【LeetCode】House Robber III(337)
1. Description
The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all houses in this place forms a binary tree". It will automatically contact the police if two directly-linked houses were broken into on the same night.
Determine the maximum amount of money the thief can rob tonight without alerting the police.
Example 1:
3
/ \
2 3
\ \
3 1
Maximum amount of money the thief can rob = 3 + 3 + 1 = 7.
Example 2:
3
/ \
4 5
/ \ \
1 3 1
Maximum amount of money the thief can rob = 4 + 5 = 9.
2. Answer
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public int rob(TreeNode root) {
if (root == null)
return 0;
int first = root.val;
int second = 0;
if (root.left != null) {
first += rob(root.left.left);
first += rob(root.left.right);
second += rob(root.left);
}
if (root.right != null) {
first += rob(root.right.left);
first += rob(root.right.right);
second += rob(root.right);
} return (first > second) ? first : second;
}
}
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