mysql笔试题大餐---1、组合查询方式及having
mysql笔试题大餐---1、组合查询方式及having
一、总结
一句话总结:
实践:我之前的mysql真的学的太浅了,这种情况下,依据实践(做题)才是唯一能把它学好的方式
学的暂时够了,以实践而学
项目中可以考虑多使用原生查询:简单,方便,查询效率高,记忆负担小,有用(考都是考这个)
1、查询考了100分的学生的信息(三种查询方式)?
#嵌套查询:小括号括住嵌套部分:select * from student s where s.s_id in (select ss_s_id from student_score where ss_score=100)
#普通多表查询:from后接多个表,where后接表相连条件:select * from student s,student_score ss where s.s_id=ss.ss_s_id and ss.ss_score=100
#链接查询:比如inner join ... on ...:select * from student s inner join student_score ss on s.s_id=ss.ss_s_id where ss.ss_score=100
2、group by如何使用?
1、注意group by的字段要被选出去:select 类别, sum(数量) as 数量之和 from A group by 类别
2、函数比如count,sum是作用在group by的那个字段上的,也就是group by选好的基础上的
select 类别, sum(数量) as 数量之和 from A group by 类别
3、查询每个学生分别考了几门课程(group by的实例)?
注意group by的字段为ss_s_id的字段,count作用的也是ss_s_id字段
链接查询:select student.s_name,count(ss_s_id) from student inner join student_score on student.s_id=student_score.ss_s_id group by ss_s_id;
普通多表查询:select s.s_name,count(ss.ss_s_id) from student s,student_score ss where s.s_id=ss.ss_s_id group by ss.ss_s_id
#链接查询
###注意group by的字段为ss_s_id的字段,count作用的也是id字段
select student.s_name,count(ss_s_id) from student inner join student_score on student.s_id=student_score.ss_s_id group by ss_s_id;
#普通多表查询
select s.s_name,count(ss.ss_s_id) from student s,student_score ss where s.s_id=ss.ss_s_id group by ss.ss_s_id
4、Group By 和 Order By一起怎么使用?
select 类别, sum(数量) AS 数量之和 from A group by 类别 order by sum(数量) desc
注意你想看到什么字段的排序结果,你就用什么字段排序:包括函数作用的group by的字段,比如order by count(ss_s_id) asc
查询每个学生分别考了几门课程,并且按课程数量从低到高排序:select student.s_name,count(ss_s_id) from student inner join student_score on student.s_id=student_score.ss_s_id group by ss_s_id order by count(ss_s_id) asc;
5、字段如何起别名?
空格:原始字段 别名:count(sc_s_id) num
mysql中的别名都是以空格来连接
select student.s_name,count(sc_s_id) num from student inner join student_score on student.s_id=student_score.sc_s_id group by sc_s_id order by num asc;
6、如何给数据库起别名?
空格:原始数据库名 数据库别名:from student s
mysql中的别名都是以空格来连接
select s.s_name,count(sc_s_id) num from student s inner join student_score sc on s.s_id=sc.sc_s_id group by sc_s_id order by num asc;
7、where后面的多个条件如何连接?
用脑子:直接and:where s.s_id=ss.ss_s_id and ss.ss_score=100
select * from student s,student_score ss where s.s_id=ss.ss_s_id and ss.ss_score=100
8、普通多表查询 和 链接查询 的区别?
普通多表查询:where s.s_id=ss.ss_s_id;直接from两表
链接查询:on s.s_id=ss.ss_s_id:inner join另外一个表
#普通多表查询
select * from student s,student_score ss where s.s_id=ss.ss_s_id and ss.ss_score=100
#链接查询
select * from student s inner join student_score ss on s.s_id=ss.ss_s_id where ss.ss_score=100
9、嵌套查询怎么写?
直接把嵌套的内容放到小括号里面即可
查询考了100分的学生的信息:select * from student s where s.s_id in (select ss_s_id from student_score where ss_score=100)
#查询考了100分的学生的信息
#嵌套查询
select * from student s where s.s_id in (select ss_s_id from student_score where ss_score=100)
10、多表链接查询?
多个inner join连在一起即可
select * from student s inner join student_score ss on s.s_id=ss.ss_s_id inner join course c on c.c_id=ss.ss_c_id order by s.s_name;
11、mysql中的符号说明(空格和逗号)?
