Description 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagona…

id=1163">链接:poj 1163 题意:输入一个n层的三角形.第i层有i个数,求从第1层到第n层的全部路线中.权值之和最大的路线. 规定:第i层的某个数仅仅能连线走到第i+1层中与它位置相邻的两个数中的一个. 状态方程:f[i][j]=max(f[i-1][j-1],f[i-1][j])+a[i][j]; 1163代码: #include<stdio.h> #include<string.h> int a[105][105],f[105][105]; int…

http://poj.org/problem?id=3321 http://acm.hdu.edu.cn/showproblem.php?pid=3887 POJ 3321: 题意:给出一棵根节点为1的边不一定的树,然后给出问题:询问区间和 或者 节点值更新. HDU 3887: 题意:和POJ 3321的题意差不多,只不过对每个节点询问不包含该节点的区间和 思路:今天才学了下才知道有DFS序这种东西,加上树状数组处理一下区间和 和 节点更新. DFS序大概就是我们在DFS遍历一棵树的时候,在进…

POJ 3252:Round Numbers Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10099 Accepted: 3669 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Sciss…

[九度OJ]题目1163:素数 解题报告 标签(空格分隔): 九度OJ 原题地址:http://ac.jobdu.com/problem.php?pid=1163 题目描述: 输入一个整数n(2<=n<=10000),要求输出所有从1到这个整数之间(不包括1和这个整数)个位为1的素数,如果没有则输出-1. 输入: 输入有多组数据. 每组一行,输入n. 输出: 输出所有从1到这个整数之间(不包括1和这个整数)个位为1的素数(素数之间用空格隔开,最后一个素数后面没有空格),如果没有则输出-1. 样…

1.链接地址: http://bailian.openjudge.cn/practice/1163 http://poj.org/problem?id=1163 2.题目: 总时间限制: 1000ms 内存限制: 65536kB 描述 73 88 1 02 7 4 44 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers pa…

The Triangle Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 49955   Accepted: 30177 Description 73 88 1 02 7 4 44 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on…

http://poj.org/problem?id=1163 The Triangle Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 32923   Accepted: 19514 Description 73 88 1 02 7 4 44 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the hi…

看题传送门门:http://poj.org/problem?id=1163 困死了....QAQ 普通做法,从下往上,可得状态转移方程为: dp[i][j]= a[i][j] + max (dp[i+1][j]  , dp[i+1][j+1] ); #include<cstdio> #include<cstring> int a[101][101]; int dp[101][101]; int main() { int n; while(~scanf("%d",…

Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 42232   Accepted: 25527 Description 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route t…