Dynamic Programming-650. 2 Keys Keyboard
Initially on a notepad only one character 'A' is present. You can perform two operations on this notepad for each step:
Copy All: You can copy all the characters present on the notepad (partial copy is not allowed).Paste: You can paste the characters which are copied last time.
Given a number n. You have to get exactly n 'A' on the notepad by performing the minimum number of steps permitted. Output the minimum number of steps to get n 'A'.
Example 1:
Input: 3
Output: 3
Explanation:
Intitally, we have one character 'A'.
In step 1, we use Copy All operation.
In step 2, we use Paste operation to get 'AA'.
In step 3, we use Paste operation to get 'AAA'.
Note:
- The
nwill be in the range [1, 1000].
class Solution {
public:
int minSteps(int n) {
vector<int> dp(n+,0x7FFFFFFF);
dp[] = dp[] = ;
for(int i=;i<n+;++i){
for(int j=;j<i;++j){
if(i%j==){
dp[i] = min(dp[i], dp[j]+i/j);
}
}
}
return dp[n];
}
};
Dynamic Programming-650. 2 Keys Keyboard的更多相关文章
- [LeetCode] 650. 2 Keys Keyboard 两键的键盘
Initially on a notepad only one character 'A' is present. You can perform two operations on this not ...
- [leetcode] 650. 2 Keys Keyboard (Medium)
解法一: 暴力DFS搜索,对每一步进行复制还是粘贴的状态进行遍历. 注意剪枝的地方: 1.当前A数量大于目标数量,停止搜索 2.当前剪贴板数字大于等于A数量时,只搜索下一步为粘贴的状态. Runtim ...
- LC 650. 2 Keys Keyboard
Initially on a notepad only one character 'A' is present. You can perform two operations on this not ...
- LeetCode 650 - 2 Keys Keyboard
LeetCode 第650题 Initially on a notepad only one character 'A' is present. You can perform two operati ...
- 650. 2 Keys Keyboard复制粘贴的次数
[抄题]: Initially on a notepad only one character 'A' is present. You can perform two operations on th ...
- 650. 2 Keys Keyboard
Initially on a notepad only one character 'A' is present. You can perform two operations on this not ...
- 【LeetCode】650. 2 Keys Keyboard 只有两个键的键盘(Python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 素数分解 日期 题目地址:https://le ...
- [LeetCode] 651. 4 Keys Keyboard 四键的键盘
Imagine you have a special keyboard with the following keys: Key 1: (A): Print one 'A' on screen. Ke ...
- [LeetCode] 2 Keys Keyboard 两键的键盘
Initially on a notepad only one character 'A' is present. You can perform two operations on this not ...
- 动态规划 Dynamic Programming
March 26, 2013 作者:Hawstein 出处:http://hawstein.com/posts/dp-novice-to-advanced.html 声明:本文采用以下协议进行授权: ...
随机推荐
- 删除SVN版本控制目录
@echo On @Rem 删除SVN版本控制目录 @PROMPT [Com] @for /r . %%a in (.) do @if exist "%%a\.svn" rd /s ...
- Loadrunner12.5-录制http://www.gw.com.cn/网页时提示“SSL身份验证失败”错误,这是为什么呢?
问题:LR产品,录制http://www.gw.com.cn/ 网页时提示下图错误,这是为什么呢? 请在如下recording options中选择正确的SSL版本,再进行录制. 注:如何确定那个SS ...
- git 一些提交等用法
从服务器上下载项目到em_cesium:git clone ssh://kjwang@code-bj.clustertech.com:29418/em-satdata em_cesium 在本地新建一 ...
- tp5.1注册路由后接收不到参数
- window下装redis扩展(以php5.5为例)
一.安装redis服务 1.下载并解压 https://github.com/dmajkic/redis/downloads 2.运行redis服务 3.检查能否正常访问 二.安装redis扩展 1 ...
- 2017年UX设计流行的六大趋势
UX设计在接下来的2017年会有怎样的发展趋势呢?让我们一起回顾去年用户体验设计领域中的变化,来展望新一年用户体验设计的发展趋势吧. 1. 原型制作的爆炸性增长 随着用户体验设计师和用户界面设计师 ...
- 强制另存文件和加扩展名的代码c#
强制另存为文件+扩展名的代码using System;using System.Collections.Generic;using System.Linq;using System.Web; name ...
- pca总结,非常详细
#coding=utf- from numpy import * '''通过方差的百分比来计算将数据降到多少维是比较合适的, 函数传入的参数是特征值和百分比percentage,返回需要降到的维度数n ...
- 使用RSA进行信息加密解密的WebService示例
使用RSA进行信息加密解密的WebService示例 按:以下文字涉及RSA对WebService传递的数据的加密解密,如果您已经熟知RSA或是有其它更好的方法请不要往下看以免浪费时间. WebSer ...
- KbmMW 服务器架构简介
kbmmw 由于文档比较少,很多同学开始用时很难理解.一直准备写一个关于kbmmw 架构的东西. 这几天与红鱼儿(blog)研究服务器线程时,整理了一下,大概画了一下kbmmw (版本4.5)服务器的 ...