问题描述: Work out the first ten digits of the sum of the following one-hundred 50-digit numbers. 371072875339021027987979982208375902465101357402504637693767749000971264812489697007805041701826053874324986199524741059474233309513058123726617309629919422…
The Euler function Time Limit : 2000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 39 Accepted Submission(s) : 19 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description The Euler function…
目录 PE 15 PE 76 PE 90 PE 577 PE 97 PE 364(坑) 待做 发现这个题库,很有意思,趁着还没有学习微积分,看不了书,赶快从头开始刷,所以都是一些简单的题目,即时简单,有一些结论还是很有意思的. 网上资料很少,有的找不到答案,所以只有硬着头皮做了. PE 15 一个网格图,只能向下,或者向右走,问从\((0,0)\)到\((n,m)\)到路径有多少条. 这里的结论是有\(C_{n+m}^n\). 证明:从0,0到n,m会往下走n步,往右走m步,把路径看成一个长度为…
GCD Again Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2611 Accepted Submission(s): 1090 Problem Description Do you have spent some time to think and try to solve those unsolved problem a…
Visible Lattice Points Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 5653 Accepted: 3331 Description A lattice point (x, y) in the first quadrant (x and y are integers greater than or equal to 0), other than the origin, is visible from t…
GCD 描述 The greatest common divisor GCD(a,b) of two positive integers a and b,sometimes written (a,b),is the largest divisor common to a and b,For example,(1,2)=1,(12,18)=6. (a,b) can be easily found by the Euclidean algorithm. Now Carp is considering…
GCD Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description The greatest common divisor GCD(a,b) of two positive integers a and b,sometimes written (a,b),,)=,(,)=. (a,b) can be e…
本题来自 Project Euler 第19题:https://projecteuler.net/problem=19 ''' How many Sundays fell on the first of the month during the twentieth century (1 Jan 1901 to 31 Dec 2000)? Answer: 171 ''' from datetime import * firstDay = date(1901,1,1) lastDay = date(…
开始做 Project Euler 的练习题.网站上总共有565题,真是个大题库啊! # Project Euler, Problem 1: Multiples of 3 and 5 # If we list all the natural numbers below 10 # that are multiples of 3 or 5, we get 3, 5, 6 and 9. # The sum of these multiples is 23. # Find the sum of all…
本题来自 Project Euler 第4题:https://projecteuler.net/problem=4 # Project Euler: Problem 4: Largest palindrome product # A palindromic number reads the same both ways. # The largest palindrome made from the product # of two 2-digit numbers is 9009 = 91 × 9…
/* 题意:(n)表示小于n与n互质的数有多少个,给你两个数a,b让你计算a+(a+1)+(a+2)+......+b; 初步思路:暴力搞一下,打表 #放弃:打了十几分钟没打完 #改进:欧拉函数:具体证明看po主的博客 ^0^ #超时:这里直接用欧拉函数暴力搞还是不可以的,用到线性筛欧拉函数,这里总和爆int,要用long long */ #include<bits/stdc++.h> #define ll long long using namespace std; /***********…
The Euler function Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description The Euler function phi is an important kind of function in number theory, (n) represents the amount of the numbers which are sm…
题目: The Euler function Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 166 Accepted Submission(s): 96 Problem Description The Euler function phi is an important kind of function in number theory…
本题来自 Project Euler 第17题:https://projecteuler.net/problem=17 ''' Project Euler 17: Number letter counts If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total. If all th…
本题来自 Project Euler 第14题:https://projecteuler.net/problem=14 ''' Project Euler: Problem 14: Longest Collatz sequence The following iterative sequence is defined for the set of positive integers: n → n/2 (n is even) n → 3n + 1 (n is odd) Using the rule…
本题来自 Project Euler 第11题:https://projecteuler.net/problem=11 # Project Euler: Problem 10: Largest product in a grid # In the 20×20 grid below, four numbers along a diagonal line have been marked in red. # The product of these numbers is 26 × 63 × 78 ×…
本题来自 Project Euler 第2题:https://projecteuler.net/problem=2 # Each new term in the Fibonacci sequence is generated # by adding the previous two terms. # By starting with 1 and 2, the first 10 terms will be: # 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... # By…