身份证号码验证算法(php和js实现)

原文:http://blog.chinaunix.net/xmlrpc.php?r=blog/article&uid=21126994&id=3938244

http://www.jb51.net/article/57627.htm

从网上找的,已经测试通过,备忘

js:

//身份证号合法性验证
    //支持15位和18位身份证号
    //支持地址编码、出生日期、校验位验证
    function IdentityCodeValid(code) {

        var city={
            11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古", 21:"辽宁",
            22:"吉林",23:"黑龙江 ",31:"上海",32:"江苏",33:"浙江", 34:"安徽",
            35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北 ", 43:"湖南",
            44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川", 52:"贵州",
            53:"云南",54:"西藏 ",61:"陕西",62:"甘肃",63:"青海", 64:"宁夏",
            65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外 "};
        var tip = "";
        var pass= true;

        if(!code || !/^\d{6}(18|19|20)?\d{2}(0[1-9]|1[12])(0[1-9]|[12]\d|3[01])\d{3}(\d|X)$/i.test(code)){
            tip = "身份证号格式错误";
            pass = false;
        }

        else if(!city[code.substr(0,2)]){
            tip = "地址编码错误";
            pass = false;
        }
        else{
            //18位身份证需要验证最后一位校验位
            if(code.length == 18){
                code = code.split('');
                //∑(ai×Wi)(mod 11)
                //加权因子
                var factor = [ 7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 ];
                //校验位
                var parity = [ 1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2 ];
                var sum = 0;
                var ai = 0;
                var wi = 0;
                for (var i = 0; i < 17; i++)
                {
                    ai = code[i];
                    wi = factor[i];
                    sum += ai * wi;
                }
                var last = parity[sum % 11];
                if(parity[sum % 11] != code[17]){
                    tip = "校验位错误";
                    pass =false;
                }
            }
        }
        if(!pass) alert(tip);
        return pass;
    }
    var c = '130981199312253466';
    var res= IdentityCodeValid(c);

php:

function checkId($id) {

    $len = strlen($id);
    if($len != 18) {
        return 0;
    }

    $a=str_split($id,1);
    $w=array(7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2);

    $c=array(1,0,'X',9,8,7,6,5,4,3,2);

    $sum = 0;
    for($i=0;$i<17;$i++){
            $sum= $sum + $a[$i]*$w[$i];
    }
    $r=$sum%11;
    $res=$c[$r];
    //echo "校验位是: ".$res;
    if ($res == $a[17]) {
        return 1;
    } else {
        return 0;
    }

}