399. Evaluate Division】的更多相关文章

lc 399 Evaluate Division 399 Evaluate Division Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a / b =…
题目如下: Equations are given in the format A / B = k, whereA and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a /…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/delete-and-earn/description/ 题目描述 Equations are given in the format A / B = k, where A and B are variables represented as strings, and k i…
我是链接 看到这道题,2个点和一个权值,然后想到图,但是leetcode就是这样,没给数据范围,感觉写起来很费劲,然后就开始用图来做,添加边的时候,注意正向边和反向变,然后查询的时候,先判断2个点是否都出现,然后判断是不是自己到自己,最后用dfs或者bfs到图里面去搜索,第一次交的时候,忘记用vis标记访问过的点,导致tle,加上之后,就ac了,套路一般吧,不知道还有什么trick. double dfs(vector<vector<pair<int, double> > &…
图像题,没觉得有什么简单的办法,貌似可以用Union Find来解. 感觉有2种思路,一种是先全部构建好每2个点的weight,然后直接遍历queires[][]来抓取答案. 一种是只构建简单的关系图,然后通过DFS来一一找寻要求的答案. 做了一会好他妈的麻烦,最后参考了(http://blog.csdn.net/yeqiuzs/article/details/52506433) 用的是第二种. 需要注意,不存在 优先于 相等 eg : x/x = -1.0, not 1.0, if x DNE…
Evaluate Division题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/evaluate-division/description/ Description Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a / b =…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example: Given a / b =…
Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a / b =…
133. Clone Graph 我们也可以使用 BFS 来遍历图,使用队列 queue 进行辅助,还是需要一个 HashMap 来建立原图结点和克隆结点之间的映射.先克隆当前结点,然后建立映射,并加入 queue 中,进行 while 循环.在循环中,取出队首结点,遍历其所有 neighbor 结点,若不在 HashMap 中,我们根据 neigbor 结点值克隆一个新 neighbor 结点,建立映射,并且排入 queue 中.然后将 neighbor 结点在 HashMap 中的映射结点加…
终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…
UnionFind就是acm中常用的并查集... 并查集常用操作 另外补充一下STL常用操作 相关问题: 547. Friend Circles 纯裸题噢... class Solution { public: ]; ]; void uf_init(int x) { ;i<=x;i++) root[i]=i; } int uf_find(int x) { if(x!=root[x]) root[x]=uf_find(root[x]); return root[x]; } void uf_unio…
突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…
1. Array 基础 27 Remove Element 26 Remove Duplicates from Sorted Array 80 Remove Duplicates from Sorted Array II 277 Find the Celebrity 189 Rotate Array 41 First Missing Positive 299 Bulls and Cows 134 Gas Station 118 Pascal's Triangle 很少考 119 Pascal's…
图基础 图(Graph)应用广泛,程序中可用邻接表和邻接矩阵表示图.依据不同维度,图可以分为有向图/无向图.有权图/无权图.连通图/非连通图.循环图/非循环图,有向图中的顶点具有入度/出度的概念. 面对图相关问题,第一步是将问题转为用图表示(邻接表/邻接矩阵),二是使用图相关算法求解. 相关LeetCode题: 997. Find the Town Judge  题解 1042. Flower Planting With No Adjacent  题解 图的遍历(DFS/BFS) 图的遍历/搜索…
All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…
All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…
源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…
# Title Solution Acceptance Difficulty Frequency     1 Two Sum       44.5% Easy     2 Add Two Numbers       31.7% Medium     3 Longest Substring Without Repeating Characters       28.8% Medium     4 Median of Two Sorted Arrays       27.2% Hard     5…
# Title Solution Acceptance Difficulty Frequency     1 Two Sum       44.5% Easy     2 Add Two Numbers       31.7% Medium     3 Longest Substring Without Repeating Characters       28.8% Medium     4 Median of Two Sorted Arrays       27.2% Hard     5…
终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 把自己刷过的所有题目做一个整理,并且用简洁的语言概括了一下思路,汇总成了一个表格. 题目的排列顺序是按照先Easy再Medium再Hard排列的,暂时还没有把题目全部整理完成.后序我会把刷过的所有的题目都整理到这个文档里. 题目 难度 解法 题目地址 566. Reshape the Matrix Easy 变长数组,求余法,维护行列计算在新的数组中的位置 https://blog.c…
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…
[133]Clone Graph (2019年3月9日,复习) 给定一个图,返回它的深拷贝. 题解:dfs 或者 bfs 都可以 /* // Definition for a Node. class Node { public: int val; vector<Node*> neighbors; Node() {} Node(int _val, vector<Node*> _neighbors) { val = _val; neighbors = _neighbors; } };…
A group of friends went on holiday and sometimes lent each other money. For example, Alice paid for Bill's lunch for $10. Then later Chris gave Alice $5 for a taxi ride. We can model each transaction as a tuple (x, y, z) which means person x gave per…
A group of friends went on holiday and sometimes lent each other money. For example, Alice paid for Bill's lunch for $10. Then later Chris gave Alice $5 for a taxi ride. We can model each transaction as a tuple (x, y, z) which means person x gave per…
在leetcode上刷339题Evaluate Division(https://leetcode.com/problems/evaluate-division/#/description)时在脑中过了一遍想法,大概是生成26棵树,每棵树又有26个子节点,子节点下方对应其父节点与祖父节点相除的结果.使用树结构进行存储.再通过问题给出的字母利用DFS进行搜索.觉得实现起来比较费键盘就没有继续写下去,跑到discuss区看大神的写法.在ycf303(以下简称y神)的答案中第一次接触到unordere…
zabbix的监控类型支持一种calculate的方式,可以对几个item结果进行简单的计算,但有时会出现分母为零的情况,这时候监控项就会报错 Cannot evaluate expression: division by zero. 下面我们做个测试,来解决这个问题: 第一,建立一个测试的监控项: 第二,为监控项传值: zabbix_sender -c 你的配置文件路径 -p 端口 -k "test.get.key_" -o "0" 我们看下结果: 好的,这个监控…
Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, *, /. Each operand may be an integer or another expression. Some examples: ["2", "1", "+", "3", "*"] -&g…