hdu 1570 AC

A C

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4830    Accepted Submission(s): 3115

Problem Description

Are you excited when you see the title "AC" ? If the answer is YES , AC it ;
You must learn these two combination formulas in the school . If you have forgotten it , see the picture.

Now I will give you n and m , and your task is to calculate the answer .

 

Input

In the first line , there is a integer T indicates the number of test cases. Then T cases follows in the T lines. Each case contains a character 'A' or 'C', two integers represent n and m. (1<=n,m<=10)

 

Output

For each case , if the character is 'A' , calculate A(m,n),and if the character is 'C' , calculate C(m,n). And print the answer in a single line.

 

Sample Input

2

A 10 10

C 4 2

 

Sample Output

3628800

6

 #include <iostream>
 using namespace std;
 int f[] = {, };

 int main(){
     for(int i = ; i < ; i++){
         f[i] = i * f[i-];
     }
     int test, n, m;
     char c;
     cin >> test;
     while(test--){
         cin >> c >> n >> m;
         if(c == 'A')
             cout << f[n] / f[n - m] << endl;
         else if(c == 'C')
             cout << f[n] / f[m] / f[n - m] << endl;
     }
     return ;
 }