Monkey and Banana(基础DP)
Monkey and Banana
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 11391 Accepted Submission(s): 5958
group of researchers are designing an experiment to test the IQ of a
monkey. They will hang a banana at the roof of a building, and at the
mean time, provide the monkey with some blocks. If the monkey is clever
enough, it shall be able to reach the banana by placing one block on the
top another to build a tower and climb up to get its favorite food.
The
researchers have n types of blocks, and an unlimited supply of blocks
of each type. Each type-i block was a rectangular solid with linear
dimensions (xi, yi, zi). A block could be reoriented so that any two of
its three dimensions determined the dimensions of the base and the other
dimension was the height.
They want to make sure that the
tallest tower possible by stacking blocks can reach the roof. The
problem is that, in building a tower, one block could only be placed on
top of another block as long as the two base dimensions of the upper
block were both strictly smaller than the corresponding base dimensions
of the lower block because there has to be some space for the monkey to
step on. This meant, for example, that blocks oriented to have
equal-sized bases couldn't be stacked.
Your job is to write a program that determines the height of the tallest tower the monkey can build with a given set of blocks.
representing the number of different blocks in the following data set. The maximum value for n is 30.
Each of the next n lines contains three integers representing the values xi, yi and zi.
Input is terminated by a value of zero (0) for n.
each test case, print one line containing the case number (they are
numbered sequentially starting from 1) and the height of the tallest
possible tower in the format "Case case: maximum height = height".
10 20 30
2
6 8 10
5 5 5
7
1 1 1
2 2 2
3 3 3
4 4 4
5 5 5
6 6 6
7 7 7
5
31 41 59
26 53 58
97 93 23
84 62 64
33 83 27
0
Case 2: maximum height = 21
Case 3: maximum height = 28
Case 4: maximum height = 342
Monkey and Banana(基础DP)的更多相关文章
- HDU 1069 Monkey and Banana 基础DP
题目链接:Monkey and Banana 大意:给出n种箱子的长宽高.每种不限个数.可以堆叠.询问可以达到的最高高度是多少. 要求两个箱子堆叠的时候叠加的面.上面的面的两维长度都严格小于下面的. ...
- HDU 1069:Monkey and Banana(DP)
Monkey and Banana Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others ...
- HDU 1069—— Monkey and Banana——————【dp】
Monkey and Banana Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u S ...
- HDU 1069 Monkey and Banana (dp)
题目链接 Problem Description A group of researchers are designing an experiment to test the IQ of a monk ...
- Monkey and Banana(dp,求最长的下降子序列)
A group of researchers are designing an experiment to test the IQ of a monkey. They will hang a bana ...
- HDU 1069 Monkey and Banana(DP——最大递减子序列)
题目链接: http://acm.split.hdu.edu.cn/showproblem.php?pid=1069 题意描述: 给n块砖,给出其长,宽和高 问将这n块砖,怎样叠放使得满足以下条件使得 ...
- HDU1069 - Monkey and Banana【dp】
题目大意 给定箱子种类数量n,及对应长宽高,每个箱子数量无限,求其能叠起来的最大高度是多少(上面箱子的长宽严格小于下面箱子) 思路 首先由于每种箱子有无穷个,而不仅可以横着放,还可以竖着放,歪着放.. ...
- HDU 1069 Monkey and Banana ——(DP)
简单DP. 题意:给出若干种长方体,如果摆放时一个长方体的长和宽小于另一个的长宽,那么它可以放在另一个的上面,问最高能放多少高度.每种长方体的个数都是无限的. 做法:因为每种个数都是无限,那么每种按照 ...
- HDU1069 Monkey and Banana(dp)
链接:http://acm.hdu.edu.cn/showproblem.php?pid=1069 题意:给定n种类型的长方体,每个类型长方体无数个,要求长方体叠放在一起,且上面的长方体接触面积要小于 ...
- 【HDU - 1069】 Monkey and Banana (基础dp)
Monkey and Banana 直接写中文了 Problem Statement 一组研究人员正在设计一项实验,以测试猴子的智商.他们将挂香蕉在建筑物的屋顶,同时,提供一些砖块给这些猴子.如果猴子 ...
随机推荐
- Linux中nmon的安装与使用【转】
一.下载nmon. 根据CPU的类型选择下载相应的版本:http://nmon.sourceforge.net/pmwiki.php?n=Site.Downloadwget http://sour ...
- Redis如何保存数组和对象
个人建议使用PHP自带的序列化函数serialize和unserialize函数 我们可以封装一个自己的Redis类 <?php class MyRedis{ private static $h ...
- asp.net textbox控件readonly为true时,后台取值的问题
如题,在后台通过textbox.Text方式取值为空,不论你默认值是否是空,如想要获得,需通过request.Form[""]的方式.
- ActiveMQ-CPP编译
1.activemq-cpp下载地址: http://activemq.apache.org/cms/download.html 2.相关依赖库 http://mirrors.hust.edu.cn/ ...
- 不注册COM组件直接调用接口
本文以COM组件AppTest.dll为例,AppTest.dll中提供了ITest接口,在不使用regsvr32命令向系统注册的情况下创建ITest接口并调用. 一.导入组件或类型库: 在C++中使 ...
- Myeclipse 创建 Web Maven项目
1.创建Web项目 添加Maven支持 2.pom.xml 报如下错误: 解决办法: pom.xml里面添加依赖: <dependency> <groupId>com.thou ...
- JavaScript 常用功能实现一览(一)
摘自于网络:http://www.cnblogs.com/joinger/articles/1506482.html 适合阅读范围:对JavaScript一无所知-离精通只差一步之遥的人基础知识:HT ...
- How To Install Apache Kafka on Ubuntu 14.04
打算学习kafka ,接触一些新的知识.加油!!! 参考:https://www.digitalocean.com/community/tutorials/how-to-install-apache- ...
- web项目docker化的两种方法
标题所讲的两种方法其实就是创建docker镜像的两种方法 第一种:启动镜像后进入容器中操作,将需要的软件或者项目移动到容器中,安装或者部署,然后退出即可 第二种:编写dockerfile,将需要的镜像 ...
- 织梦DEDE文章列表前面自动加递增数字标签
实现的办法很简单,只须要在序号递增的处所加上这段代码就行 [field:global runphp=""yes"" name=autoindex][/field ...