【Django】Django 如何实现 如下 联表 JOIN 查询?
SQL语句:
select distinct a.device_hash, sum(b.cmn_merge_count) from
(select distinct device_hash from tbl_fileprotect_svc_instance where customer_id='3f500ac5-020d-3ce3-a2a2-51a59ddd606e')
as a left join tbl_file_protect_alarm as b on a.device_hash = b.device_hash group by a.device_hash;
简化SQL如下(把子查询转化为WHERE语句):
select distinct a.device_hash, sum(b.cmn_merge_count) from
tbl_fileprotect_svc_instance
as a left join tbl_file_protect_alarm as b on a.device_hash = b.device_hash
where a.customer_id='3f500ac5-020d-3ce3-a2a2-51a59ddd606e'
group by a.device_hash; select distinct a.device_hash, sum(b.cmn_merge_count) from tbl_fileprotect_svc_instance as a left join tbl_file_protect_alarm as b on a.device_hash = b.device_hash where a.customer_id='3f500ac5-020d-3ce3-a2a2-51a59ddd606e' group by a.device_hash; select distinct a.device_hash, sum(b.cmn_merge_count) as alarm_sum from tbl_fileprotect_svc_instance as a left join tbl_file_protect_alarm as b on a.device_hash = b.device_hash where a.customer_id='3f500ac5-020d-3ce3-a2a2-51a59ddd606e' group by a.device_hash;
Django代码:
TODO:
方法一:
ret = []
device_list = models.FILE_PROTECT_INSTANCE.objects.filter(customer_id=customer_id)
for item in device_list:
tmp_dict = {}
tmp_dict['device_hash'] = item.device_hash
tmp_dict['hostname'] = item.hostname
tmp_dict['status'] = item.status
from django.db.models import Sum
alarm_sum_group_items = models.FILE_PROTECT_ALARM.objects.filter(customer_id=customer_id).filter(device_hash=tmp_dict['device_hash']).values('device_hash').annotate(alarm_sum=Sum('cmn_merge_count'))
#tmp_dict['customer_id'] = customer_id
tmp_dict['alarm_sum'] = alarm_sum_group_items[]['alarm_sum'] if (len(alarm_sum_group_items)!=) else
ret.append(tmp_dict)
方法二: hashes = A.objects.values_list("device_hash", flat=True).filter(customer_id="3f500ac5-020d-3ce3-a2a2-51a59ddd606e") B.objects.filter(device_hash__in=hashes).values_list("device_hash").annotate(Sum("cmn_merge_count"))
SQL实现聚合查询统计(Sum,Count等)
from django.db.models import Sum
#start_time = datetime.utcfromtimestamp(data['start_time']).replace(tzinfo=utc)
#end_time = datetime.utcfromtimestamp(data['end_time']).replace(tzinfo=utc)
end_time = datetime.now()
start_time = end_time + timedelta(days=-)
condition['cmn_alert_time__range'] = (start_time, end_time)
#alarm_sum_group_items_day = models.FILE_PROTECT_ALARM.objects.filter(**condition).values('customer_id').annotate(alarm_sum_day=Sum('cmn_merge_count'))
alarm_sum_day = models.FILE_PROTECT_ALARM.objects.filter(**condition).aggregate(Sum("cmn_merge_count"))
day_sum = alarm_sum_day['cmn_merge_count__sum'] if (alarm_sum_day['cmn_merge_count__sum'] is not None) else end_time = datetime.now()
start_time = end_time + timedelta(days=-)
condition['cmn_alert_time__range'] = (start_time, end_time)
#alarm_sum_group_items_week = models.FILE_PROTECT_ALARM.objects.filter(**condition).values('customer_id').annotate(alarm_sum_week=Sum('cmn_merge_count'))
alarm_sum_week = models.FILE_PROTECT_ALARM.objects.filter(**condition).aggregate(Sum("cmn_merge_count"))
week_sum = alarm_sum_week['cmn_merge_count__sum'] if (alarm_sum_week['cmn_merge_count__sum'] is not None) else condition = {}
#condition['device_hash'] = data['device_hash']
condition['customer_id'] = customer_id
end_time = datetime.now()
#start_time = end_time + timedelta(days=-)
condition['cmn_alert_time__lte'] = end_time
#alarm_sum_group_items_all = models.FILE_PROTECT_ALARM.objects.filter(**condition).values('customer_id').annotate(alarm_sum_all=Sum('cmn_merge_count'))
alarm_sum_all = models.FILE_PROTECT_ALARM.objects.filter(**condition).aggregate(Sum("cmn_merge_count"))
all_sum = alarm_sum_all['cmn_merge_count__sum'] if (alarm_sum_all['cmn_merge_count__sum'] is not None) else 参考资料:
http://stackoverflow.com/questions/6481279/django-sum-query
参考资料:
DINSTINCT: http://www.w3school.com.cn/sql/sql_distinct.asp
RAW语句实现:http://yeelone.blog.51cto.com/1476571/946694
http://www.it165.net/database/html/201207/2755.html
http://stackoverflow.com/questions/21355601/django-orm-inner-join
http://djangobook.py3k.cn/2.0/chapter10/
http://blog.csdn.net/clh604/article/details/9789839
https://www.douban.com/note/301166150/
【Django】Django 如何实现 如下 联表 JOIN 查询?的更多相关文章
- Django 如何实现 如下 联表 JOIN 查询?
