Chocolate Bar


Time limit : 2sec / Memory limit : 256MB

Score : 400 points

Problem Statement

There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.

Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize Smax - Smin, where Smax is the area (the number of blocks contained) of the largest piece, and Smin is the area of the smallest piece. Find the minimum possible value of Smax−Smin.

Constraints

  • 2≤H,W≤105

Input

Input is given from Standard Input in the following format:

H W

Output

Print the minimum possible value of Smax−Smin.


Sample Input 1

3 5

Sample Output 1

0

In the division below, Smax−Smin=5−5=0.


Sample Input 2

4 5

Sample Output 2

2

In the division below, Smax−Smin=8−6=2.


Sample Input 3

5 5

Sample Output 3

4

In the division below, Smax−Smin=10−6=4.


Sample Input 4

100000 2

Sample Output 4

 
1

Sample Input 5

100000 100000

Sample Output 5

50000

//问有一块 h*w 的木板,要恰好切成 3 份,且,边长为整数,问切出来的最大面积减最小面积的最小值是多少?

//竟然是一个暴力题,枚举所有切割情况

 #include <bits/stdc++.h>
using namespace std;
#define LL long long
#define INF (1LL<<62) LL slv(LL x,LL y,LL s)
{
LL X = x/,Y = y/;
return min (
max( max(abs(X*y-s),abs((x-X)*y-s)), abs(X*y-(x-X)*y) ),
max( max(abs(x*Y-s),abs((y-Y)*x-s)), abs(Y*x-(y-Y)*x) )
);
} int main()
{
LL h,w;
cin>>h>>w;
LL ans = INF;
for (int i=;i<=h;i++)
ans = min (ans,slv(h-i,w,i*w));
for (int i=;i<=w;i++)
ans = min (ans, slv(w-i,h,i*h));
cout<<ans<<endl;
return ;
}

Chocolate Bar(暴力)的更多相关文章

  1. Educational Codeforces Round 1 E. Chocolate Bar 记忆化搜索

    E. Chocolate Bar Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/598/prob ...

  2. Codeforces Problem 598E - Chocolate Bar

    Chocolate Bar 题意: 有一个n*m(1<= n,m<=30)的矩形巧克力,每次能横向或者是纵向切,且每次切的花费为所切边长的平方,问你最后得到k个单位巧克力( k <= ...

  3. Educational Codeforces Round 1 E. Chocolate Bar dp

    题目链接:http://codeforces.com/contest/598/problem/E E. Chocolate Bar time limit per test 2 seconds memo ...

  4. codeforces 598E E. Chocolate Bar(区间dp)

    题目链接: E. Chocolate Bar time limit per test 2 seconds memory limit per test 256 megabytes input stand ...

  5. Codeforces 598E:Chocolate Bar

    E. Chocolate Bar time limit per test 2 seconds memory limit per test 256 megabytes input standard in ...

  6. CodeForces 598E Chocolate Bar

    区间DP预处理. dp[i][j][k]表示大小为i*j的巧克力块,切出k块的最小代价. #include<cstdio> #include<cstring> #include ...

  7. cf 450c Jzzhu and Chocolate

    Jzzhu and Chocolate time limit per test 1 second memory limit per test 256 megabytes input standard ...

  8. codeforces 490 D Chocolate

    题意:给出a1*b1和a2*b2两块巧克力,每次可以将这四个数中的随意一个数乘以1/2或者2/3,前提是要可以被2或者3整除,要求最小的次数让a1*b1=a2*b2,并求出这四个数最后的大小. 做法: ...

  9. Codeforces 490D Chocolate

    D. Chocolate time limit per test 1 second memory limit per test 256 megabytes input standard input o ...

随机推荐

  1. Python CODE——Nonblocking I/O client AND Delaying Server

    #!Nonblocking I/O - Chapter 5 -pollclient.py import socket,sys,select port=51423 host='localhost' sp ...

  2. oracle获取时间毫秒数

    select (sysdate-to_date('1970-01-01','yyyy-mm-dd')-8/24)*24*60*60*1000-1* 60 * 60 * 1000  millisecon ...

  3. android-seekbar的thumb图片不居中显示的处理办法

    seekbar更换图片后,发现thumb的图片不会居中(竖直方向)显示了,代码如下: <SeekBar android:id="@+id/wb_seekbar" androi ...

  4. C# NPOI操作Excel(上)

    NPOI 官网下载DLL:http://npoi.codeplex.com/releases 1.读取Excel转为DataTable /// <summary> /// 读取excel转 ...

  5. 获取表数据的插入SQL

    DECLARE @TABLE_NAME VARCHAR(200) SET @TABLE_NAME = 'myFunction' --表名 DECLARE @TABLE_CONDITION VARCHA ...

  6. Sklearn 中的 CrossValidation 交叉验证

    1. 交叉验证概述 进行模型验证的一个重要目的是要选出一个最合适的模型,对于监督学习而言,我们希望模型对于未知数据的泛化能力强,所以就需要模型验证这一过程来体现不同的模型对于未知数据的表现效果. 最先 ...

  7. Atitit.跨语言  文件夹与文件的io操作集合  草案

    Atitit.跨语言  文件夹与文件的io操作集合  草案 1. Jdk原生的太难用了..1 2. PS: apache commons-io包,FileUtils有相关的方法,IOUtils一般是拷 ...

  8. Atitit.uml2 api 的编程代码实现设计uml开发 使用eclipse jar java 版本

    Atitit.uml2 api 的编程代码实现设计uml开发 使用eclipse jar java 版本 1. clipse提供了UML的底层Java包, 1 2. MDTUML2Getting St ...

  9. YUV格式详细解释与FFMPEG的关系

    YUV主要的采样格式 主要的采样格式有YCbCr 4:2:0.YCbCr 4:2:2.YCbCr 4:1:1和 YCbCr 4:4:4.其中YCbCr 4:1:1 比较常用,其含义为:每个点保存一个 ...

  10. poj2184 Cow Exhibition(p-01背包的灵活运用)

    转载请注明出处:http://blog.csdn.net/u012860063 题目链接:id=2184">http://poj.org/problem?id=2184 Descrip ...