Unique Paths [LeetCode]
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
How many possible unique paths are there?
Above is a 3 x 7 grid. How many possible unique paths are there?
Note: m and n will be at most 100.
Solution: Pretty easy, use dynamic programming, from bottom line to top line, caculate every the path num of every cell.
class Solution {
public:
int uniquePaths(int m, int n) {
if(m <= || n <= )
return ;
vector<int> nums;
for(int i = ; i < m; i ++) {
if(i == ) {
for(int j = ; j < n; j++)
nums.push_back();
} else {
for(int j = ; j < n; j ++) {
nums[j] += nums[j - ];
}
}
}
return nums[n - ];
}
};
Unique Paths [LeetCode]的更多相关文章
- Unique Paths ——LeetCode
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- Unique Paths leetcode java
题目: A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...
- [LeetCode] Unique Paths II 不同的路径之二
Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How m ...
- [LeetCode] Unique Paths 不同的路径
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- LeetCode: Unique Paths II 解题报告
Unique Paths II Total Accepted: 31019 Total Submissions: 110866My Submissions Question Solution Fol ...
- LeetCode: Unique Paths I & II & Minimum Path Sum
Title: https://leetcode.com/problems/unique-paths/ A robot is located at the top-left corner of a m ...
- LeetCode 62. Unique Paths(所有不同的路径)
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- 【一天一道LeetCode】#63. Unique Paths II
一天一道LeetCode (一)题目 Follow up for "Unique Paths": Now consider if some obstacles are added ...
- 【一天一道LeetCode】#62. Unique Paths
一天一道LeetCode系列 (一)题目 A robot is located at the top-left corner of a m x n grid (marked 'Start' in th ...
随机推荐
- 《微信开发日志》之OAuth2验证接口
OAuth2接口说明: 企业应用中的URL链接(包括自定义菜单或者消息中的链接),可以通过OAuth2.0验证接口来获取员工的身份信息. 通过此接口获取用户身份会有一定的时间开销.对于频繁获取用户身份 ...
- pupper基线加固
1. 概述 puppet是一个开源的软件自动化配置和部署工具,它使用简单且功能强大,正得到了越来越多地关注,现在很多大型IT公司均在使用puppet对集群中的软件进行管理和部署,如google利用p ...
- LINQ 如何实现 in 与 not in
T-SQL的IN: Select ProductID, ProductName, CategoryID From dbo.Products Where CategoryID , ) T-SQL的NOT ...
- linux 目录结构图解
参考资料:http://www.linuxidc.com/Linux/2016-08/134701.htm
- ScriptX.cab打印控件的使用,控件文件里有
1.在head里添加 <object id="factory" style="display:none;" viewastext classid=&quo ...
- MATLAB中的nargin与varargin的用法
nargin的用法: nargin:number of function input arguments,指的是一个函数的输入变量的个数. 用法:nargin或着nargin(fx), 其中fx指的是 ...
- (二)shell中case语句、程序传参、while
2.2.6.1.case语句(1)shell中的case语句和C语言中的switch case语句作用一样,格式有差异(2)shell中的case语句天生没有break,也不需要break,和C语言中 ...
- JAVA 程序设置运行内存
1.修改jdk设置 2.如果不行则 一般安装完eclipse之后,在安装目录下你应该可以看到有一个 eclipse.ini 文件,对了,就是在这个文件里面修改 -vmargs:说明后面是VM的参数 - ...
- iOS开发 Date转字符串
+ (NSString *)formatterDate:(NSNumber *)desDate WithDateFormatter:(NSString *)formatter{ NSDateForma ...
- ionic 原生日历控件不支持,改用 datepicker-for-ionic
具体参考地址 http://npm.taobao.org/package/datepicker-for-ionic