dotnet中文字符工具类

支持繁体简体互换。

 using System;
 using System.Collections.Generic;
 using System.IO;
 using System.Linq;
 using System.Runtime.InteropServices;
 using System.Threading.Tasks;

 namespace DLMApi.Utils
 {
     /// <summary>
     /// 中文字符工具类
     /// </summary>
     public  class ChineseStringUtility
     {
         private const int LOCALE_SYSTEM_DEFAULT = 0x0800;
         private const int LCMAP_SIMPLIFIED_CHINESE = 0x02000000;
         private const int LCMAP_TRADITIONAL_CHINESE = 0x04000000;

         [DllImport("kernel32", CharSet = CharSet.Auto, SetLastError = true)]
         private static extern int LCMapString(int Locale, int dwMapFlags, string lpSrcStr, int cchSrc, [Out] string lpDestStr, int cchDest);

         /// <summary>
         /// 将字符转换成简体中文
         /// </summary>
         /// <param name="source">输入要转换的字符串</param>
         /// <returns>转换完成后的字符串</returns>
         public static string ToSimplified(string source)
         {
             String target = new String(' ', source.Length);
             int ret = LCMapString(LOCALE_SYSTEM_DEFAULT, LCMAP_SIMPLIFIED_CHINESE, source, source.Length, target, source.Length);
             return target;
         }

         /// <summary>
         /// 将字符转换为繁体中文
         /// </summary>
         /// <param name="source">输入要转换的字符串</param>
         /// <returns>转换完成后的字符串</returns>
         public static string ToTraditional(string source)
         {
             String target = new String(' ', source.Length);
             int ret = LCMapString(LOCALE_SYSTEM_DEFAULT, LCMAP_TRADITIONAL_CHINESE, source, source.Length, target, source.Length);
             return target;
         }

         // <summary>
         /// 获取两个字符串的相似度
         /// </summary>
         /// <param name=”sourceString”>第一个字符串</param>
         /// <param name=”str”>第二个字符串</param>
         public static int GetSimilarityWith(string sourceString, string str)
         {
             char[] ss = sourceString.ToCharArray();
             char[] st = str.ToCharArray();

             //获取交集数量
             int q = ss.Intersect(st).Count();
             return q;
         }

     }
 }