题目链接:http://poj.org/problem? id=1028 Description Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features is to use two stacks to keep track of the pages that can be rea…
Web Navigation Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 31088 Accepted: 13933 Description Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features…
题目地址:http://poj.org/problem?id=1028 测试样例: Sample Input VISIT http://acm.ashland.edu/ VISIT http://acm.baylor.edu/acmicpc/ BACK BACK BACK FORWARD VISIT http://www.ibm.com/ BACK BACK FORWARD FORWARD FORWARD QUIT Sample Output http://acm.ashland.edu/ ht…
Description Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features is to use two stacks to keep track of the pages that can be reached by moving backward and forward.…
Web Navigation Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 30828 Accepted: 13821 Description Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features…
一道水题,由于x坐标递增y坐标也递增于是前缀和统计即可,用树状数组实现. #include<bits/stdc++.h> using namespace std; const int maxn=15010; const int maxx=32010; inline long long read(){ long long x=0,f=1; char ch=getchar(); while(ch<'0'||ch>'9'){ if(ch=='-') f=-1; ch=getchar();…
It's hard to construct a problem that's so easy that everyone will get it, yet still difficult enough to beworthy of some respect. Usually, we err on one side or the other. How simple can a problem really be? Here, as in Celebrity Jepoardy, questions…
