Sql字段动态比较判断

<sql id="getUserInfoList_body">
SELECT * from userinfo
<dynamic prepend="WHERE">
  <isNotNull prepend="AND" property="id"> a.id=#id#</isNotNull>
  <isNotNull prepend="AND" property="userName"> a.userName like concat('%', #userName#, '%') </isNotNull>
  <isNotNull prepend="AND" property="inschoolTimeEnd"> a.inschoolTime &lt; #inschoolTimeEnd# </isNotNull>
  <isNotNull property="roleID">
<isEqual property="roleID" compareValue="3" prepend="AND">
addrProvinceID in (SELECT areaID FROM co_user_area WHERE adminID = #adminID#)</isEqual>
<isEqual property="roleID" compareValue="4" prepend="AND">
addrCityID in (SELECT areaID FROM co_user_area WHERE adminID = #adminID#)</isEqual>
  </isNotNull>
</dynamic>
ORDER BY a.id DESC
</sql>

sql语句返回主键id     

<insert id="">      //注意无需resultClass

  <selectKey resultClass="int" keyProperty="id">
  SELECT @@IDENTITY AS id
  </selectKey>
</insert> public Integer insert(Invoice invoice) throws DAOException {
return (Integer)getSqlMapClientTemplate().insert("insert",invoice);
}

sql时间范围查询条件  

//一
< isNotNull prepend="AND" property="createStartDateStr">
  CONVERT(varchar(100), kb.createDate , 23) &gt;= #createStartDateStr#
</isNotNull>
<isNotNull prepend="AND" property="createEndDateStr">
  CONVERT(varchar(100),kb.createDate,23) &lt;=#createEndDateStr#
</isNotNull> //二
<isNotNull prepend="AND" property="startTime">
  kc.createDate >= #startTime#
</isNotNull>
<isNotNull prepend="AND" property="endTime">
  <![CDATA[kc.createDate <= #endTime#]]>
</isNotNull> //三
<isNotNull prepend="AND" property="startTime">
  CONVERT(varchar(100), kb.createDate , 23) &gt;= #startTime#
</isNotNull>
<isNotNull prepend="AND" property="endTime">
  CONVERT(varchar(100), kb.createDate , 23) &lt;= #endTime#
</isNotNull>

sql每月数据统计  

SELECT
COUNT(DISTINCT kes.userID) AS examCount,
CONVERT(nvarchar(7), kesd.createTime, 120) AS month
FROM kp_out_system kos WITH (NOLOCK)
LEFT JOIN kp_exam_score kes WITH (NOLOCK)
ON kes.outSystemSign = kos.outSystemSign
LEFT JOIN kp_exam_score_detail kesd WITH (NOLOCK)
ON kesd.examScoreID = kes.id AND kesd.valid = 1
< isNotNull prepend="AND" property="startTime"> kesd.createTime &gt;= #startTime# </isNotNull>
<isNotNull prepend="AND" property="endTime"> kesd.createTime &lt;= #endTime# </isNotNull>
WHERE kos.status = 1
<isNotNull prepend="AND" property="outSystemSign"> kos.outSystemSign=#outSystemSign# </isNotNull>
AND kos.outSystemSign IS NOT NULL AND kos.sysAreaID IS NOT NULL AND kesd.createTime IS NOT NULL
GROUP BY CONVERT(nvarchar(7), kesd.createTime, 120)
ORDER BY CONVERT(nvarchar(7), kesd.createTime, 120)

sqlsum()结果判空 

SELECT ISNULL(SUM(myTable.thesisCount),0) AS thesisCount FROM (
  SELECT
COUNT(kuu.id) AS thesisCount,
ISNULL(kos.outSystemName, '无') AS outSystemName
FROM kp_out_system kos WITH (NOLOCK)
LEFT JOIN kp_user_upload_thesis kuu WITH (NOLOCK) ON kuu.outSystemSign = kos.outSystemSign AND kuu.valid = 1
WHERE kos.status = 1
   <isNotNull prepend="AND" property="outSystemSign"> kuu.outSystemSign = #outSystemSign# </isNotNull>
AND kos.outSystemSign IS NOT NULL AND kos.sysAreaID IS NOT NULL
GROUP BY ISNULL(kos.outSystemName, '无')
) AS myTable

验证某个属性是否已存在(修改信息时用)

select COUNT(*) from ... where id != #id# and ... = #...#

sql数组传参(in

//Action代码
if (null != studyID && 2 == studyID.intValue()) {
Integer[] studyIDs = new Integer[] { 2,3, 4 };
userInfo.setStudyIDs(studyIDs);
} else {
userInfo.setStudyID(studyID);
} //Xml文件
<isNotNull prepend="AND" property="studyID">
a.studyID=#studyID#
</isNotNull>
<isNotNull prepend="AND" property="studyIDs">
a.studyID in
<iterate property="studyIDs" open="(" close=")" conjunction=",">
#studyIDs[]#
</iterate>
</isNotNull>

