题目: 最后一个单词的长度 给定一个字符串, 包含大小写字母.空格' ',请返回其最后一个单词的长度. 如果不存在最后一个单词,请返回 0 . 样例 给定 s = "Hello World",返回 5. 注意 一个单词的界定是,由字母组成,但不包含任何的空格. 解题: 利用正则确认是字母,向前走,当遇到不是字母的时候跳出程序,为了合适的跳出定义一个布尔值,是字母的时候是true,当不是字母同时布尔值是true时候跳出 Java程序: public class Solution { /*…

Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space char…

给定一个字符串, 包含大小写字母.空格 ' ',请返回其最后一个单词的长度.如果不存在最后一个单词,请返回 0 .注意事项:一个单词的界定是,由字母组成,但不包含任何的空格.案例:输入: "Hello World"输出: 5详见:https://leetcode.com/problems/length-of-last-word/description/ Java实现: class Solution { public int lengthOfLastWord(String s) { in…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Notice A word is defined as a character sequence consists of non-space ch…

［抄题］: [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: ［奇葩输出条件］: ［奇葩corner case］: "b a " 最后一位是空格,可能误判lastindexof().所以必须用.trim() ［思维问题］: ［一句话思路］: 用函数 再次强调是最后一位的索引是length() - 1 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: ［二刷］: ［三刷］: ［四刷］: ［…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…

[ 问题: ] Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. 给你一个字符串,设法获取它最后一个单词的长度.假设这个单词不存在,则返回0. [ 分析 : ] A word is defined…