Minimum Depth of Binary Tree,求树的最小深度
算法分析:递归和非递归两种方法。
public class MinimumDepthofBinaryTree { //递归,树的最小深度,就是它左右子树的最小深度的最小值+1
public int minDepth(TreeNode root) {
if(root == null)
{
return 0;
}
int lmin = minDepth(root.left);
int rmin = minDepth(root.right);
if(lmin == 0 && rmin == 0)
{
return 1;
}
if(lmin == 0)//左子树为空,右子树不为空,则最小深度为右子子树的最小深度+1
{
return rmin + 1;
}
if(rmin == 0)
{
return lmin + 1;
}
return Math.min(lmin, rmin)+1;
} //非递归,按层遍历,找到第一个叶子结点
public int minDepth2(TreeNode root) {
if(root == null)
{
return 0;
}
ArrayList<TreeNode> list = new ArrayList<>();
int count = 1;//初始值为1
list.add(root);
while(!list.isEmpty())
{
ArrayList<TreeNode> temp = new ArrayList<>();
for (TreeNode node : list) {
if(node.left == null && node.right == null)//当节点左右子树都为空时,该节点为第一个叶子节点,该节点的深度即为树的最小深度
{
return count;
}
if(node.left != null)
{
temp.add(node.left);
}
if(node.right != null)
{
temp.add(node.right);
}
}
count ++;//按层遍历,每循环一次,就是一层,层数加1
list = temp;
}
return count;
}
}
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