对于没有题目积累和clever mind的我来说,想解这道题还是非常困难的,也根本没有想到用dp。

from:

http://blog.csdn.net/u013050857/article/details/45285515

#include <bits/stdc++.h>
using namespace std;
#define LL unsigned long long
LL a[100010];
int main()
{
int n,m;
scanf("%d",&n);
while(n--){
scanf("%d",&m);
memset(a,0,sizeof(a));
LL sum=0,dp=0;
for(int i=1;i<=m;i++){
int x;
scanf("%d",&x);
dp=(i-a[x])*x+dp;
sum+=dp;
a[x]=i;
}
printf("%llu\n",sum);
}
return 0;
}

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