Codeforces Round #288 (Div. 2) C. Anya and Ghosts 模拟 贪心

C. Anya and Ghosts

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Anya loves to watch horror movies. In the best traditions of horror, she will be visited by m ghosts tonight. Anya has lots of candles prepared for the visits, each candle can produce light for exactly t seconds. It takes the girl one second to light one candle. More formally, Anya can spend one second to light one candle, then this candle burns for exactly t seconds and then goes out and can no longer be used.

For each of the m ghosts Anya knows the time at which it comes: the i-th visit will happen w_i seconds after midnight, all w_i's are distinct. Each visit lasts exactly one second.

What is the minimum number of candles Anya should use so that during each visit, at least r candles are burning? Anya can start to light a candle at any time that is integer number of seconds from midnight, possibly, at the time before midnight. That means, she can start to light a candle integer number of seconds before midnight or integer number of seconds after a midnight, or in other words in any integer moment of time.

Input

The first line contains three integers m, t, r (1 ≤ m, t, r ≤ 300), representing the number of ghosts to visit Anya, the duration of a candle's burning and the minimum number of candles that should burn during each visit.

The next line contains m space-separated numbers w_i (1 ≤ i ≤ m, 1 ≤ w_i ≤ 300), the i-th of them repesents at what second after the midnight the i-th ghost will come. All w_i's are distinct, they follow in the strictly increasing order.

Output

If it is possible to make at least r candles burn during each visit, then print the minimum number of candles that Anya needs to light for that.

If that is impossible, print  - 1.

Sample test(s)

Input

1 8 3
10

Output

3

Input

2 10 1
5 8

Output

1

Input

1 1 3
10

Output

-1

Note

Anya can start lighting a candle in the same second with ghost visit. But this candle isn't counted as burning at this visit.

It takes exactly one second to light up a candle and only after that second this candle is considered burning; it means that if Anya starts lighting candle at moment x, candle is buring from second x + 1 to second x + t inclusively.

In the first sample test three candles are enough. For example, Anya can start lighting them at the 3-rd, 5-th and 7-th seconds after the midnight.

In the second sample test one candle is enough. For example, Anya can start lighting it one second before the midnight.

In the third sample test the answer is  - 1, since during each second at most one candle can burn but Anya needs three candles to light up the room at the moment when the ghost comes.

模拟一下，然后肯定是在这个鬼之前点灯好，越晚点灯越好

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define maxn 1001
const int inf=0x7fffffff;   //无限大
int flag[];
int a[maxn];
int kiss[];
int main()
{
    int m,t,r;
    cin>>m>>t>>r;
    for(int i=;i<m;i++)
    {
        cin>>a[i];
        flag[a[i]+]=;
    }
    if(r>t)
        cout<<"-1"<<endl;
    else
    {
        sort(a,a+m);
        for(int i=;i<;i++)
        {
            if(flag[i]==)
            {
                int check=;
                for(int j=i-;j>=i-t;j--)
                {
                    if(kiss[j]==)
                        check++;
                }
                for(int j=i-;j>=i-(r-check);j--)
                    kiss[j]=;
            }
        }
        int ans=;
        for(int i=;i<;i++)
        {
            if(kiss[i]==)
                ans++;
        }
        cout<<ans<<endl;
    }
}