HDU 5875 Function 2016 ACM/ICPC Asia Regional Dalian Online
N个数(N<=100000),M个询问,每次询问L,R,求F(L,R)。
F(L,R)=F(L,R-1)%A[R] , L<R
这道题数据比较鶸 可以直接用递减爆 正确做法应该是倍增
用倍增的思想,对于位置i右侧的最长下降子序列,next[i][j]表示位置i右边第2j个的位置,预处理出每个位置的next数组
每次做的时候尽量远跳,直到找到next[j][0]恰好小于当前的值z,则z对A[next[j][0]]取模,移动左标记,继续查找,直到超出R或者没有更小的数
//
//by coolxxx
//#include<bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<string>
#include<iomanip>
#include<map>
#include<stack>
#include<queue>
#include<set>
#include<bitset>
#include<memory.h>
#include<time.h>
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
//#include<stdbool.h>
#include<math.h>
#define min(a,b) ((a)<(b)?(a):(b))
#define max(a,b) ((a)>(b)?(a):(b))
#define abs(a) ((a)>0?(a):(-(a)))
#define lowbit(a) (a&(-a))
#define sqr(a) ((a)*(a))
#define swap(a,b) ((a)^=(b),(b)^=(a),(a)^=(b))
#define mem(a,b) memset(a,b,sizeof(a))
#define eps (1e-10)
#define J 10000
#define mod 1000000007
#define MAX 0x7f7f7f7f
#define PI 3.14159265358979323
#pragma comment(linker,"/STACK:1024000000,1024000000")
#define N 100004
#define M 18
using namespace std;
typedef long long LL;
double anss;
LL aans;
int cas,cass;
int n,m,lll,ans;
int a[N],s[N];
int nextt[N][M];
void init()
{
int i,j,k,top;
s[top=]=n;
for(i=;i<M;i++)nextt[n][i]=n+;
for(i=n-;i;i--)
{
while(top && a[i]<a[s[top]])top--;
if(!top)nextt[i][]=n+;
else nextt[i][]=s[top];
s[++top]=i;
}
for(j=;j<M;j++)
{
for(i=;i<n;i++)
{
k=nextt[i][j-];
nextt[i][j]=nextt[k][j-];
}
}
}
int work(int l,int r)
{
int i,j,z=a[l];
if(l==r)return z;
while(l<r)
{
if(!z)return z;
for(i=;i<M-;i++)
{
if(a[nextt[l][]]<=z || nextt[l][i]>r)break;
if(a[nextt[l][i+]]<=z || nextt[l][i+]>r)
{
l=nextt[l][i];
i=-;
continue;
}
}
if(i==M || nextt[l][i]>r || !a[nextt[l][i]])return z;
z%=a[nextt[l][]];l=nextt[l][];
}
return z;
}
int main()
{
#ifndef ONLINE_JUDGE
// freopen("1.txt","r",stdin);
// freopen("2.txt","w",stdout);
#endif
int i,j,k;
int x,y,z;
// init();
for(scanf("%d",&cass);cass;cass--)
// for(scanf("%d",&cas),cass=1;cass<=cas;cass++)
// while(~scanf("%s",s))
// while(~scanf("%d",&n))
{
scanf("%d",&n);
for(i=;i<=n;i++)scanf("%d",a+i);
init();
scanf("%d",&m);
for(i=;i<=m;i++)
{
scanf("%d%d",&x,&y);
printf("%d\n",work(x,y));
}
}
return ;
}
/*
// //
*/
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