Codeforces--597A--Divisibility（数学）



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Time Limit:1000MS    
Memory Limit:262144KB    
64bit IO Format:%I64d & %I64u

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Status Practice CodeForces 597A

Description

Find the number of k-divisible numbers on the segment
[a, b]. In other words you need to find the number of such integer values
x that a ≤ x ≤ b and
x is divisible by k.

Input

The only line contains three space-separated integers k,
a and b (1 ≤ k ≤ 10¹⁸; - 10¹⁸ ≤ a ≤ b ≤ 10¹⁸).

Output

Print the required number.

Sample Input

Input

1 1 10

Output

10

Input

2 -4 4

Output

5

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<algorithm>
using namespace std;
int main()
{
	__int64 a,b,k;
	while(scanf("%I64d%I64d%I64d",&k,&a,&b)!=EOF)
	{
		__int64 ans=0;
		ans=b/k-a/k;
		if(a==0&&b==0)
		cout<<1<<endl;
		else
		{
			if(a>=0&&b>=0&&a%k==0) ans++;
			else if(a<=0&&b<=0&&b%k==0) ans++;
			else if(a<=0&&b>=0) ans++;
			printf("%I64d\n",ans);
		}
	}
	return 0;
}