并列用 逗号:select s.s_name,count(sc_s_id) num from
别名用 空格:select s.s_name,count(sc_s_id) num from
12、查询“01:牛顿力学”课程比“2:狂人日记”课程成绩高的所有学生的学号; (多条记录之间比较大小)?
1、多条记录之间比较大小,用的是嵌套查询:将嵌套查询的部分起别名:(select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1) a
2、嵌套查询出来的内容可以直接起别名后用点的方式查看:select a.ss_s_id from (select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1) a,
3、最后的比较条学生分数,又比较学生id:where a.ss_score>b.ss_score and a.ss_s_id=b.ss_s_id
4、嵌套查询部分如何起别名:from (select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1) a,
select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1
select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=2
select a.ss_s_id from (select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1) a,(select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=2) b where a.ss_score>b.ss_score and a.ss_s_id=b.ss_s_id
13、mysql中的having是什么意思?
和where一样选条件:和where一样都是选条件的,但是 因为having是从前筛选的字段再筛选,而where是从数据表中的字段直接进行的筛选的。
出错条件:select goods_price,goods_name from sw_goods having goods_price > 100:上面的having可以用的前提是我已经筛选出了goods_price字段,在这种情况下和where的效果是等效的,但是如果我没有select goods_price 就会报错!!
误区:不要错误的认为having和group by 必须配合使用。
14、having和where的区别是什么?
having是从前筛选的字段再筛选:上面的having可以用的前提是我已经筛选出了goods_price字段,在这种情况下和where的效果是等效的,但是如果我没有select goods_price 就会报错!!
where是从数据表中的字段直接进行的筛选的:
having是从前筛选的字段再筛选:select goods_price,goods_name from sw_goods having goods_price > 100:上面的having可以用的前提是我已经筛选出了goods_price字段,在这种情况下和where的效果是等效的,但是如果我没有select goods_price 就会报错!!
where是从数据表中的字段直接进行的筛选的:
15、where和having都可以使用的场景?
字段被筛选出来了:比如 select goods_price之后,where和having都可以对goods_price操作
select goods_price,goods_name from sw_goods where goods_price > 100
select goods_price,goods_name from sw_goods having goods_price > 100
解释:上面的having可以用的前提是我已经筛选出了goods_price字段,在这种情况下和where的效果是等效的,但是如果我没有select goods_price 就会报错!!因为having是从前筛选的字段再筛选,而where是从数据表中的字段直接进行的筛选的。
16、为什么having总是和group by搭配使用?
1、因为group by一定会保证having的字段被选
2、group by只能和having搭配:因为group by出来的东西数据库没有,比如avg(ss.ss_score),所以不能用where
3、我猜having速度比where快:因为having是从前筛选的字段再筛选,而where是从数据表中的字段直接进行的筛选的。
#2、查询平均成绩大于60分的同学的学号和平均成绩;
select ss.ss_s_id,avg(ss.ss_score) from student_score ss group by ss.ss_s_id having avg(ss.ss_score) > 60;
17、如何复制 navicat 查询出来的结果?
选工具栏中 导出当前结果 即可:可以有多种导出方式
18、group by + having的使用场景是什么?
group by之后,要对依赖group by的字段(比如avg(ss.ss_score))进行选择判断:比如 查询平均成绩大于60分的同学的学号和平均成绩;
select ss.ss_s_id,avg(ss.ss_score) from student_score ss group by ss.ss_s_id having avg(ss.ss_score) > 60;
19、对学生分组查询的时候,能够选择select *么?
可以,不推荐:select ss.*,avg(ss.ss_score) from student_score ss group by ss.ss_s_id having avg(ss.ss_score) > 60;
20、查询平均成绩大于60分的同学的学号和平均成绩?
