UVA227

步骤：1.把输入的数字和空格保存。（这里用到gets函数读取整行）2.定位空格。3.输入指令。

#include<stdio.h>
#include<string.h>
][];//声明数组
int main(){
    memset(a,,sizeof(a));
    ;
    ;
    ];
    ];
    //输入网格
    gets(a[]);
    gets(a[]);
    gets(a[]);
    gets(a[]);
    gets(a[]);
    //定位空格
    ; x<; x++)
    {
        ; y<; y++)
        {
            if(a[x][y] == ' ')
            {
                blank_x = x;
                blank_y = y;
            }
        }
    }
    gets(s);//输入指令
    ;s[i] != ';i++){
        if(s[i] == 'A'){
            ][blank_y])
                {
                 printf("1 This puzzle has no final configuration.\n");
                 ;}
            a[blank_x][blank_y]=a[blank_x-][blank_y];
            a[blank_x-][blank_y]=' ';
            blank_x=blank_x-;
        }
        else if(s[i] == 'B'){
            ][blank_y])
                    {
                 printf("2 This puzzle has no final configuration.\n");
                 ;}
            a[blank_x][blank_y]=a[blank_x+][blank_y];
            a[blank_x+][blank_y]=' ';
            blank_x=blank_x+;
        }
        else if(s[i] == 'L'){
            ])
                    {
                 printf("3 This puzzle has no final configuration.\n");
                 ;}
            a[blank_x][blank_y]=a[blank_x][blank_y-];
            a[blank_x][blank_y-]=' ';
            blank_y=blank_y-;
        }
        else if(s[i] == 'R'){
            ])
                {
                 printf("4 This puzzle has no final configuration.\n");
                 ;}
            a[blank_x][blank_y]=a[blank_x][blank_y+];
            a[blank_x][blank_y+]=' ';
            blank_y=blank_y+;
        }
    }
    //输出
    puts(a[]);
    puts(a[]);
    puts(a[]);
    puts(a[]);
    puts(a[]);
    ;
}

OJ里还要加Puzzle #1:...