The structure of Segment Tree is a binary tree which each node has two attributes startand end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end is given bybuild method…

The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end is given by build meth…

The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end is given by build meth…

Segment Tree Build I The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval. start and end are both integers, they should be assigned in following rules: The root's start and end i…

For a Maximum Segment Tree, which each node has an extra value max to store the maximum value in this node's interval. Implement a modify function with three parameter root, index and value to change the node's value with [start, end] = [index, index…

For an array, we can build a SegmentTree for it, each node stores an extra attribute count to denote the number of elements in the the array which value is between interval start and end. (The array may not fully filled by elements) Design a query me…

For an integer array (index from 0 to n-1, where n is the size of this array), in the corresponding SegmentTree, each node stores an extra attribute max to denote the maximum number in the interval of the array (index from start to end). Design a que…

Lesson learnt: for any calculator problems, keep 2 stacks: 1 for operators and 1 for operands. class Solution { stack<ExpressionTreeNode*> op; stack<ExpressionTreeNode*> data; void eval() { ExpressionTreeNode *opnode = op.top(); op.pop(); Expr…

最后更新 08-Jan-2017 开始介绍线段树的主要作用了,可以快速在区间查找极值,我猜是这样的..... 一个NODE的最大值取决于它左边和右边最大值里大 按个,所以,所以什么?对了,我们该用post-order traversal来构建. public class Solution { public SegmentTreeNode build(int[] A) { // write your code here if (A.length == 0) return null; return…

最后更新 二刷 08-Jan-2017 一刷忘了什么时候做的,只是觉得这几个题挺好的,一步一步手动构建线段树,最终理解了这个数据结构,并且后面有利用的地方. 其实重要的3个东西题目已经提供了: 1) left < right return null 2) left == right return root 3) (left, mid), (mid+1, right) public class Solution { public SegmentTreeNode build(int start, i…