题目链接:HDOJ - 5183

题目分析

分两种情况,奇数位正偶数位负或者相反。

从1到n枚举,在Hash表中查询 Sum[i] - k ,然后将 Sum[i] 加入 Hash 表中。

BestCoder比赛的时候我写了 STL map, 然后TLE...

注意: Hash负数的时候 % 了一个质数,得到的是负数还要 + Mod !!

代码

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <queue>
#include <map>
#include <set>
#include <vector> using namespace std; #define Debug(x) cout << #x << " = " << x << endl typedef long long LL;
typedef double DB; inline int gmax(int a, int b) {return a > b ? a : b;}
inline int gmin(int a, int b) {return a < b ? a : b;} inline void Read(int &Num)
{
char c = getchar();
bool Neg = false;
while (c < '0' || c > '9')
{
if (c == '-') Neg = true;
c = getchar();
}
Num = c - '0'; c = getchar();
while (c >= '0' && c <= '9')
{
Num = Num * 10 + c - '0';
c = getchar();
}
if (Neg) Num = -Num;
} const int MaxN = 1000000 + 5, Mod = 1000007; int T, n, k;
int A[MaxN]; struct HashNode
{
int x;
HashNode *Next;
} HA[MaxN], *P = HA, *Hash[2][Mod + 5]; bool Find(int f, LL Num)
{
int HN = ((Num % Mod) + Mod) % Mod;
for (HashNode *j = Hash[f][HN]; j; j = j -> Next)
if (j -> x == Num) return true;
return false;
} void Insert(int f, LL Num)
{
int HN = ((Num % Mod) + Mod) % Mod;
++P; P -> x = Num;
P -> Next = Hash[f][HN]; Hash[f][HN] = P;
} int main()
{
scanf("%d", &T);
for (int Case = 1; Case <= T; ++Case)
{
memset(Hash, 0, sizeof(Hash));
P = HA;
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; ++i) Read(A[i]);
int Temp;
LL Sum0, Sum1;
Sum0 = Sum1 = 0;
Insert(1, 0);
bool Flag = false;
for (int i = 1; i <= n; ++i)
{
if (i & 1) Temp = -A[i];
else Temp = A[i];
Sum0 = Sum0 + (LL)Temp;
Sum1 = Sum1 - (LL)Temp;
if (Find(0, Sum0 - (LL)k) || Find(1, Sum1 - (LL)k))
{
Flag = true;
break;
}
if (i & 1) Insert(0, Sum0);
if ((i & 1) == 0) Insert(1, Sum1);
}
if (Flag) printf("Case #%d: Yes.\n", Case);
else printf("Case #%d: No.\n", Case);
}
return 0;
}

  

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