平均成绩怎么弄(每个人学科数量不一样):group by + having +avg:group by ss.ss_s_id having avg(ss.ss_score) > 60;
原理:group by将每个人的信息分组,avg将group by出来的每个人的分数平均,having来选这个平均分
#2、查询平均成绩大于60分的同学的学号和平均成绩;
##平均成绩怎么弄(每个人学科数量不一样):group by + having +avg:group by ss.ss_s_id having avg(ss.ss_score) > 60;
##原理:group by将每个人的信息分组,avg将group by出来的每个人的分数平均,having来选这个平均分
#having
select ss.ss_s_id,avg(ss.ss_score) from student_score ss group by ss.ss_s_id having avg(ss.ss_score) > 60;
select ss.*,avg(ss.ss_score) from student_score ss group by ss.ss_s_id having avg(ss.ss_score) > 60;
二、对应数据库结构及sql
1、查询
select * from student; #查询每个学生的课程成绩-链接查询
select * from student inner join student_score on student.s_id=student_score.ss_s_id; #查询每个学生分别考了几门课程-链接查询
###注意group by的字段为count的字段
select student.s_name,count(ss_s_id) from student inner join student_score on student.s_id=student_score.ss_s_id group by ss_s_id;
#普通多表查询
select s.s_name,count(ss.ss_s_id) from student s,student_score ss where s.s_id=ss.ss_s_id group by ss.ss_s_id #查询每个学生分别考了几门课程,并且按课程数量从低到高排序
###注意你想要什么字段,就用什么字段排序
select student.s_name,count(ss_s_id) from student inner join student_score on student.s_id=student_score.ss_s_id group by ss_s_id order by count(ss_s_id) asc;
#字段别名
select student.s_name,count(ss_s_id) num from student inner join student_score on student.s_id=student_score.ss_s_id group by ss_s_id order by num asc;
#数据库别名
select s.s_name,count(ss_s_id) num from student s inner join student_score ss on s.s_id=ss.ss_s_id group by ss_s_id order by num asc; #查询考了100分的学生的信息
#嵌套查询
select * from student s where s.s_id in (select ss_s_id from student_score where ss_score=100)
#普通多表查询
select * from student s,student_score ss where s.s_id=ss.ss_s_id and ss.ss_score=100
#链接查询
select * from student s inner join student_score ss on s.s_id=ss.ss_s_id where ss.ss_score=100 #将学生的成绩 按照学生姓名排到一块
select * from student s inner join student_score ss on s.s_id=ss.ss_s_id inner join course c on c.c_id=ss.ss_c_id inner join teacher t on c.c_t_id=t.t_id order by s.s_id,c.c_id asc; #1、查询“01:牛顿力学”课程比“2:狂人日记”课程成绩高的所有学生的学号; (多条记录之间比较大小)
##多条记录之间比较大小,用的是嵌套查询:将嵌套查询的部分起别名
##嵌套查询出来的内容可以直接用点的方式查看:select a.ss_s_id from (select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1) a,
##最后的比较条学生分数,又比较学生id:where a.ss_score>b.ss_score and a.ss_s_id=b.ss_s_id
select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1
select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=2
select a.ss_s_id from (select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=1) a,(select ss.ss_s_id,ss.ss_score from student_score ss where ss.ss_c_id=2) b where a.ss_score>b.ss_score and a.ss_s_id=b.ss_s_id #2、查询平均成绩大于60分的同学的学号和平均成绩;
##平均成绩怎么弄(每个人学科数量不一样):group by + having +avg:group by ss.ss_s_id having avg(ss.ss_score) > 60;
##原理:group by将每个人的信息分组,avg将group by出来的每个人的分数平均,having来选这个平均分
#having
select ss.ss_s_id,avg(ss.ss_score) from student_score ss group by ss.ss_s_id having avg(ss.ss_score) > 60;
select ss.*,avg(ss.ss_score) from student_score ss group by ss.ss_s_id having avg(ss.ss_score) > 60;
2、数据库结构
/*
Navicat Premium Data Transfer Source Server : localhost_3306
Source Server Type : MySQL
Source Server Version : 50553
Source Host : localhost:3306
Source Schema : test_2019_06_10 Target Server Type : MySQL
Target Server Version : 50553
File Encoding : 65001 Date: 10/06/2019 13:55:45
*/ SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0; -- ----------------------------
-- Table structure for course
-- ----------------------------
DROP TABLE IF EXISTS `course`;
CREATE TABLE `course` (
`c_id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT COMMENT '课程表id',
`c_name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci DEFAULT NULL,
`c_t_id` int(11) DEFAULT NULL COMMENT '课程对应的老师的id',
PRIMARY KEY (`c_id`) USING BTREE
) ENGINE = MyISAM AUTO_INCREMENT = 5 CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic; -- ----------------------------
-- Records of course
-- ----------------------------
INSERT INTO `course` VALUES (1, '牛顿力学', 1);
INSERT INTO `course` VALUES (2, '狂人日记', 2);
INSERT INTO `course` VALUES (3, '鲁迅作品集', 2);
INSERT INTO `course` VALUES (4, '史记', 3); -- ----------------------------
-- Table structure for student
-- ----------------------------
DROP TABLE IF EXISTS `student`;
CREATE TABLE `student` (
`s_id` int(11) UNSIGNED NOT NULL AUTO_INCREMENT COMMENT '学生表主键',
