200. Number of Islands + 695. Max Area of Island
Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water. Example 1: Input:
11110
11010
11000
00000 Output: 1
Example 2: Input:
11000
11000
00100
00011 Output: 3
Solution: dfs or bfs or union find
class Solution {
public int numIslands(char[][] grid) {
int res = 0;
for(int i=0; i<grid.length; i++){
for(int j = 0; j<grid[0].length; j++){
if(grid[i][j] == '1'){
res++;
dfs(grid, i, j);
}
}
}
return res;
}
void dfs(char[][] grid, int i, int j){
if(i >= grid.length || i<0 || j>=grid[0].length || j < 0 || grid[i][j] == '0') return;
grid[i][j] = '0'; // visited
dfs(grid, i-1, j);
dfs(grid, i+1, j);
dfs(grid, i, j-1);
dfs(grid, i, j+1);
}
}
FOllow up get max number of islands
695
Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) connected 4-directionally (horizontal or vertical.) You may assume all four edges of the grid are surrounded by water. Find the maximum area of an island in the given 2D array. (If there is no island, the maximum area is 0.) Example 1:
[[0,0,1,0,0,0,0,1,0,0,0,0,0],
[0,0,0,0,0,0,0,1,1,1,0,0,0],
[0,1,1,0,1,0,0,0,0,0,0,0,0],
[0,1,0,0,1,1,0,0,1,0,1,0,0],
[0,1,0,0,1,1,0,0,1,1,1,0,0],
[0,0,0,0,0,0,0,0,0,0,1,0,0],
[0,0,0,0,0,0,0,1,1,1,0,0,0],
[0,0,0,0,0,0,0,1,1,0,0,0,0]]
Given the above grid, return 6. Note the answer is not 11, because the island must be connected 4-directionally.
Example 2:
[[0,0,0,0,0,0,0,0]]
Given the above grid, return 0.
Note: The length of each dimension in the given grid does not exceed 50.
SOlution dfs + array to store the number
class Solution {
int[] a;
public int maxAreaOfIsland(int[][] grid) {
a = new int[grid.length*grid[0].length];
int res = 0;
for(int i=0; i<grid.length; i++){
for(int j = 0; j<grid[0].length; j++){
if(grid[i][j] == 1){
dfs(grid, i, j, res);
res++;
}
}
}
int max = 0;
for(int i = 0; i<res; i++){
//System.out.println(a[i]);
if(max < a[i]) max = a[i];
}
return max;
}
void dfs(int[][] grid, int i, int j,int res){
if(i >= grid.length || i<0 || j>=grid[0].length || j < 0 || grid[i][j] == 0) return;
a[res]++;
grid[i][j] = 0; // visited
dfs(grid, i-1, j, res);
dfs(grid, i+1, j, res);
dfs(grid, i, j-1, res);
dfs(grid, i, j+1, res);
}
}
There is another aolution with dfs without array ....
class Solution {
int[][] grid;
boolean[][] seen; public int area(int r, int c) {
if (r < 0 || r >= grid.length || c < 0 || c >= grid[0].length ||
seen[r][c] || grid[r][c] == 0)
return 0;
seen[r][c] = true;
return (1 + area(r+1, c) + area(r-1, c)
+ area(r, c-1) + area(r, c+1));
} public int maxAreaOfIsland(int[][] grid) {
this.grid = grid;
seen = new boolean[grid.length][grid[0].length];
int ans = 0;
for (int r = 0; r < grid.length; r++) {
for (int c = 0; c < grid[0].length; c++) {
ans = Math.max(ans, area(r, c));
}
}
return ans;
}
}
200. Number of Islands + 695. Max Area of Island的更多相关文章
- leetcode 200. Number of Islands 、694 Number of Distinct Islands 、695. Max Area of Island 、130. Surrounded Regions
两种方式处理已经访问过的节点:一种是用visited存储已经访问过的1:另一种是通过改变原始数值的值,比如将1改成-1,这样小于等于0的都会停止. Number of Islands 用了第一种方式, ...
- [leetcode]python 695. Max Area of Island
Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) conn ...
- LeetCode 695. Max Area of Island (岛的最大区域)
Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) conn ...
- 【easy】695. Max Area of Island
题目: Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) ...
- 695. Max Area of Island最大岛屿面积
[抄题]: 求最多的联通的1的数量 Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (repre ...
- 695. Max Area of Island@python
Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) conn ...
- 【LeetCode】695. Max Area of Island 解题报告(Python & C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:DFS 方法二:BFS 日期 题目地址:ht ...
- [Leetcode]695. Max Area of Island
Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) conn ...
- 695. Max Area of Island
static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { publ ...
随机推荐
- git笔记(三)
详细输出日志 git log --pretty=raw 查看id类型 git cat-file -t fe4c git cat-file -t b36bf6 git cat-file -t b08 ...
- mongodb3.4 远程连接认证失败
mongodb开启或者关闭授权功能时还是挺麻烦的,需要新建服务键入mongod --auth.为了方便,我这里是建了两个服务,用到哪个就切换至哪个服务. --需要授权 mongod --logpath ...
- unity鼠标拖动物体旋转
using System.Collections; using System.Collections.Generic; using UnityEngine; /// <summary> / ...
- 部分linux命令
计算机网络的主要优点是能够实现资源和信息的共享,并且用户可以远程访问信息.Linux提供了一组强有力的网络命令来为用户服务,这些工具能够帮助用户登录到远程计算机上.传输文件和执行远程命令等. 本章介绍 ...
- 深入理解JavaScript系列(49):Function模式(上篇)
介绍 本篇主要是介绍Function方面使用的一些技巧(上篇),利用Function特性可以编写出很多非常有意思的代码,本篇主要包括:回调模式.配置对象.返回函数.分布程序.柯里化(Currying) ...
- 【vm安装vmtools】
使用sudo ./安装命令 对vmware-tools-distrib文件夹里面vmware-install.pl文件夹进行安装 sudo ./vmware-install.pl
- Firebird Case-Insensitive Searching 大小写不敏感查找
Firebird 默认是大小写敏感,在检索的时候. 要想不敏感检索,两种方法: 1.where upper(name) = upper(:flt_name) 2.检索时指定字符集collation,例 ...
- Maven 配置Tomcat
1.Tomcat conf 下的tomcat-users.xml 增加 <role rolename="manager"/> <role rolename=&qu ...
- JS 提交反斜杠\替换成正斜杠/
js将字符串中所有反斜杠\替换成正斜杠/ 区分正斜杠与反斜杠: 正斜杠:http://.http紧跟着的斜杠,离手输入最近的斜杠,shift中间斜杠.45度角斜杠.正斜杠不需要转义 反斜杠:回车与空格 ...
- 一:ActiveMQ知识整理
一:JMS概念 JMS即Java消息服务(Java Message Service)应用程序接口,是一个Java平台中关于面向消息中间件(MOM)的API,用于在两个应用程序之间,或分布式系统中发送消 ...