【leetcode】997. Find the Town Judge】的更多相关文章

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 度 日期 题目地址:https://leetcode.com/problems/rotting-oranges/ 题目描述 In a town, there are N people labelled from 1 to N. There is a rumor that one of these people is secretly the town…
题目如下: In a town, there are N people labelled from 1 to N.  There is a rumor that one of these people is secretly the town judge. If the town judge exists, then: The town judge trusts nobody. Everybody (except for the town judge) trusts the town judge…
problem 997. Find the Town Judge solution: class Solution { public: int findJudge(int N, vector<vector<int>>& trust) { vector<); ]]--; balance[t[]]++; } ; i<=N; i++) { ) return i; } ; } }; 参考 1. Leetcode_easy_997. Find the Town Judge…
[LeetCode]657. Judge Route Circle 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/judge-route-circle/description/ 题目描述: Initially, there is a Robot at position (0, 0). Given a sequence of its moves, judge if this robot makes a circle, which mea…
Algorithm [leetcode]657. Robot Return to Origin https://leetcode.com/problems/robot-return-to-origin/ 1)problem There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0,…
[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…
Given an index k, return the kth row of the Pascal's triangle. For example, given k = 3, Return [1,3,3,1]. Note: Could you optimize your algorithm to use only O(k) extra space? 思路:最简单的方法就是依照[Leetcode]Pascal's Triangle 的方式自顶向下依次求解,但会造成空间的浪费.若仅仅用一个vect…
53. Maximum Subarray[leetcode] Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4],the contiguous subarray [4,-1,2,1] has the largest sum = 6. 挑…
27. Remove Element[leetcode] Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. The order of elements can b…
[刷题][LeetCode]总 用动画的形式呈现解LeetCode题目的思路 参考链接-空 007-整数反转 方法: 弹出和推入数字 & 溢出前进行检查 思路: 我们可以一次构建反转整数的一位数字.在这样做的时候,我们可以预先检查向原整数附加另一位数字是否会导致溢出. 算法: 反转整数的方法可以与反转字符串进行类比. 我们想重复"弹出" x 的最后一位数字,并将它"推入"到 rev 的后面.最后,rev 将与 x 相反. 要在没有辅助堆栈 / 数组的帮助下…