Palindrome Permutation -- LeetCode

Given a string, determine if a permutation of the string could form a palindrome.

For example,
"code" -> False, "aab" -> True, "carerac" -> True.

要点：学习如何iterate一个unordered_map。

 class Solution {
 public:
     bool canPermutePalindrome(string s) {
         unordered_map<char, int> dict;
         for (int i = , n = s.size(); i < n; i++) {
             if (dict.count(s[i]) == )
                 dict.insert(make_pair(s[i], ));
             else dict[s[i]]++;
         }
         int oddCount = ;
         for (auto it = dict.begin(); it != dict.end(); it++) {
             if (it->second % ) oddCount++;
             if (oddCount > ) return false;
         }
         return true;
     }
 };