通过重写一个继承自Activity的基类中的onUserLeaveHint()方法,当用户按Home键等操作使程序进入后台时即开始计时,当用户使程序恢复为前台显示时执行onResume()方法,在其中判断是否超时. public class BaseActivity extends Activity { private static final String TAG = "z"; private static SharedPreferences pref; private static…
<?php $arr = array("Linux"); if (in_array(0, $arr)) { echo "match"; } ?> 执行以上代码,0和字符串是可以匹配成功的. 原因是在in_array,如果比较的类型不匹配,并且第一个参数是0,它会返回true(不正确). 查手册:If the third parameter strict is set to TRUE then the in_array() function will al…
SELECT s.sid, s.serial# FROM gv$locked_object l, dba_objects o, gv$session s WHERE l.object_id = o.object_id AND l.session_id = s.sid; alter system kill session 'sid,serial';…