UVa OJ 455 Periodic Strings A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repe…

Periodic Strings 模板 题意分析 判断字符串的最小周期 代码总览 /* Title:UVA.455 Author:pengwill Date:2016-12-16 */ #include <iostream> #include <cstdio> #include <cstring> using namespace std; char str[100]; int main() { int n; scanf("%d",&n); w…

题意:给出一个字符串,找出它的最小的周期,枚举从1到len的周期,看是否满足. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ]; int main() { int ncase,t,i,k,j,len; scanf("%d",&ncase); while(ncase--) { scanf(…

1.题目大意 求一个长度不超过80的字符串的最小周期. 2.思路 非常简单,基本就是根据周期的定义做出来的,几乎不需要过脑. 3.应该注意的地方 (1) 最后输出的方式要注意,不然很容易就PE了.不过个人认为,其实这题Sample Output给的不好 (2) 注意输出的要求是最小周期 4.代码 #include"stdio.h" #include"string.h" #define maxn 80 int main() { int T,m,i,j,flag; ch…

 Periodic Strings  A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repetitions o…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 枚举 [代码] #include <bits/stdc++.h> using namespace std; const int N = 100; char s[N]; int len; bool check(int L) { if (len%L != 0) return false; for (int i = L; i < len; i++) if (s[i] != s[i%L]) return false; retur…

​ A character string is said to have period k if it can be formed by concatenating one or more repetitions of another string of length k. For example, the string "abcabcabcabc" has period 3, since it is formed by 4 repetitions of the string &quo…

如果一个字符串可以被某个长度为k的字符串重复多次得到,则称这个字符串的周期为k.例如,字符串"abcabcabcabc"以3为周期(当然,他也以6.12等等为周期).  现在请你编写一个程序,求出任一长度不超过80的字符串的最小周期. Input 输入首先是一个整数n,代表有n组数据. 每组数据占一行,是一个长度不超过80的字符串. 两组相邻的输入之间有一个空行. Output 每组数据在一行内输出一个整数k,代表该字符串的最小周期. 两组相邻的输出之间应当有一个空行. Sample…

#include<stdio.h> #include<string.h> char s[100]; int main() { int T; scanf("%d",&T); while(T--) { scanf("%s",s); int t = 1; while(1) { int len = strlen(s),c = 0;; for(int i = 0;i < len;i++) { if(s[i] == s[(i + t)%le…

Description Problem D: Power Strings Given two strings a and b we define a*b to be their concatenation. For example, ifa = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiatio…