1022. 从根到叶的二进制数之和 1022. Sum of Root To Leaf Binary Numbers 题目描述 Given a binary tree, each node has value 0 or 1. Each root-to-leaf path represents a binary number starting with the most significant bit. For example, if the path is 0 -> 1 -> 1 ->…

这是小川的第381次更新,第410篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第243题(顺位题号是1022).给定二叉树,每个节点值为0或1.每个根到叶路径表示以最高有效位开始的二进制数.例如,如果路径为0 -> 1 -> 1 -> 0 -> 1,那么这可能表示二进制的01101,即13. 对于树中的所有叶子节点,请考虑从根到该叶子节点的路径所代表的数字.返回这些数字的总和. 例如: 1 / \ 0 1 / \ / \ 0 1 0 1 输入:[1,…

Given a binary tree, each node has value 0 or 1.  Each root-to-leaf path represents a binary number starting with the most significant bit.  For example, if the path is 0 -> 1 -> 1 -> 0 -> 1, then this could represent 01101 in binary, which is…

problem 1022. Sum of Root To Leaf Binary Numbers 参考 1. Leetcode_easy_1022. Sum of Root To Leaf Binary Numbers; 完…

网址:https://leetcode.com/problems/sum-of-root-to-leaf-binary-numbers/ 递归调用求和,同时注意%1000000007的位置 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS 日期 题目地址:https://leetcode.com/problems/sum-of-root-to-leaf-binary-numbers/ 题目描述 Given a binary tree, each node has value 0 or 1. Each root-to-leaf path represents a binary n…

dfs class Solution: def sumRootToLeaf(self, root: TreeNode) -> int: stack=[(root,0)] ans=[] bi_str=[] while stack: node,level=stack.pop() s_len=len(bi_str) if s_len-1<level: bi_str.append(str(node.val)) else: bi_str[level]=str(node.val) del bi_str[l…

题目如下: Given a binary tree, each node has value 0 or 1.  Each root-to-leaf path represents a binary number starting with the most significant bit.  For example, if the path is 0 -> 1 -> 1 -> 0 -> 1, then this could represent 01101 in binary, wh…

题目 class Solution { public: int ans = 0; int sumRootToLeaf(TreeNode* root) { dfs(root,0); return ans; } void dfs(TreeNode*root,int cur){ if(root== NULL) return ; if(root->left == NULL && root->right == NULL){ cur += root->val; ans += cur;…

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. An example is the root-to-leaf path 1->2->3 which represents the number 123. Find the total sum of all root-to-leaf numbers. For example, 1 / \ 2 3…