5. Digital Root 的推导

    背景 在LeetCode上遇到这道题:Add Digits 大意是给一个数,把它各位数字相加得到一个数,如果这个数小于10就返回,不然继续 addDigits(这个相加得到的数). 题目很简单,但是如 ...

  6. codeforces 10C Digital Root(非原创)

    Not long ago Billy came across such a problem, where there were given three natural numbers A, B and ...

  7. 数字根(digital root)

    来源:LeetCode 258  Add Dights Question:Given a non-negative integer  num , repeatedly add all its digi ...

  8. 【HDOJ】4351 Digital root

    digital root = n==0 ? 0 : n%9==0 ? 9:n%9;可以简单证明一下n = a0*n^0 + a1*n^1 + ... + ak * n^kn%9 = a0+a1+..+ ...

  9. 树根 Digital root

    数根 (又称数字根Digital root)是自然数的一种性质.换句话说.每一个自然数都有一个数根.数根是将一正整数的各个位数相加(即横向相加),若加完后的值大于等于10的话,则继续将各位数进行横向相 ...

随机推荐

  1. C++归并排序总结

    #include <iostream> using namespace std; //归并排序非递归版. void Sort(int a[], int n,int high) { int ...

  2. 单点登录(二)使用Cookie+File实现单点登录登出(附源代码)

    上一篇文章<单点登录(一)使用Cookie+File实现单点登录>中,我们实现了单点登录的功能. 本文作为上一篇文章的扩展部分,加入"单点登出"功能. 源代码下载:链接 ...

  3. angularjs 模块化

    <!DOCTYPE HTML> <html ng-app="myApp"> <head> <meta http-equiv="C ...

  4. 51nod-1296: 有限制的排列

    [传送门:51nod-1296] 简要题意: 有一个集合,集合中的数为1到n 给出a限制条件,a[i]表示第a[i]位置的数要比相邻位置的数要小 给出b限制条件,b[i]表示第b[i]位置的数要比相邻 ...

  5. legend---九、js的核心是什么

    legend---九.js的核心是什么 一.总结 一句话总结:js里面一切东西都是对象,包括数组,字符串,所以你就知道数组啊,对象啊,的很多东西怎么用了 1.js如何合并两个数组? concat,ar ...

  6. List exercise

    The slice operator can take a third argument that determines the step size, so t[::2] creates a list ...

  7. Lists are mutable

    The syntax for accessing the elements of a list is the same as for accessing the characters of a str ...

  8. 1355: [Baltic2009]Radio Transmission

    Time Limit: 10 Sec  Memory Limit: 64 MBSubmit: 958  Solved: 659[Submit][Status][Discuss] Description ...

  9. PostgreSQL Replication之第四章 设置异步复制(7)

    4.7 冲突管理 在PostgreSQL中,流复制数据仅在一个方向流动.XLOG由master提供给几个slave,这些slave消耗事务日志并为您提供一个较好的数据备份.您可能想知道这怎么会导致冲突 ...

  10. PostgreSQL 系统表

    postgres=# \d pg_class      Table "pg_catalog.pg_class"     Column     |   Type    | Modif ...