http://codeforces.com/contest/1077/problem/E

output

standard output

Polycarp has prepared nn competitive programming problems. The topic of the ii-th problem is aiai, and some problems' topics may coincide.

Polycarp has to host several thematic contests. All problems in each contest should have the same topic, and all contests should have pairwise distinct topics. He may not use all the problems. It is possible that there are no contests for some topics.

Polycarp wants to host competitions on consecutive days, one contest per day. Polycarp wants to host a set of contests in such a way that:

  • number of problems in each contest is exactly twice as much as in the previous contest (one day ago), the first contest can contain arbitrary number of problems;
  • the total number of problems in all the contests should be maximized.

Your task is to calculate the maximum number of problems in the set of thematic contests. Note, that you should not maximize the number of contests.

Input

The first line of the input contains one integer nn (1≤n≤2⋅1051≤n≤2⋅105) — the number of problems Polycarp has prepared.

The second line of the input contains nn integers a1,a2,…,ana1,a2,…,an (1≤ai≤1091≤ai≤109) where aiai is the topic of the ii-th problem.

Output

Print one integer — the maximum number of problems in the set of thematic contests.

Examples
input

Copy
18
2 1 2 10 2 10 10 2 2 1 10 10 10 10 1 1 10 10
output

Copy
14
input

Copy
10
6 6 6 3 6 1000000000 3 3 6 6
output

Copy
9
input

Copy
3
1337 1337 1337
output

Copy
3
Note

In the first example the optimal sequence of contests is: 22 problems of the topic 11, 44 problems of the topic 22, 88 problems of the topic 1010.

In the second example the optimal sequence of contests is: 33 problems of the topic 33, 66 problems of the topic 66.

In the third example you can take all the problems with the topic 13371337 (the number of such problems is 33 so the answer is 33) and host a single contest.

代码:

    #include <bits/stdc++.h>
using namespace std; const int maxn = 2e5 + 10;
const int N = 1e6 + 5;
int n;
int a[N]; int main() {
scanf("%d", &n);
int cnt = 0;
map<int, int> mp;
for(int i = 1; i <= n; i ++) {
int x;
scanf("%d", &x);
if(!mp[x]) {
cnt ++;
mp[x] = cnt;
}
a[mp[x]] ++;
}
sort(a + 1, a + 1 + cnt);
int ans = 0; for(int i = 1; i <= n; i ++) {
int st = 1;
int m = 0;
for(int k = i; k <= n; k *= 2) {
int pos = lower_bound(a + st, a + 1 + cnt, k) - a;
if(pos == cnt + 1) break;
m += k;
st = pos + 1;
}
ans = max(ans, m);
}
printf("%d\n", ans);
return 0;
}

  

CodeForces Round #521 (Div.3) E. Thematic Contests的更多相关文章

  1. Codeforces Round #521 (Div. 3) E. Thematic Contests(思维)

    Codeforces Round #521 (Div. 3)  E. Thematic Contests 题目传送门 题意: 现在有n个题目,每种题目有自己的类型要举办一次考试,考试的原则是每天只有一 ...

  2. Codeforces Round #521 (Div. 3) E. Thematic Contests (离散化,二分)

    题意:有\(n\)个话题,每次都必须选取不同的话题,且话题数必须是上次的两倍,第一次的话题数可以任意,问最多能选取多少话题数. 题解:我们首先用桶来记录不同话题的数量,因为只要求话题的数量,与话题是多 ...

  3. Codeforces Round #521 (Div. 3) D. Cutting Out 【二分+排序】

    任意门:http://codeforces.com/contest/1077/problem/D D. Cutting Out time limit per test 3 seconds memory ...

  4. CodeForces Round #521 (Div.3) D. Cutting Out

    http://codeforces.com/contest/1077/problem/D You are given an array ss consisting of nn integers. Yo ...

  5. Codeforces Round #521 (Div. 3) F1. Pictures with Kittens (easy version)

    F1. Pictures with Kittens (easy version) 题目链接:https://codeforces.com/contest/1077/problem/F1 题意: 给出n ...

  6. CodeForces Round #521 (Div.3) B. Disturbed People

    http://codeforces.com/contest/1077/problem/B There is a house with nn flats situated on the main str ...

  7. CodeForces Round #521 (Div.3) A. Frog Jumping

    http://codeforces.com/contest/1077/problem/A A frog is currently at the point 00 on a coordinate axi ...

  8. Codeforces Round #521 (Div. 3)

    B 题过的有些牵强,浪费了很多时间,这种题一定想好思路和边界条件再打,争取一发过.  D 题最开始读错题,后面最后发现可以重复感觉就没法做了,现在想来,数据量大,但是数据范围小枚举不行,二分还是可以的 ...

  9. Codeforces Round #521 Div. 3 玩耍记

    A:签到. #include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> ...

随机推荐

  1. Linux 安装 python 指定版本--编译源码方式

    自动化脚本: #!/bin/bash sudo apt-get update sudo apt-get install -y gcc make build-essential libssl-dev z ...

  2. EF core Code First 简单的使用方法

    好吧,我又回来了,其实一直都想写一篇关于EF core 的文章去记录自己在开发时候遇到的问题. 为什么要使用EF框架呢,因为原始的ADO.NET需要编写大量的数据访问代码,所以使用EF会更方便.但是今 ...

  3. 思维导图 XMind 8 Update 8 Pro for Mac 中文破解版

    破解包下载地址 在官网下载8版本就可以了

  4. JVM 垃圾回收机制和常见算法和 JVM 的内存结构和内存分配(面试题)

    一.JVM 垃圾回收机制和常见算法 Sun 公司只定义了垃圾回收机制规则而不局限于其实现算法,因此不同厂商生产的虚拟机采用的算法也不尽相同.GC(Garbage Collector)在回收对象前首先必 ...

  5. 使用nginx对spring boot项目进行代理

    摘要:使用nginx对spring boot项目进行反向代理,并且使用轮询均衡负载策略 均衡负载与集群 集群和均衡都涉及到多个机器提供的服务的问题 不同点是,集群是互相通信.协同的的多个服务,服务之前 ...

  6. 初学Splunk

    splunk简介 https://www.splunk.com/zh-hans_cn/download.html splunk 简体中文版手册 http://docs.splunk.com/Docum ...

  7. vue组件中的样式属性--scoped

    Scoped CSS Scoped CSS规范是Web组件产生不污染其他组件,也不被其他组件污染的CSS规范. vue组件中的style标签标有scoped属性时表明style里的css样式只适用于当 ...

  8. YII2 多MongoDB配置和使用

    1:在config/web.php 文件下配置多个连接即可: 注意在componets 下 'mongodb' => [ 'class' => '\yii\mongodb\Connecti ...

  9. 【动态规划】[UVA1025]A Spy in the Metro 城市里的间谍

    参考:https://blog.csdn.net/NOIAu/article/details/71517440 https://blog.csdn.net/c20180630/article/deta ...

  10. sort()的部分用法

    #include <iostream> #include <cstdio> #include <algorithm>//sort要包含的头文件 #include & ...