leetcode@ [174] Dungeon Game (Dynamic Programming)
https://leetcode.com/problems/dungeon-game/
The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way through the dungeon to rescue the princess.
The knight has an initial health point represented by a positive integer. If at any point his health point drops to 0 or below, he dies immediately.
Some of the rooms are guarded by demons, so the knight loses health (negative integers) upon entering these rooms; other rooms are either empty (0's) or contain magic orbs that increase the knight's health (positive integers).
In order to reach the princess as quickly as possible, the knight decides to move only rightward or downward in each step.
Write a function to determine the knight's minimum initial health so that he is able to rescue the princess.
For example, given the dungeon below, the initial health of the knight must be at least 7 if he follows the optimal path RIGHT->RIGHT->DOWN->DOWN.
| -2 (K) | -3 | 3 |
| -5 | -10 | 1 |
| 10 | 30 | -5 (P) |
Notes:
1.The knight's health has no upper bound.
2. Any room can contain threats or power-ups, even the first room the knight enters and the bottom-right room where the princess is imprisoned.
class Solution {
public:
int calculateMinimumHP(vector<vector<int>>& dungeon) {
if(dungeon.size() == ) return ;
int m = dungeon.size(), n = dungeon[].size();
vector<vector<int> > dp(m, vector<int>(n, ));
dp[m-][n-] = (-dungeon[m-][n-]<=)? : -dungeon[m-][n-];
for(int j=n-;j>=;--j) {
dp[m-][j] = (dp[m-][j+]-dungeon[m-][j] <= )? : dp[m-][j+]-dungeon[m-][j];
}
for(int i=m-;i>=;--i) {
dp[i][n-] = (dp[i+][n-]-dungeon[i][n-] <= )? : dp[i+][n-]-dungeon[i][n-];
}
for(int i=m-;i>=;--i) {
for(int j=n-;j>=;--j) {
bool flag = (dp[i][j+]<=dungeon[i][j] || dp[i+][j]<=dungeon[i][j]);
dp[i][j] = flag? : min(dp[i][j+]-dungeon[i][j], dp[i+][j]-dungeon[i][j]);
}
}
return dp[][];
}
};
leetcode@ [174] Dungeon Game (Dynamic Programming)的更多相关文章
- [LeetCode] 174. Dungeon Game 地牢游戏
The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. ...
- ✡ leetcode 174. Dungeon Game 地牢游戏 --------- java
The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. ...
- Java for LeetCode 174 Dungeon Game
The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. ...
- Leetcode#174 Dungeon Game
原题地址 典型的地图寻路问题 如何计算当前位置最少需要多少体力呢?无非就是在向下走或向右走两个方案里做出选择罢了. 如果向下走,看看当前位置能提供多少体力(如果是恶魔就是负数,如果是草药就是正数),如 ...
- leetcode@ [134] Gas station (Dynamic Programming)
https://leetcode.com/problems/gas-station/ 题目: There are N gas stations along a circular route, wher ...
- leetcode@ [322] Coin Change (Dynamic Programming)
https://leetcode.com/problems/coin-change/ You are given coins of different denominations and a tota ...
- leetcode@ [91] Decode Ways (Dynamic Programming)
https://leetcode.com/problems/decode-ways/ A message containing letters from A-Z is being encoded to ...
- [leetcode]174. Dungeon Game地牢游戏
The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. ...
- LeetCode 174. Dungeon Game (C++)
题目: The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dung ...
随机推荐
- Unity3D开发(一):NGUI之UIRoot屏幕分辨率自适应
原地址:http://blog.csdn.net/onerain88/article/details/11713299 NGUI在Unity3D游戏开发中非常常用,而NGUI对于每一个UI场景,都是以 ...
- PYTHON设计模式,创建型之工厂方法模式
我感觉和上一个差不多,可能不要动最要的地方吧... #!/usr/bin/evn python #coding:utf8 class Pizza(object): def prepare(self, ...
- mvc+entity framework database first,生成的model每次更新一个表会更新所有的model
在使用Entity Framework 的Database frist或model first时,直接加attribute到modle类上是太现实也不合理的,因为model类是自动生成的,重新生成后会 ...
- web页面浮动回到顶部功能和浮动广告
实现测试浮动回到顶部 法一:用js实现<%@ Page Language="C#" AutoEventWireup="true" CodeBehind=& ...
- 分布式事务的管理--atomikos
在一些业务场景及技术架构下,跨库的事务时不可避免的,这时候如何统一管理事务,保证事务的强一致性是整个系统稳定.可用基石.一些中间件如tuxedo.cics就是凭借这个能力占据了金融.电信.银行等很大的 ...
- 安装Ubuntu双系统系列——安装Ubuntu
一.将Ubuntu系统烧进U盘 1.打开老毛桃,选择“U盘启动” -> "ISO模式":选择ISO文件,我这里安装的是Ubuntu12.04-64bit,你可以在网上下载一个 ...
- Java汉字排序(2)按拼音排序
对于包含汉字的字符串来说,排序的方式主要有两种:一种是拼音,一种是笔画. 本文就讲述如何实现按拼音排序的比较器(Comparator). 作者:Jeff 发表于:2007年12月21日 11:27 最 ...
- Android 常用UI控件之TabHost(5)Tab栏在底部且在最上层也不盖tab页
tab栏在底部 <TabHost android:id="@android:id/tabhost" android:layout_width="match_pare ...
- Android开发之布局的学习
FrameLayout-帧布局 实现效果: 代码: <?xml version="1.0" encoding="utf-8"?> <Frame ...
- write_chip,read_chip
int write_chip(UINT32 addr, UINT32 data) { if(0 == fpgaRWMode) /* localbus mode */ { UINT16 datah, d ...