A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 思路: 做过,先复制一遍指针,再复制random位置,再拆分两个链表. #include <iostream> #include <vector> #incl…
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 思路:第一遍正常复制链表,同一时候用哈希表保存链表中原始节点和新节点的相应关系,第二遍遍历链表的时候,再复制随机域. 这是一种典型的空间换时间的做法,n个节点,须要大小为O…
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 本题要求新建一个链表,使其完全等于输入链表,相当于对输入链表深复制. 题目的难点在于,原链表中有random指针,指向原链表对应的结点.当新链表建立时,需要对新…
Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题目意思: 深拷贝一个给定的带random指针的链表,这个random指针可能会指向其他任意一个节点或者是为nu…
Copy List with Random Pointer 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/copy-list-with-random-pointer/description/ Description A linked list is given such that each node contains an additional random pointer which could point to any node in the…
Problem link: http://oj.leetcode.com/problems/copy-list-with-random-pointer/ Deepcopy a linked list with random pointer, realy simple problem, solved in three steps using a hash map: Create a new head, duplicating the head (return NULL for case head=…
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 我们在Java for LeetCode 133 Clone Graph题中做过图的复制,本题和图的复制十分类似,JAVA实现如下: public Random…
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Example 1: Input: {"$id":"1","next":{"$id":"2&…
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道题的难点在于如何处理随机指针,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果在生成一个新节点给其随机指针赋值时,都去遍历原链表的话…
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 和第133题差不多,都是图的复制,区别在于这道题的label有可能是相同的,所以导致了map的key有可能相同,所以需要处理. 两种方法差不多.第二种更简洁. 1.在复制n…
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 剑指offer里面的一道题,具体思路看不懂请查阅剑指offer /** * Definition for singly-linked list with a random…
python代码如下: # Definition for singly-linked list with a random pointer. # class RandomListNode(object): # def __init__(self, x): # self.label = x # self.next = None # self.random = None class Solution(object): def copyRandomList(self, head): ""&q…
职务地址:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题意:对一个有回路的链表的深复制 解题:这道题我AC了之后才发现理解错了题意,然后就參考了以下这篇文章. 假设想看这道题的解题思路的话,请移步http://www.2cto.com/kf/201310/253477.html 拓展:假如题目给的节点不是链表的头节点.而是链表中的随意一个节点,在保证从给的点能遍历所有节点的情况下,深复制这个链表. 那么该怎么做呢…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 数组保存再随机选择 蓄水池抽样 日期 题目地址:https://leetcode.com/problems/linked-list-random-node/description/ 题目描述 Given a singly linked list, return a random node's value from the linked list. E…
原题地址 非常巧妙的方法,不需要用map,只需要O(1)的额外存储空间,分为3步: 1. 先复制链表,但是这个复制比较特殊,每个新复制的节点添加在原节点的后面,相当于"加塞"2. 根据原节点的 ramdon 指针构造新节点的 random 指针3. 恢复原链表结构,同时得到新复制链表 时间复杂度:O(n) 注意random有可能是NULL 代码: RandomListNode *copyRandomList(RandomListNode *head) { RandomListNode…
深拷贝一个链表,不同的是这个链表有个额外的随机指针.参考:http://blog.csdn.net/ljiabin/article/details/39054999 做法非常的巧妙,分成三步,一是新建结点,并放在旧结点之后:二是修改新结点的random指针:三是将新旧链表断开. RandomListNode *randomList(RandomListNode *head) { //复制每个结点,并将新结点放在旧结点之后 for (RandomListNode *cur = head; cur…
public RandomListNode copyRandomList(RandomListNode head) { /* 深复制,就是不能只是复制原链表变量,而是做一个和原来链表一模一样的新链表, 每一个节点都是新建的,而不是指向就节点 这个题的难点在于:随机节点. 随机节点有可能指向后边还没有建立的节点,这就没法指. 方法一:一一对应地记录每个新旧节点的映射关系,在常规节点建立后,就去查哈希表,找到对应 新节点的旧节点的random,就是新节点的random */ if (head==nu…
[1]Two Sum (2018年11月9日,k-sum专题,算法群衍生题) 给了一个数组 nums, 和一个 target 数字,要求返回一个下标的 pair, 使得这两个元素相加等于 target . 题解:我这次最大范围的优化代码, hash-table + one pass,时间复杂度 O(N),空间复杂度 O(N).重点在于动态找,一边生成hash-table的同时去找答案,不是先生成hash-table再开始找答案. //这种类似 hash 的能用 unordered_map 就不要…
[2]Add Two Numbers (2018年11月30日,第一次review,ko) 两个链表,代表两个整数的逆序,返回一个链表,代表两个整数相加和的逆序. Example: Input: ( -> -> ) + ( -> -> ) Output: -> -> Explanation: + = . /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *…
题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题解: 如果要copy一个带有random pointer的list,主要的问题就是有可能这个random指向的位置还没有被copy到,所以解决方法都是多次扫描li…
题目如下: We are given the root node of a maximum tree: a tree where every node has a value greater than any other value in its subtree. Just as in the previous problem, the given tree was constructed from an list A (root = Construct(A)) recursively with…
题目如下: On an NxN chessboard, a knight starts at the r-th row and c-th column and attempts to make exactly K moves. The rows and columns are 0 indexed, so the top-left square is (0, 0), and the bottom-right square is (N-1, N-1). A chess knight has 8 po…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS BFS 日期 题目地址:https://leetcode.com/problems/clone-graph/ 题目描述 Given a reference of a node in a connected undirected graph, return a deep copy (clone) of the graph. Each node…
[LeetCode]380. Insert Delete GetRandom O(1) 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/insert-delete-getrandom-o1/description/ 题目描述: Design a data structure that supports all following oper…
[LeetCode]430. Flatten a Multilevel Doubly Linked List 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/flatten-a-multilevel-doubly-linked-list/description/ 题目描述: You are given…
[LeetCode]117. Populating Next Right Pointers in Each Node II 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/populating-next-right-pointers-in-each-node-ii/description/ 题目描述: Follow up for problem "Populating Next Right Pointers in Each…
[LeetCode]331. Verify Preorder Serialization of a Binary Tree 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/verify-preorder-serialization-of-a-binary-tree/description/ 题目描述: One way to serialize a binary tree is to use pre-order traver…
类同:剑指 Offer 题目汇总索引第26题 Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 说明:分三步, 1. 每个节点复制其本身并链接在后面. 2, 复制…
133. Clone Graph Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node lab…
[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…