自己实现sizeof+大小端测试

#define my_sizeof(type) ((char *)(&type+1)-(char*)(&type))

同时大小端测试 如下

#include <stdio.h>
#include <stdlib.h>

#define my_sizeof(type) ((char *)(&type+1)-(char*)(&type))

int main(void)
{
    unsigned int u32RawData;
    unsigned char *pu8CheckData;
    u32RawData = 0x11223344; //Assign data

    printf("%ld\n", my_sizeof(u32RawData));
    printf("%p\n", (&u32RawData+1 - &u32RawData));
    printf("%p\n", (char*)(&u32RawData+1)-(char*)(&u32RawData));
    printf("%p\n", (char*)(&u32RawData)); 

    pu8CheckData = (unsigned char *)&u32RawData; //Type cast

    if (*pu8CheckData == 0x44) //check the value of lower address
    {
        printf("little-endian");
    }
    else if (*pu8CheckData == 0x11) //check the value of lower address
    {
        printf("big-endian");
    }

    return 0;
}

在x86平台测试是小端模式