hdu 1162 Eddy's picture (最小生成树)
Eddy's picture
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6339 Accepted Submission(s): 3179
Problem descriptions as follows: Given you some coordinates pionts on a drawing paper, every point links with the ink with the straight line, causes all points finally to link in the same place. How many distants does your duty discover the shortest length which the ink draws?
Input contains multiple test cases. Process to the end of file.
最小生成树入门题:
//0MS 384K 1215B G++
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
struct point{
double x,y;
}p[];
struct node{
int u,v;
double d;
}t[];
int set[],n;
int cmp(const void*a,const void*b)
{
return (*(node*)a).d>(*(node*)b).d?:-;
}
int find(int x)
{
if(set[x]!=x) set[x]=find(set[x]);
return set[x];
}
int merge(int a,int b)
{
int x=find(a);
int y=find(b);
if(x!=y){
set[x]=y;
return ;
}
return ;
}
double kruskal()
{
double ans=;
for(int i=;i<n*n;i++)
if(merge(t[i].u,t[i].v))
ans+=t[i].d;
return ans;
}
double dis(point a,point b)
{
return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));
}
int main(void)
{
while(scanf("%d",&n)!=EOF)
{
for(int i=;i<=n;i++) set[i]=i;
for(int i=;i<n;i++)
scanf("%lf%lf",&p[i].x,&p[i].y);
int k=;
for(int i=;i<n;i++)
for(int j=;j<n;j++){
t[k].u=i;
t[k].v=j;
t[k].d=dis(p[i],p[j]);
k++;
}
qsort(t,n*n,sizeof(t[]),cmp);
printf("%.2lf\n",kruskal());
}
return ;
}
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