SQL语句: select distinct a.device_hash, sum(b.cmn_merge_count) from (select distinct device_hash from ...
- solr之高级查询--联表 join查询
例如有两个业务表:文章表,评论表 . 场景: 一个文章可以由多个人评论. 创建两个core,一个core叫article,一个叫comment.article实例的schema.xml文件中定义几个简 ...
- Django进阶Model篇006 - 多表关联查询
接着前面的例子,举例多表查询实例如下: 1.查询作战的所有完整信息. >>> AuthorDetail.objects.values('sex','email','address', ...
- springBootJpa 联表分页查询总数不准的问题
问题情景: 在联表查询时 ``` // 两张表关联查询 Join<Project, Plan> planJoin = root.join("plans", JoinTy ...
- 数据库联表统计查询 Group by & INNER JOIN
原数据表 视频信息表 tab_video_info 播放记录表 tab_play_record 需求 统计播放量(已经开始播放)最多的前20个视频: SELECT a.video_id, SUM( ...
- 基于Solr的多表join查询加速方法
前言 DT时代对平台或商家来说最有价值的就是数据了,在大数据时代数据呈现出数据量大,数据的维度多的特点,用户会使用多维度随意组合条件快速召回数据.数据处理业务场景需要实时性,需要能够快速精准的获得到需 ...
- SQL SERVER跨数据库服务,联表进行查询
SELECT * FROM 数据库A..表A a, 数据库B..表B b WHERE a.field=b.field
- 10 ORM 多表操作 查询
1.子查询:基于对象的跨表查询 def query(request): """ 跨表查询: 1.基于对象查询 2.基于双下划线查询 3.聚合.分组查询 4. F Q 查询 ...
- Django之model联表:一对多、跨表操作,联表查询
表结构概述 model.py : class Something(models.Model): name = models.CharField(max_length=32) class UserTyp ...
随机推荐
- HTML布局篇之双飞翼(圣杯)布局
最近在写页面的时候,总是为布局头疼,倒不是不能布出来,就是感觉不系统,没有成一个体系的感觉.所以决定自己写博文,梳理一下思路. 常用的布局方式大致可以分为三种: 浮动布局 Float 负边距(双飞翼) ...
- 修改ssh的访问端口号
[root@redis143 ~]# vim /etc/ssh/sshd_config 修改其中的:Port 10056 重启sshd服务 同时如果有防火墙规则的话,注意修改防火墙规则,或者关闭防火墙 ...
- iOS开发小技巧--设置cell左右有空隙,设置分割线的新思路,重写setFrame:让别人在外界无法修改控件的大小
如图:需要自定义cell
- 负margin一些奇葩的布局技巧
copy_from_ http://www.hicss.net/i-know-you-do-not-know-the-negative-margin/ <!doctype html> &l ...
- 【CodeForces 625C】K-special Tables
题意 把1到n*n填在n*n的格子里.要求每一行都是递增的,使第k列的和最大. 分析 第k列前的格子1 2 .. 按要求填到满格,然后第k列及后面的格子,都从左到右填递增1的数. 第k列的和再加起来, ...
- 【CodeForces 606A】A -特别水的题1-Magic Spheres
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=102271#problem/A Description Carl is a beginne ...
- 【CodeForces 620D】Professor GukiZ and Two Arrays
题 题意 两个数列,一个有n个数,另一个有m个数,让你最多交换两次两个数列的数,使得两个数列和的差的绝对值最小,求这个差的绝对值.最少交换次数.交换数对 分析 交换0次.1次可得到的最小的差可以枚举出 ...
- Excel 计算 tips
1. 对一列数据想看看,distinct的结果 选中数据区域(包含列名),插入pivot table 2. 想检查一个单元格的值在不在某一列中,并返回标志值 =IF (COUNTIF(B:B,A1) ...
- Java编程思想学习(十一) 泛型
1.概要 generics enable types (classes and interfaces) to be parameters when defining classes, interfac ...
- Codeforces 650C Table Compression
传送门 time limit per test 4 seconds memory limit per test 256 megabytes input standard input output st ...