M - 约会安排 HDU - 4553 线段树 （最长连续段）

中文题面

思路：维和两个区间  一个是女神区间 一个是基友区间  如果是基友要预约时间 直接在基友区间查询可满足的起点 （这里先判tree[1].m >=length也就是有没有这样的区间满足时间length） 预约成功后更新基友区间

如果是女神要预约区间 先在基友区间预约看有没有满足的区间 （同样看根节点的m） 如果有 同时更新两个区间 如果没有继续在女神区间查找 如果女神区间有 则同时更新基友和女神区间 如果没有 那就真没有了直接输出 题目要求的话

 #include<bits/stdc++.h>
 using namespace std;
 const int maxn=1e6+;
 struct Node{
     int l,r;
     int ml,mr,m;
 }tree1[maxn*],tree2[maxn*];
 void build(int x,int l,int r){
     tree1[x].l=tree2[x].l=l;
     tree1[x].r=tree2[x].r=r;
     tree1[x].ml=tree2[x].ml=tree1[x].mr=tree2[x].mr=tree1[x].m=tree2[x].m=r-l+;
     if(l==r)return ;
     int mid=l+r>>;
     build(x<<,l,mid);
     build(x<<|,mid+,r);
 }
 void push_up(int x){
     int mid=tree1[x].r+tree1[x].l>>;
     tree1[x].ml=tree1[x<<].ml;
     tree1[x].mr=tree1[x<<|].mr;
     tree1[x].m=max(max(tree1[x<<].m,tree1[x<<|].m),tree1[x<<].mr+tree1[x<<|].ml);
     if(tree1[x<<].ml==mid-tree1[x].l+)tree1[x].ml+=tree1[x<<|].ml;
     if(tree1[x<<|].mr==tree1[x].r-mid)tree1[x].mr+=tree1[x<<].mr;
 
     tree2[x].ml=tree2[x<<].ml;
     tree2[x].mr=tree2[x<<|].mr;
     tree2[x].m=max(max(tree2[x<<].m,tree2[x<<|].m),tree2[x<<].mr+tree2[x<<|].ml);
     if(tree2[x<<].ml==mid-tree2[x].l+)tree2[x].ml+=tree2[x<<|].ml;
     if(tree2[x<<|].mr==tree2[x].r-mid)tree2[x].mr+=tree2[x<<].mr;
 
 }
 void push_down(int x){
     int mid=tree1[x].l+tree1[x].r>>;
     if(tree1[x].m==tree1[x].r-tree1[x].l+){
         tree1[x<<].ml=tree1[x<<].mr=tree1[x<<].m=mid-tree1[x].l+;
         tree1[x<<|].ml=tree1[x<<|].mr=tree1[x<<|].m=tree1[x].r-mid;
     }
     else if(tree1[x].m==){
         tree1[x<<].ml=tree1[x<<].mr=tree1[x<<].m=;
         tree1[x<<|].ml=tree1[x<<|].mr=tree1[x<<|].m=;
     }
 
     if(tree2[x].m==tree2[x].r-tree2[x].l+){
         tree2[x<<].ml=tree2[x<<].mr=tree2[x<<].m=mid-tree2[x].l+;
         tree2[x<<|].mr=tree2[x<<|].ml=tree2[x<<|].m=tree2[x].r-mid;
     }
     else if(tree2[x].m==){
             tree2[x<<].ml=tree2[x<<].mr=tree2[x<<].m=;
         tree2[x<<|].mr=tree2[x<<|].ml=tree2[x<<|].m=;
     }
 }
 void update(int x,int l,int r,int value){
     if(tree1[x].l>=l&&tree1[x].r<=r){
         if(value==){
             tree1[x].ml=tree1[x].mr=tree1[x].m=;
         }
         else if(value==){
             tree1[x].ml=tree1[x].mr=tree1[x].m=;
             tree2[x].ml=tree2[x].mr=tree2[x].m=;
         }
         else {
             tree1[x].ml=tree1[x].mr=tree1[x].m=tree1[x].r-tree1[x].l+;
             tree2[x].ml=tree2[x].mr=tree2[x].m=tree1[x].r-tree1[x].l+;
         }
         return ;
     }
     int mid=tree1[x].l+tree1[x].r>>;
     push_down(x);
     if(mid>=l)update(x<<,l,r,value);
     if(mid<r)update(x<<|,l,r,value);
     push_up(x);
 }
 int  query(int x,int length,int value){
     if(tree1[x].l==tree1[x].r)return tree1[x].l;
     push_down(x);
     int mid=tree1[x].l+tree1[x].r>>;
     if(value==){
         if(tree1[x<<].m>=length){
             return query(x<<,length,value);
         }
         else if(tree1[x<<].mr+tree1[x<<|].ml>=length){
             return mid-tree1[x<<].mr+;
         }
         else return query(x<<|,length,value);
     }
     else {
             if(tree2[x<<].m>=length){
             return query(x<<,length,value);
         }
         else if(tree2[x<<].mr+tree2[x<<|].ml>=length){
             return mid-tree2[x<<].mr+;
         }
         else return query(x<<|,length,value);
     }
 }
 int main(){
     int t;
     int kase=;
     scanf("%d",&t);
     char s[];
     int temp;
     int q;
     int  n;
     while(t--){
         printf("Case %d:\n",kase++);
         scanf("%d%d",&n,&q);
         build(,,n);
         while(q--){
             scanf("%s%d",s,&temp);
             if(s[]=='D'){
                 if(tree1[].m>=temp){
                     int start=query(,temp,);
                     update(,start,start+temp-,);
                  printf("%d,let's fly\n",start);
                 }
                 else printf("fly with yourself\n");
             }
             else if(s[]=='N'){
                 if(tree1[].m>=temp){
                     int start=query(,temp,);
                     update(,start,start+temp-,);
                  printf("%d,don't put my gezi\n",start);
                 }
                 else if(tree2[].m>=temp){
                     int start=query(,temp,);
                     update(,start,start+temp-,);
                  printf("%d,don't put my gezi\n",start);
                 }
                 else   printf("wait for me\n");
             }
             else {
                 int zz;
                 scanf("%d",&zz);
                 update(,temp,zz,);
                 printf("I am the hope of chinese chengxuyuan!!\n");
             }
         }
 
     }
     return ;
 }