`s_name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci DEFAULT NULL,
`s_age` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci DEFAULT NULL,
`s_sex` tinyint(2) DEFAULT NULL,
PRIMARY KEY (`s_id`) USING BTREE
) ENGINE = MyISAM AUTO_INCREMENT = 4 CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic; -- ----------------------------
-- Records of student
-- ----------------------------
INSERT INTO `student` VALUES (1, '张三', '', 0);
INSERT INTO `student` VALUES (2, '王丽丽', '', 1);
INSERT INTO `student` VALUES (3, '李四', '', 0); -- ----------------------------
-- Table structure for student_score
-- ----------------------------
DROP TABLE IF EXISTS `student_score`;
CREATE TABLE `student_score` (
`ss_id` int(11) NOT NULL AUTO_INCREMENT,
`ss_s_id` int(11) DEFAULT NULL,
`ss_c_id` int(11) DEFAULT NULL,
`ss_score` int(11) DEFAULT NULL,
PRIMARY KEY (`ss_id`) USING BTREE
) ENGINE = MyISAM AUTO_INCREMENT = 7 CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Fixed; -- ----------------------------
-- Records of student_score
-- ----------------------------
INSERT INTO `student_score` VALUES (1, 1, 1, 75);
INSERT INTO `student_score` VALUES (2, 2, 1, 98);
INSERT INTO `student_score` VALUES (3, 3, 3, 54);
INSERT INTO `student_score` VALUES (4, 1, 4, 100);
INSERT INTO `student_score` VALUES (5, 2, 2, 43);
INSERT INTO `student_score` VALUES (6, 2, 3, 100); -- ----------------------------
-- Table structure for teacher
-- ----------------------------
DROP TABLE IF EXISTS `teacher`;
CREATE TABLE `teacher` (
`t_id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`t_name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci DEFAULT NULL,
PRIMARY KEY (`t_id`) USING BTREE
) ENGINE = MyISAM AUTO_INCREMENT = 4 CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic; -- ----------------------------
-- Records of teacher
-- ----------------------------
INSERT INTO `teacher` VALUES (1, '牛顿');
INSERT INTO `teacher` VALUES (2, '鲁迅');
INSERT INTO `teacher` VALUES (3, '司马迁'); SET FOREIGN_KEY_CHECKS = 1;
三、某硕笔试题mysql数据库部分(较为全面)
转自或参考:某硕笔试题mysql数据库部分(较为全面)
https://www.cnblogs.com/zjfjava/p/6012443.html
Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
问题:
1、查询“001”课程比“002”课程成绩高的所有学生的学号;
select a.S# from (select s#,score from SC where C#='') a,(select s#,score
from SC where C#='') b
where a.score>b.score and a.s#=b.s#;
2、查询平均成绩大于60分的同学的学号和平均成绩;
select S#,avg(score)
from sc
group by S# having avg(score) >60;
3、查询所有同学的学号、姓名、选课数、总成绩;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname
4、查询姓“李”的老师的个数;
select count(distinct(Tname))
from Teacher
where Tname like '李%';
5、查询没学过“叶平”老师课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平');
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#=''and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='');
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名;
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='叶平'));
8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='') score2
from Student,SC where Student.S#=SC.S# and C#='') S_2 where score2 <score;
9、查询所有课程成绩小于60分的同学的学号、姓名;
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查询没有学全所有课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名;
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='';
12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#='');
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩;
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='叶平');
14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名;
select S# from SC where C# in (select C# from SC where S#='')
group by S# having count(*)=(select count(*) from SC where S#='');
15、删除学习“叶平”老师课的SC表记录;
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平';
16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2、
号课的平均成绩;
Insert SC select S#,'',(Select avg(score)
from SC where C#='') from Student where S# not in (Select S# from SC where C#='');
17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分
SELECT S# as 学生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='') AS 数据库
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='') AS 企业管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='') AS 英语
,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分
SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序
SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0) AS 平均成绩
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004)
SELECT SUM(CASE WHEN C# ='' THEN score ELSE 0 END)/SUM(CASE C# WHEN '' THEN 1 ELSE 0 END) AS 企业管理平均分
,100 * SUM(CASE WHEN C# = '' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '' THEN 1 ELSE 0 END) AS 企业管理及格百分数
,SUM(CASE WHEN C# = '' THEN score ELSE 0 END)/SUM(CASE C# WHEN '' THEN 1 ELSE 0 END) AS 马克思平均分
,100 * SUM(CASE WHEN C# = '' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '' THEN 1 ELSE 0 END) AS 马克思及格百分数
,SUM(CASE WHEN C# = '' THEN score ELSE 0 END)/SUM(CASE C# WHEN '' THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN C# = '' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '' THEN 1 ELSE 0 END) AS UML及格百分数
,SUM(CASE WHEN C# = '' THEN score ELSE 0 END)/SUM(CASE C# WHEN '' THEN 1 ELSE 0 END) AS 数据库平均分
,100 * SUM(CASE WHEN C# = '' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '' THEN 1 ELSE 0 END) AS 数据库及格百分数
FROM SC
21、查询不同老师所教不同课程平均分从高到低显示
SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教师姓名,C.C# AS 课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、查询如下课程成绩第 3 名到第 6 名的学生成绩单:企业管理(001),马克思(002),UML (003),数据库(004)
[学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩
SELECT DISTINCT top 3
SC.S# As 学生学号,
Student.Sname AS 学生姓名 ,
T1.score AS 企业管理,
T2.score AS 马克思,
T3.score AS UML,
T4.score AS 数据库,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 总分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = ''
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = ''
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = ''
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = ''
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);
23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as 课程ID, Cname as 课程名称
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;
24、查询学生平均成绩及其名次
SELECT 1+(SELECT COUNT( distinct 平均成绩)
FROM (SELECT S#,AVG(score) AS 平均成绩
FROM SC
GROUP BY S#
) AS T1
WHERE 平均成绩 > T2.平均成绩) as 名次,
S# as 学生学号,平均成绩
FROM (SELECT S#,AVG(score) 平均成绩
FROM SC
GROUP BY S#
) AS T2
ORDER BY 平均成绩 desc;
25、查询各科成绩前三名的记录:(不考虑成绩并列情况)
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
26、查询每门课程被选修的学生数
select c#,count(S#) from sc group by C#;
27、查询出只选修了一门课程的全部学生的学号和姓名
select SC.S#,Student.Sname,count(C#) AS 选课数
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
28、查询男生、女生人数
Select count(Ssex) as 男生人数 from Student group by Ssex having Ssex='男';
Select count(Ssex) as 女生人数 from Student group by Ssex having Ssex='女';
29、查询姓“张”的学生名单
SELECT Sname FROM Student WHERE Sname like '张%';
30、查询同名同性学生名单,并统计同名人数
select Sname,count(*) from Student group by Sname having count(*)>1;;
31、1981年出生的学生名单(注:Student表中Sage列的类型是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(char(11),DATEPART(year,Sage))='';
32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
33、查询平均成绩大于85的所有学生的学号、姓名和平均成绩
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;
34、查询课程名称为“数据库”,且分数低于60的学生姓名和分数
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='数据库'and score <60;
35、查询所有学生的选课情况;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
37、查询不及格的课程,并按课程号从大到小排列
select c# from sc where scor e <60 order by C# ;
38、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='';
39、求选了课程的学生人数
select count(*) from sc;
40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='叶平' and SC.score=(select max(score)from SC where C#=C.C# );
41、查询各个课程及相应的选修人数
select count(*) from sc group by C#;
42、查询不同课程成绩相同的学生的学号、课程号、学生成绩
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
43、查询每门功成绩最好的前两名
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列
select C# as 课程号,count(*) as 人数
from sc
group by C#
order by count(*) desc,c#
45、检索至少选修两门课程的学生学号
select S#
from sc
group by s#
having count(*) > = 2
46、查询全部学生都选修的课程的课程号和课程名
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
47、查询没学过“叶平”老师讲授的任一门课程的学生姓名
select Sname
from Student
where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='叶平');
48、查询两门以上不及格课程的同学的学号及其平均成绩
select S#,avg(isnull(score,0))
from SC
where S# in (select S# from SC where score <60 group by S# having count(*)>2)
group by S#;
49、检索“004”课程分数小于60,按分数降序排列的同学学号
select S#
from SC
where C#=''and score <60
order by score desc;
50、删除“002”同学的“001”课程的成绩
delete from Sc where S#=''and C#='';
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