Int类型拼接需要使用cast()  

SELECT (SELECT DISTINCT
CAST(studyID AS varchar) + ','
FROM kp_study_type
WHERE outSystemSign = 'drivingcoach' AND valid = 1
FOR xml PATH (''))
AS studyIDs,
ISNULL(
SUM(CASE
WHEN b.isPass = 1 THEN 1 ELSE 0
END), 0) AS isPassCount,
ISNULL(
SUM(CASE
WHEN b.isOpen = 1 OR b.isOpen = 3 THEN 1 ELSE 0
END), 0) AS isOpenCount,
ISNULL(
SUM(CASE
WHEN b.isOpen = 1 OR b.isOpen = 3 THEN 0 ELSE 1
END), 0) AS isNotOpenCount
FROM kp_study_type a WITH (NOLOCK)
INNER JOIN kp_select_studyType b WITH (NOLOCK)
ON a.studyID = b.studyID AND b.valid = 1
INNER JOIN kp_user_info kui WITH (NOLOCK)
ON kui.ID = b.userID AND kui.valid = 1
LEFT JOIN (SELECT
k.studyID,
k.userID,
SUM(k.studyTimes) studyTimes,
SUM(CASE
WHEN k.studyTimes >= k.studyTime * 60 THEN 1 ELSE 0
END) coursefinishCount,
COUNT(k.courseID) courseCount
FROM (SELECT
r.studyID,
t.userID,
SUM(t.studyTimes) AS studyTimes,
r.courseID,
r.studyTime
FROM kp_studyCourse_relation r WITH (NOLOCK)
LEFT JOIN kp_course c WITH (NOLOCK)
ON r.courseID = c.id
LEFT JOIN kp_study_course_time t WITH (NOLOCK)
ON c.courseNumber = t.courseNumber AND t.studyID = r.studyID
WHERE r.valid = 1 AND c.valid = 1 AND t.id IS NOT NULL
GROUP BY r.studyID,
t.userID,
r.courseID,
r.studyTime) k
GROUP BY k.studyID,
k.userID) e
ON a.studyID = e.studyID AND b.userID = e.userID
WHERE a.valid = 1 AND a.studyID IN (SELECT DISTINCT
studyID
FROM kp_select_studyType
WHERE outerSystemSign = 'drivingcoach' AND valid = 1 AND isOpen = 1)

sql截取字符串 

SELECT DISTINCT
ISNULL(SUBSTRING(areaID, 1, 6), 0) AS areaID
FROM kp_user_info

SELECT
TOP 10
kui.username
FROM kp_user_info kui WITH (NOLOCK)
LEFT JOIN dic_area dc WITH (NOLOCK)
ON RIGHT(kui.areaID, 6) = dc.areaID

地区搜索,传参设置

if(null != provinceID && !"000000".equals(provinceID)){
productOrder.setAreaID(provinceID);
}
if(null!=cityID && cityID != ""){
//数据库存储为110000:110101,依据存储方式设置
productOrder.setAreaID(provinceID+":"+cityID);
} <dynamic prepend="">
<isNotNull prepend="AND" property="areaID">
    kui.areaID like #areaID# + '%'
   </isNotNull>
</dynamic>

以...开头

*
FROM computer
WHERE sex = '男' AND LEFT(name, 1) IN ('李', '陈')

SELECT
*
FROM computer
WHERE sex = '男'
(and name like '李__'or name like '陈__')

跨库复制表数据

//-1-
SET IDENTITY_INSERT cdel_jxjy_flat20171106..op_ip_login_control ON;
//-2-
INSERT INTO cdel_jxjy_flat20171106..op_ip_login_control (id, ip, notes, valid, creator, createTime)
SELECT * FROM cdel_jxjy_flat0725..op_ip_login_control

Mapper查询技巧的更多相关文章

  1. SQL高级查询技巧

    SQL高级查询技巧   1.UNION,EXCEPT,INTERSECT运算符 A,UNION 运算符 UNION 运算符通过组合其他两个结果表(例如 TABLE1 和 TABLE2)并消去表中任何重 ...

  2. google查询技巧

    技巧一:使用正确的方法 无论你是使用一个简单或是高级的Google搜索,在此都存在你应该使用的某种可靠的方法.遵循适当的方法你就能获得非常准确的结果:要是忽略这条建议的话,你也许就会看到大量不相关的结 ...

