为0的不要输出。

#include<iostream>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<cstdio>
using namespace std; double a[],b[];
int k; int main()
{
for(int i=;i<=;i++) a[i]=b[i]=;
int Max=-;
scanf("%d",&k);
for(int i=;i<=k;i++)
{
int id;double num;
scanf("%d%lf",&id,&num);
Max=max(Max,id);
a[id]=num;
} scanf("%d",&k);
for(int i=;i<=k;i++)
{
int id;double num;
scanf("%d%lf",&id,&num);
Max=max(Max,id);
b[id]=num;
} int cnt=;
for(int i=Max;i>=;i--)
if(a[i]+b[i]!=) cnt++; printf("%d",cnt);
int op=;
for(int i=Max;i>=;i--)
{
if(a[i]+b[i]!=){
printf(" %d %.1lf",i,a[i]+b[i]);
}
}
return ;
}

PAT (Advanced Level) 1002. A+B for Polynomials (25)的更多相关文章

  1. PTA (Advanced Level) 1002 A+B for Polynomials

    1002 A+B for Polynomials This time, you are supposed to find A+B where A and B are two polynomials. ...

  2. PAT (Advanced Level) Practise - 1094. The Largest Generation (25)

    http://www.patest.cn/contests/pat-a-practise/1094 A family hierarchy is usually presented by a pedig ...

  3. PAT (Advanced Level) 1102. Invert a Binary Tree (25)

    简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #in ...

  4. PAT (Advanced Level) 1098. Insertion or Heap Sort (25)

    简单题.判断一下是插排还是堆排. #include<cstdio> #include<cstring> #include<cmath> #include<ve ...

  5. PAT (Advanced Level) 1067. Sort with Swap(0,*) (25)

    只对没有归位的数进行交换. 分两种情况: 如果0在最前面,那么随便拿一个没有归位的数和0交换位置. 如果0不在最前面,那么必然可以归位一个数字,将那个数字归位. 这样模拟一下即可. #include& ...

  6. PAT (Advanced Level) 1066. Root of AVL Tree (25)

    AVL树的旋转.居然1A了.... 了解旋转方式之后,数据较小可以当做模拟写. #include<cstdio> #include<cstring> #include<c ...

  7. PAT (Advanced Level) 1055. The World's Richest (25)

    排序.随便加点优化就能过. #include<iostream> #include<cstring> #include<cmath> #include<alg ...

  8. PAT (Advanced Level) 1047. Student List for Course (25)

    简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> ...

  9. PAT (Advanced Level) 1082. Read Number in Chinese (25)

    模拟题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #in ...

随机推荐

  1. 用 openSSL 生成 公钥 私钥

    支付宝app接口需要 RSA加密通讯 https://doc.open.alipay.com/doc2/detail?treeId=58&articleId=103242&docTyp ...

  2. 【prim + kruscal 】 最小生成树模板

    来源:dlut oj 1105: Zhuo’s Dream Time Limit: 1 Sec Memory Limit: 128 MBSubmit: 40 Solved: 14[Submit][St ...

  3. WPF Template模版之DataTemplate与ControlTemplate【一】

    WPF Template模版之DataTemplate与ControlTemplate[一] 标签: Wpf模版 2015-04-19 11:52 510人阅读 评论(0) 收藏 举报  分类: -- ...

  4. OpenGL—Android 开机动画源码分析一

    .1 Android开机动画实现方式目前实现Android开机动画的方式主要是逐帧动画和OpenGL动画. ?逐帧动画 逐帧动画是一种常见的动画形式(Frame By Frame),其原理是在“连续的 ...

  5. 404、500、502等HTTP状态码介绍

    基本涵盖了所有问题HTTP 400 – 请求无效HTTP 401.1 – 未授权:登录失败HTTP 401.2 – 未授权:服务器配置问题导致登录失败HTTP 401.3 – ACL 禁止访问资源HT ...

  6. IE 和 FF 写不同的CSS

    .FireFox 下如何使连续长字段自动换行 众所周知IE中直接使用word-wrap:break-word 就可以了, FF中我们使用JS插入的技巧来解决 <style type=" ...

  7. 求n!末尾0的个数

    题目连接 /* £:离散数学. £:n!中2的个数>5的个数. £:2*5=10: */ #include<cstdio> #include<cstring> #incl ...

  8. iOS 开发之照片框架详解

    转载自:http://kayosite.com/ios-development-and-detail-of-photo-framework.html 一. 概要 在 iOS 设备中,照片和视频是相当重 ...

  9. linux系统tomcat项目部署和tomcat访问日志

    一.只用ip地址访问 先把端口号改成80,然后用 <Host name="localhost"  appBase="webapps"    137     ...

  10. CentOS下编译安装Apache2(新)

    官网下载apache,apr, apr-util,pcre httpd-2.4.16.tar.gz http://httpd.apache.org/download.cgi#apache24 apr- ...