CF1228F One Node is Gone

题目链接

问题分析

这题感觉就是有很多种方法，然后一种都写不明白……

首先分为3种情况：

• 删了根节点下的一个节点，对应两个答案；
• 删了一个叶节点，对应一个答案；
• 删了一个其他节点，对应一个答案。

可以从叶子向上一层一层处理。第一个情况比较好判断；剩下两种情况通过对应节点儿子的个数来判断。注意第二种情况叶节点最大深度差只能是1，其他的点不能有深度差（毕竟是完全二叉树）。

面向数据编程

参考程序

#include <bits/stdc++.h>
//#include <unistd.h>
using namespace std;
const int Maxn = 131100;
struct edge {
	int To, Next;
	edge() {}
	edge( int _To, int _Next ) : To( _To ), Next( _Next ) {}
};
edge Edge[ Maxn << 1 ];
int Start[ Maxn ], Used;
inline void AddEdge( int x, int y ) {
	Edge[ ++Used ] = edge( y, Start[ x ] );
	Start[ x ] = Used;
	return;
}
int deep, n;
int Deg[ Maxn ], Dep[ Maxn ], Deep, Son[ Maxn ];
int Rec[ Maxn ], Left, Vis[ Maxn ];
int Ans[ 10 ];
int main() {
	scanf( "%d", &deep );
	n = 1; for( int i = 1; i <= deep; ++i ) n *= 2; n -= 2;
	memset( Deg, 0, sizeof( Deg ) );
	for( int i = 1; i < n; ++i ) {
		int x, y;
		scanf( "%d%d", &x, &y );
		AddEdge( x, y );
		AddEdge( y, x );
		++Deg[ x ]; ++Deg[ y ];
	}
	Left = n;
	Deep = 1;
	for( int i = 1; i <= n; ++i )
		if( Deg[ i ] == 1 )
			Dep[ i ] = Deep;
	while( Left > 1 ) {
		//printf( "========================================\n" );
		//printf( "Deg B:\n" );
		//for( int i = 1; i <= n; ++i ) printf( "%d ", Deg[ i ] );
		//printf( "\n" );
		Rec[ 0 ] = 0;
		for( int i = 1; i <= n; ++i )
			if( Deg[ i ] == 1 ) {
				Rec[ ++Rec[ 0 ] ] = i;
				if( Son[ i ] != 3 && Dep[ i ] != Deep ) {
					printf( "0\n" );
					return 0;
				}
				if( Son[ i ] == 3 && Dep[ i ] + 1 != Deep ) {
					printf( "0\n" );
					return 0;
				}
				if( Son[ i ] != 2 && Son[ i ] != 0 ) {
					if( Ans[ 0 ] ) {
						printf( "0\n" );
						return 0;
					}
					Ans[ ++Ans[ 0 ] ] = i;
				}
			}
		//printf( "Rec %d\n", Rec[ 0 ] );
		//for( int i = 1; i <= Rec[ 0 ]; ++i ) printf( "%d ", Rec[ i ] );
		//printf( "\n" );
		if( Rec[ 0 ] == 2 && Left == 2 ) {
			if( Ans[ 0 ] ) {
				printf( "0\n" );
				return 0;
			}
			printf( "2\n%d %d\n", Rec[ 1 ], Rec[ 2 ] );
			return 0;
		}
		for( int i = 1; i <= Rec[ 0 ]; ++i )
			Vis[ Rec[ i ] ] = 1;
		for( int i = 1; i <= Rec[ 0 ]; ++i ) {
			int u = Rec[ i ];
			for( int t = Start[ u ]; t; t = Edge[ t ].Next ) {
				int v = Edge[ t ].To;
				if( Vis[ v ] ) continue;
				--Deg[ u ]; --Deg[ v ];
				++Son[ v ];
				if( Dep[ v ] == 0 ) Dep[ v ] = Deep + 1;
			}
		}
		Left -= Rec[ 0 ];
		++Deep;
		//printf( "Deg A:\n" );
		//for( int i = 1; i <= n; ++i ) printf( "%d ", Deg[ i ] );
		//printf( "\n" );
		//printf( "Left = %d\n", Left );
		//printf( "Son:\n" );
		//for( int i = 1; i <= n; ++i ) printf( "%d ", Son[ i ] );
		//printf( "\n" );
		//printf( "Ans = %d\n", Ans[ 0 ] );
		//sleep( 3 );
	}
	printf( "1\n%d\n", Ans[ 1 ] );
	return 0;
}