  3. MySQL翻页查询技巧

    在查询大量数据库,一般都会采用翻页.自然会想到offset跟limit. 今天知道了一个技巧,用id查询.因为id是主键,查起来很快. 思路是:给id一个区间做where条件,将数据分隔成几份,然后每 ...

  4. SQLServer多条件查询技巧

    2019-10-15  13:31:04 在实际项目开发中,有很多页面都会出现多条件查询功能,类似于这种情况: 牵扯到数据就少不了数据库了.这么多条件的查询,如果要用常规的if else来写判断逻辑的 ...

  5. 2020想进大厂你不得不了解的MySQL意外事件的查询技巧

    导读:数据库是导致应用系统运行缓慢的常见原因.面对数据库引性能问题,很多开发者或者DBA却束手无策.本文作者经过多年的实际经验,整理了一些材料,将Linux环境下MySQL性能突发事件问题排查技巧分享 ...

  6. 【转】sql各种查询技巧

    高级查询在数据库中用得是最频繁的,也是应用最广泛的. Ø 基本常用查询 --select select * from student;   --all 查询所有 select all sex from ...

  7. SQL高级查询技巧(两次JOIN同一个表,自包含JOIN,不等JOIN)

    掌握了这些,就比较高级啦 Using the Same Table Twice 如下面查询中的branch字段 SELECT a.account_id, e.emp_id, b_a.name open ...

  8. Oracle优化查询技巧

    1. WHERE子句中的连接顺序:Oracle采用自下而上的顺序解析WHERE子句,根据这个原理,表之间的连接必须写在其他WHERE条件之前, 那些可以过滤掉最大数量记录的条件必须写在WHERE子句的 ...

  9. hql查询技巧

    要擅于利用对象之间映射的集合去查与其关联的对象,而不是直接在dao层重新写查询的方法,其实,hibernate正是对复杂查询的一种解放,既然有现成的东西,何必再去闭门造车,而且造出来的还是个旧车. 查 ...

随机推荐

  1. 在开发板上显示英文字符和汉字--tiny6410

    程序字符需要改成gb2312.否则无法正常显示中文字符. main.c代码: #include <sys/types.h> #include <sys/stat.h> #inc ...

  2. docker基础属性简介包含镜像 容器 registry服务等概念及关系

    Docker 镜像 我们都知道,操作系统分为内核和用户空间.对于 Linux 而言,内核启动后,会挂载 root 文件系统为其提供用户空间支持.而 Docker 镜像(Image),就相当于是一个 r ...

  3. HelloGitHub 月刊最受欢迎的开源项目 Top10(2020 年)

    作者:HelloGitHub-卤蛋 2020 年已成往事,2021 年悄然而至. 在已经过完的 2020 年里 HelloGitHub 共发布了 12 期月刊,推荐了 419 个开源项目.​每个月的 ...

  4. 第二章 信号量及条件变量(三)——> 重点

    2.4.4 信号量的应用 1. 利用信号量实现进程互斥   为使多个进程能互斥的访问某临界资源,只需为该资源设置一个互斥信号量mutex,并设置其初值为 1 ,然后讲个进程访问该资源的临界区CS置于w ...

  5. spark:reducebykey与groupbykey的区别

    从源码看: reduceBykey与groupbykey: 都调用函数combineByKeyWithClassTag[V]((v: V) => v, func, func, partition ...

  6. JDK动态代理案例与原理分析

    一.JDK动态代理实现案例 Person接口 package com.zhoucong.proxy.jdk; public interface Person { // 寻找真爱 void findlo ...

  7. 在Docker下进行MyCAT管理双主双从MySQL集群

    前言 在Docker下双主双从MySQL集群模拟 https://www.cnblogs.com/yumq/p/14259964.html 本文实验配置文件 Docker拉取MyCAT镜像 如果没启动 ...

  8. 多年经验总结,写出最惊艳的 Markdown 高级用法

    点赞再看,养成习惯,微信搜索[高级前端进阶]关注我. 本文 GitHub https://github.com/yygmind 已收录,有一线大厂面试完整考点和系列文章,欢迎 Star. 最近在学习的 ...

  9. java对象

    原文链接http://zhhll.icu/2020/04/26/java%E5%9F%BA%E7%A1%80/%E9%9D%A2%E5%90%91%E5%AF%B9%E8%B1%A1/java%E5% ...

  10. 在IDEA中通过Module管理多个项目

    你身边有没有这种顽固的Eclipse忠实用户:IDEA不能一个窗口管理多个项目!太不方便了! 对于一个窗口同时管理多个项目的需求,在我们日常开发时候是经常需要的.尤其当我们在分布式环境下,在一个窗口中 ...