EasyUi DataGrid 获取选中行的checkbox

EasyUi DataGrid 获取选中行的checkbox

 var checked = $(":checkbox[name=ID]:checked");
            console.log(checked);
            var IDS = new Array();
            $.each(checked, function (i, v) {
                IDS[i] = v.value;
            });

获取行的内容

 var row = $('#jgrid').datagrid('getSelected');