SQL,LINQ,Lambda语法对照图(转载)
如果你熟悉SQL语句,当使用LINQ时,会有似曾相识的感觉.但又略有不同.下面是SQL和LINQ,Lambda语法对照图
SQL |
LINQ | Lambda |
---|---|---|
SELECT * FROM HumanResources.Employee |
from e in Employees select e |
Employees |
SELECT e.LoginID, e.JobTitle FROM HumanResources.Employee AS e |
from e in Employees select new {e.LoginID, e.JobTitle} |
Employees |
SELECT e.LoginID AS ID, e.JobTitle AS Title FROM HumanResources.Employee AS e |
from e in Employees select new {ID = e.LoginID, Title = e.JobTitle} |
Employees |
SELECT DISTINCT e.JobTitle FROM HumanResources.Employee AS e |
(from e in Employees select e.JobTitle).Distinct() |
Employees |
SELECT e.* FROM HumanResources.Employee AS e WHERE e.LoginID = 'test' |
from e in Employees where e.LoginID == "test" select e |
Employees |
SELECT e.* FROM HumanResources.Employee AS e WHERE e.LoginID = 'test' AND e.SalariedFlag = 1 |
from e in Employees where e.LoginID == "test" && e.SalariedFlag select e |
Employees |
SELECT e.* WHERE e.VacationHours >= 2 AND e.VacationHours <= 10 |
from e in Employees where e.VacationHours >= 2 && e.VacationHours <= 10 select e |
Employees |
SELECT e.* FROM HumanResources.Employee AS e |
from e in Employees orderby e.NationalIDNumber select e |
Employees |
SELECT e.* FROM HumanResources.Employee AS e ORDER BY e.HireDate DESC, e.NationalIDNumber |
from e in Employees orderby e.HireDate descending, e.NationalIDNumber select e |
Employees |
SELECT e.* WHERE e.JobTitle LIKE 'Vice%' OR SUBSTRING(e.JobTitle, 0, 3) = 'Pro' |
from e in Employees where e.JobTitle.StartsWith("Vice") || e.JobTitle.Substring(0, 3) == "Pro" select e |
Employees |
SELECT SUM(e.VacationHours) FROM HumanResources.Employee AS e |
Employees.Sum(e => e.VacationHours); |
|
SELECT COUNT(*) FROM HumanResources.Employee AS e |
Employees.Count(); |
|
SELECT SUM(e.VacationHours) AS TotalVacations, e.JobTitle FROM HumanResources.Employee AS e GROUP BY e.JobTitle |
from e in Employees group e by e.JobTitle into g select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)} |
Employees |
SELECT e.JobTitle, SUM(e.VacationHours) AS TotalVacations FROM HumanResources.Employee AS e GROUP BY e.JobTitle HAVING e.COUNT(*) > 2 |
from e in Employees group e by e.JobTitle into g where g.Count() > 2 select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)} |
Employees |
SELECT * FROM Production.Product AS p, Production.ProductReview AS pr |
from p in Products from pr in ProductReviews select new {p, pr} |
Products |
SELECT * FROM Production.Product AS p INNER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID |
from p in Products join pr in ProductReviews on p.ProductID equals pr.ProductID select new {p, pr} |
Products |
SELECT * FROM Production.Product AS p INNER JOIN Production.ProductCostHistory AS pch ON p.ProductID = pch.ProductID AND p.SellStartDate = pch.StartDate |
from p in Products join pch in ProductCostHistories on new {p.ProductID, StartDate = p.SellStartDate} equals new {pch.ProductID, StartDate = pch.StartDate} select new {p, pch} |
Products |
SELECT * FROM Production.Product AS p LEFT OUTER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID |
from p in Products join pr in ProductReviews on p.ProductID equals pr.ProductID into prodrev select new {p, prodrev} |
Products |
SELECT p.ProductID AS ID FROM Production.Product AS p UNION SELECT pr.ProductReviewID FROM Production.ProductReview AS pr |
(from p in Products select new {ID = p.ProductID}).Union( from pr in ProductReviews select new {ID = pr.ProductReviewID}) |
Products |
SELECT TOP (10) * FROM Production.Product AS p WHERE p.StandardCost < 100 |
(from p in Products where p.StandardCost < 100 select p).Take(10) |
Products |
SELECT * FROM [Production].[Product] AS p WHERE p.ProductID IN( SELECT pr.ProductID FROM [Production].[ProductReview] AS [pr] WHERE pr.[Rating] = 5 ) |
from p in Products where (from pr in ProductReviews where pr.Rating == 5 select pr.ProductID).Contains(p.ProductID) select p |
Products |
SQL,LINQ,Lambda语法对照图(转载)的更多相关文章
- SQL,Linq,Lambda之间的转换练习
1.查询Student表中的所有记录的Sname.Ssex和Class列. SQL:select sname,ssex,class from Students linq:from s in Stude ...
