Starting in the top left corner of a 22 grid, and only being able to move to the right and down, there are exactly 6 routes to the bottom right corner.

How many such routes are there through a 2020 grid?

题目大意:

从一个22网格的左上角开始,有6条(不允许往回走)通往右下角的路。

对于2020的网格,这样的路有多少条?

// (Problem 15)Lattice paths
// Completed on Tue, 11 Feb 2014, 23:58
// Language: VC++2010
//
// 版权所有(C)acutus (mail: acutus@126.com)
// 博客地址:http://www.cnblogs.com/acutus/
#include<iostream>
#include<cmath>
using namespace std; long long a[][]; int main()
{
int i;
for(i = ; i < ; i++)
{
a[][i] = ;
a[i][] = ;
}
for (i = ; i < ; i++)
for (int j = ; j < ; j++)
a[i][j] = a[i][j-] + a[i-][j];
cout<<a[][]<<endl;
return ;
}
Answer:
137846528820

(Problem 15)Lattice paths的更多相关文章

  1. (Problem 42)Coded triangle numbers

    The nth term of the sequence of triangle numbers is given by, tn = ½n(n+1); so the first ten triangl ...

  2. (Problem 46)Goldbach's other conjecture

    It was proposed by Christian Goldbach that every odd composite number can be written as the sum of a ...

  3. (Problem 49)Prime permutations

    The arithmetic sequence, 1487, 4817, 8147, in which each of the terms increases by 3330, is unusual ...

  4. (Problem 47)Distinct primes factors

    The first two consecutive numbers to have two distinct prime factors are: 14 = 2  7 15 = 3  5 The fi ...

  5. (Problem 29)Distinct powers

    Consider all integer combinations ofabfor 2a5 and 2b5: 22=4, 23=8, 24=16, 25=32 32=9, 33=27, 34=81, ...

  6. (Problem 28)Number spiral diagonals

    Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is forme ...

  7. (Problem 22)Names scores

    Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over five-tho ...

  8. (Problem 16)Power digit sum

    215 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26. What is the sum of the digits of th ...

  9. (Problem 73)Counting fractions in a range

    Consider the fraction, n/d, where n and d are positive integers. If nd and HCF(n,d)=1, it is called ...

随机推荐

  1. grunt切换下载源

    nrm 是一个 NPM 源管理器,允许你快速地在NPM 源间切换: 安装:npm install -g nrm 列出可选源:nrm ls 切换:nrm use taobao 测试所有源连接时间:nrm ...

  2. FPGA知识大梳理(四)FPGA中的复位系统大汇总

    本文整合特权(吴厚航)和coyoo(王敏志)两位大神的博文.我也很推崇这两位大神的书籍,特权的书籍要偏基础一下,大家不要一听我这么说就想买coyoo的.我还是那一句话,做技术就要step by ste ...

  3. 输出1到最大的N位数

    题目:输入数字n,按顺序输出从1最大的n位10进制数.比如输入3,则输出1.2.3一直到最大的3位数即999. 分析:这是一道很有意思的题目.看起来很简单,其实里面却有不少的玄机. 应聘者在解决这个问 ...

  4. HDU 3486 Interviewe

    题目大意:给定n个数的序列,让我们找前面k个区间的最大值之和,每个区间长度为n/k,如果有剩余的区间长度不足n/k则无视之.现在让我们找最小的k使得和严格大于m. 题解:二分k,然后求RMQ检验. S ...

  5. DRP过后,感受知识间的通性

    DRP视频看了不短的时间,真正开始DRP的时间是7月17号,至今两个月了.由于暑假期间英语的学习占得时间比较多,所以DRP视频进行的很慢.9月11号看完了DRP所有的视频,这个项目完成后最大的感受是: ...

  6. java软件工程师成长过程的学习

    第一阶段:Java基础,包括java语法,面向对象特征,常见API,集合框架: *第二阶段:java界面编程,包括AWT,事件机制,SWING,这个部分也可以跳过,用的时候再看都能来及: *第三阶段: ...

  7. android经常使用的电话操作

    给大家分享一下我的一个Android工具类,能够获取手机里面的各种信息,包含拨打电话. 获取全部联系人姓名及电话,插入联系人姓名及电话,插入联系人姓名及电话.插入通话记录.获取用户全部短信.批量插入短 ...

  8. HDU4712+随机算法

    随机算法 求n个20位的2进制串的MinDist. Dist:两个串的异或结果中1的个数 /* 随机算法 */ #include<algorithm> #include<iostre ...

  9. No.3小白的HTML+CSS心得篇

    A--看的东西多了总会出现好多模糊不清的又长的很像的的词语 今天对此进行区别分析下 1. align 与 text-align的区别 align 在W3Cschool中是这样解释的  ----alig ...

  10. Implement custom foreach function in C#

    http://msdn.microsoft.com/en-us/library/System.Collections.IEnumerator.aspx http://support.microsoft ...