January 16 2017 Week 3 Monday
In love, folly is always sweet.
恋爱中,干傻事总是让人感到十分美妙。
Love can easily get us in over our heads, so it is not strange that sometimes we may do some fool things.
Suggestion: To be a fool in love sometimes, don't be too smart.
The things that we love tell us what we are.
我们所爱之物昭示着我们究竟是谁。
I love money, so what am I?
January 16 2017 Week 3 Monday的更多相关文章
- January 09 2017 Week 2nd Monday
Patience is bitter, but its fruit is sweet. 忍耐是痛苦的,但它的果实是甜蜜的. Some patience may be just fruitless, o ...
- January 02 2017 Week 1st Monday
A day is a miniature of eternity. 一天是永恒的缩影. My life is short, but I can make something eternal. What ...
- January 23 2017 Week 4 Monday
Knowledge is long, life is short. 吾生也有涯,而知也无涯. I often feel that I have a lot of things to learn, ne ...
- January 30 2017 Week 5 Monday
I can accept defeat but could not accept to give up. 我可以接受失败,但不能接受放弃. Fortune has not always smiled ...
- 【模拟退火】Petrozavodsk Winter Training Camp 2017 Day 1: Jagiellonian U Contest, Monday, January 30, 2017 Problem F. Factory
让你在平面上取一个点,使得其到给定的所有点的距离和最小. 就是“费马点”. 模拟退火……日后学习一下,这是从网上扒的,先存下. #include<iostream> #include< ...
- 【动态规划】【二分】Petrozavodsk Winter Training Camp 2017 Day 1: Jagiellonian U Contest, Monday, January 30, 2017 Problem B. Dissertation
题意: 给定S1串,长度100w,S2串,长度1k.问它俩的LCS. f(i,j)表示S2串前i个字符,LCS为j时,最少需要的S1串的前缀长度.转移的时候,枚举下一个字符在S1的位置即可.(可以预处 ...
- 【二分】Petrozavodsk Winter Training Camp 2017 Day 1: Jagiellonian U Contest, Monday, January 30, 2017 Problem A. The Catcher in the Rye
一个区域,垂直分成三块,每块有一个速度限制,问你从左下角跑到右上角的最短时间. 将区域看作三块折射率不同的介质,可以证明,按照光路跑时间最短. 于是可以二分第一个入射角,此时可以推出射到最右侧边界上的 ...
- January 15th, 2018 Week 03rd Monday
We got things to do. Places to go. People to see. Futures to make. 我们有很多事情要做,有很多地方要去,有很多人要见,有很多美好的未来 ...
- October 09th 2017 Week 41st Monday
My motto is: Contended with little, yet wishing for more. 我的座右铭是:为一点点感到满足,但希望获得更多. If you can live y ...
随机推荐
- android viewpager 拿到当前显示的 fragment 的实例
一个 ViewPager 通过 FragmentPagerAdapter 绑定了 3 个 fragment 可以通过 Fragment fragment = getSupportFragmentMan ...
- Android JPush极光推送应用
JPush纠结了5-6个小时,一直报下面的错误,纠结! [AndroidUtil] AndroidManifest.xml missing required intent filter for Pus ...
- js中的闭包理解一
闭包是一个比较抽象的概念,尤其是对js新手来说.书上的解释实在是比较晦涩,对我来说也是一样. 但是他也是js能力提升中无法绕过的一环,几乎每次面试必问的问题,因为在回答的时候.你的答案的深度,对术语的 ...
- ubuntu16上安装openJDK.md
ubuntu16上安装openJDK.md 环境 操作系统:ubuntu 16.04.2 LTS 安装 当你不需要安装oracle的JDK时,使用openJDK,安装就比较方便. sudo apt-g ...
- PHP自然排序,非自然排序(未完成)
还要研究一下,暂时先添加个链接 参考:PHP数组的“自然”排序
- Timer 控件
1. 设置属性 Enable = true 或调用 start方法后, *_Tick 方法不会立即执行,会先等待一个时间间隔 2.timer1不管你上次的事情是否做完,它都会每个一个时间间隔做它应该 ...
- C#语言-03.逻辑控制语句
a. 逻辑控制语句: i. 条件语句:先对条件判断,然后根据判断结果执行不同的分支 . If 和 if-else:判断“布尔表达式的值”来决定执行那个代码块 a. 语法:if(布尔表达式){ b. 布 ...
- Vue-[v-model]理解示例
对应文档节点: https://vuefe.cn/v2/guide/components.html#Customizing-Component-v-model <body> <div ...
- php foreach遍历
foreach($facility_list['data'] as $facility){ //处理语句} 第一种格式遍历给定的 array_expression_r_r 数组.每次循环中,当前单元的 ...
- How to limit Dialog's max height?
1. We can make it to play trick in code. At Dialog's show function, after app has set contentView, w ...