- sql linq lambda 对比
. 查询Student表中的所有记录的Sname.Ssex和Class列. select sname,ssex,class from student Linq: from s in Students ...
- SQL-LINQ-Lambda 语法对照
SQL LINQ Lambda SELECT *FROM Employees from e in Employees select e Employees .Select (e => e) ...
- SQL/LINQ/Lamda 写法[转发]
SQL LINQ Lambda SELECT * FROM HumanResources.Employee from e in Employees select e Employees .Sele ...
- SQL Linq lamda区别
SQL LINQ Lambda SELECT * FROM HumanResources.Employee from e in Employees select e Employees .Sele ...
- SQL/LINQ/Lamda
SQL LINQ Lambda SELECT * FROM HumanResources.Employee from e in Employees select e Employees .Sele ...
- SQL-LINQ-Lambda语法对照,好记性不如烂笔头
忘记的时候就翻阅翻阅吧~~ SQL LINQ Lambda SELECT *FROM HumanResources.Employee from e in Employees select e Empl ...
- SQL-LINQ-Lambda语法对照
SQL LINQ Lambda SELECT *FROM HumanResources.Employee from e in Employees select e Employees .Select ...
- 对于SQL的Join,在学习起来可能是比较乱的。我们知道,SQL的Join语法有很多inner的,有outer的,有left的,有时候,对于Select出来的结果集是什么样子有点不是很清楚。Coding Horror上有一篇文章,通过文氏图 Venn diagrams 解释了SQL的Join。我觉得清楚易懂,转过来。
对于SQL的Join,在学习起来可能是比较乱的.我们知道,SQL的Join语法有很多inner的,有outer的,有left的,有时候,对于Select出来的结果集是什么样子有点不是很清楚.Codi ...
随机推荐
- SSH无密码登录配置小结
ssh-keygen -t rsa //-t指定算法 将公钥复制到被管理机器上面 ssh-copy-id -i ~/.ssh/id_rsa.pub 172.29.0.89 ssh-copy-id -i ...
- MVVM模式下实现拖拽
在文章开始之前先看一看效果图 我们可以拖拽一个"游戏"给ListBox,并且ListBox也能接受拖拽过来的数据, 但是我们不能拖拽一个"游戏类型"给它. 所以 ...
- MongoDB 入门之基础 DDL
此文章主要记录部分主要的 MongoDB 的 DDL 操作. db 查看当前所在的数据库(默认 test) > db test > show dbs 查看当前数据库服务器上的数据库名字 ...
- 完数[HDU1406]
完数 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission( ...
- BZOJ3764 : Petya的序列
首先如果一段连续子序列里没有任何幸运数,那么显然可以缩成一个点. 设幸运数个数为$m$,那么现在序列长度是$O(m)$的,考虑暴力枚举$R_1$,然后从右往左枚举$L_1$. 每次碰到一个幸运数,就将 ...
- Arima拟合函数,se出现NaN问题
R语言Arima函数拟合模型,se(标准误)出现NaN的问题. 参考了网上的资料,虽然不太明白是什么意思,但是这样的模型不能用. 参考:http://stackoverflow.com/questio ...
- 2016年AR行业十大热点事件汇总
2016年即将接近尾声,增强现实在今年完成了里程碑式的跃进.无论是从新玩法的开发还是从大众接受度,以及行业巨头的青睐,无不证明这AR的无线潜力,故而,2016年算是AR的崛起之年. 纵观全年AR新闻事 ...
- UVa 10870 & 矩阵快速幂
题意: 求一个递推式(不好怎么概括..)的函数的值. 即 f(n)=a1f(n-1)+a2f(n-2)+...+adf(n-d); SOL: 根据矩阵乘法的定义我们可以很容易地构造出矩阵,每次乘法即可 ...
- POJ 2096 (概率DP)
题目链接: http://poj.org/problem?id=2096 题目大意:n种bug,s个子系统.每天随机找一个bug,种类随机,来自系统随机.问找齐n种bug,且每个子系统至少有一个bug ...
- BZOJ1798[Ahoi2009]Seq 维护序列seq 题解
题目大意: 有长为N的数列,有如下三种操作形式: (1)把数列中的一段数全部乘一个值; (2)把数列中的一段数全部加一个值; (3)询问数列中的一段数的和,由于答案可能很大,你只需输出这个数模P的值. ...