A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99.

Find the largest palindrome made from the product of two 3-digit numbers.

译文:

 
利用相同的方法寻找回文数。两个2位数字的乘积的最大回文是9009=91×99。

得到两个3位数字的乘积的最大回文。

 import java.util.ArrayList;
 import java.util.List;

 public class Main
 {
     public static void main(String[] args)
     {
         List<Integer> list = new ArrayList<Integer>();
         int a=0;
         for(int i=99;i<1000;i++)
         {
             for(int j=99;j<1000;j++)
             {
                 list.add(j*i);
             }
         }
         List<Integer> lis = new ArrayList<Integer>();
         for(int i=0;i<list.size();i++)
         {
             if(list.get(i)>100000)
             {
                 if(list.get(i) % 10 ==list.get(i) / 100000 && (list.get(i) /10)% 10 ==(list.get(i) / 10000)%10 && (list.get(i) / 1000)%10 ==(list.get(i) / 100)%10)
                 {
                     lis.add(list.get(i));
                 }
             }
         }
         int max=lis.get(0);
         for(int i=0;i<lis.size();i++)
         {
             if(max<lis.get(i))
             {
                 max=lis.get(i);
             }
         }
         System.out.println(max);
     }
 }

结果:

906609

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