Rain on your Parade Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 655350/165535 K (Java/Others)Total Submission(s): 6752    Accepted Submission(s): 2117 Problem Description You’re giving a party in the garden of your villa by the sea. The p…

You’re giving a party in the garden of your villa by the sea. The party is a huge success, and everyone is here. It’s a warm, sunny evening, and a soothing wind sends fresh, salty air from the sea. The evening is progressing just as you had imagined.…

HDU 2389 Rain on your Parade / HUST 1164 4 Rain on your Parade(二分图的最大匹配) Description You're giving a party in the garden of your villa by the sea. The party is a huge success, and everyone is here. It's a warm, sunny evening, and a soothing wind send…

题目链接: Hdu 3289 Rain on your Parade 题目描述: 有n个客人,m把雨伞,在t秒之后将会下雨,给出每个客人的坐标和每秒行走的距离,以及雨伞的位置,问t秒后最多有几个客人可以拿到雨伞? 解题思路: 数据范围太大,匈牙利算法O(n*m)果断华丽丽的TLE,请教了一下度娘,发现还有一种神算法—— Hopcroft-Karp,然后就get√新技能,一路小跑过了,有一点不明白的是hdu上竟然有人0ms过,这又是什么神姿势(吓哭!!!!!),额.........,扯远了.  H…

Rain on your Parade Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 655350/165535 K (Java/Others)Total Submission(s): 2154    Accepted Submission(s): 662 Problem Description You’re giving a party in the garden of your villa by the sea. The pa…

Rain on your Parade Time Limit:3000MS     Memory Limit:165535KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 2389 Description You’re giving a party in the garden of your villa by the sea. The party is a huge success, and everyone is h…

<题目链接> 题目大意:有m个宾客,n把雨伞,预计时间t后将会下大雨,告诉你每个宾客的位置和速度,每把雨伞的位置,问你最多几个宾客能够拿到伞. 解题分析: 本题就是要我们求人与伞之间的最大匹配,但是数据量较大,匈牙利算法复杂度为$O(n*m)$,会超时,所以这里用的是复杂度为$O(sqrt(n)*m)$的HK算法. 当然,本题也可以用Dinic最大流来求解最大匹配,并且这种方法求得到最大匹配的时间复杂度也为$O(sqrt(n)*m)$ #include <bits/stdc++.h>…

The Accomodation of Students Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3565    Accepted Submission(s): 1659 Problem Description There are a group of students. Some of them may know each ot…

题目链接:https://vjudge.net/problem/HDU-2389 Rain on your Parade Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 655350/165535 K (Java/Others)Total Submission(s): 4889    Accepted Submission(s): 1612 Problem Description You’re giving a party in t…

大意:在一个二维坐标系上有nx个人和ny把伞,每个人都有自己的移动速度,问有多少人可以再 time 时间内移动到不同的雨伞处(不允许两个人共用一把伞).   输入数据: 第一行是一个T代表T组测试数据. 开始是一个数字  time (1 <=time<= 5) 代表还有t时间就开始下雨了.  接下来是一个数字m代表宾客的数量. 接下来m行每行一个x,y 代表宾客所在的坐标, s代表宾客移动的速度 然后是一个数字n  代表伞的数量. 接下来n行就是伞的坐标.(所有坐标的绝对值是小于10000的)…

奔小康赚大钱 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1836    Accepted Submission(s): 798 Problem Description 传说在遥远的地方有一个非常富裕的村落,有一天,村长决定进行制度改革:重新分配房子.这可是一件大事,关系到人民的住房问题啊.村里共有n间房间,刚好有n家老百姓,考虑到每…

http://acm.hdu.edu.cn/showproblem.php?pid=6178 题意:现在有一n个顶点的树形图,还有k只猴子,每个顶点只能容纳一只猴子,而且每只猴子至少和另外一只猴子通过边相连,现在要删边,保留最少的边使得满足题意. 思路: 贪心的想一想,顶点两两匹配时一条边的贡献值就是两只猴子,那这不就是二分匹配吗.所以先求个二分匹配即可,然后如果此时还是不够的话,那么剩下的猴子每只猴子都需要一条边. 如果用二分匹配的算法可能不太行,虽然看别人用Hopcroft-Carp算法跑了…

 HK.... Rain on your Parade Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 655350/165535 K (Java/Others)Total Submission(s): 2229    Accepted Submission(s): 696 Problem Description You're giving a party in the garden of your villa by the sea…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=3081 题意 有n对男女 女生去选男朋友 如果女生从来没和那个男生吵架 那么那个男生就可以当她男朋友 女生也可以选择从来没和自己闺蜜吵过架的男生当男朋友 如果 女生A和女生B是闺蜜 女生A和男生C吵过架 但是女生B和男生C从来没吵过架 那么女生A是可以选择男生C当男朋友的. 看来 讨好闺蜜是一件多么重要的事情.. T T组数据 给出 n, m, f 有N对男女, m对从未吵架关系 f 对闺蜜关系 思路…

Kingdom of Obsession Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 49    Accepted Submission(s): 14 Problem Description There is a kindom of obsession, so people in this kingdom do things very…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=2236 代码: #include<cstdio> #include<cstring> #include<cmath> #include<iostream> #include<algorithm> using namespace std; #define N 105 #define INF 0xffffff ///匹配 ///只需要用二分找一个区间, //…

读题显然是二分图匹配,看成guest与umbrella的匹配.匈牙利果断TLE了,其实时间卡的相当紧.HK过的,750ms. /* 2389 */ #include <iostream> #include <string> #include <map> #include <queue> #include <set> #include <stack> #include <vector> #include <algori…

题意:婚配问题,但是题目并不要求输出最大匹配值,而是让我们输出,一个王子可以与哪些王妃婚配而不影响最大匹配值. 解决办法:先求一次最大匹配,如果有两个已经匹配的王妃,喜欢她们两个的有两个或者以上相同的王子,那她们两个是可以交换的,对于前面的王子来说,他与这两个王妃中的任何一个匹配都不会影响最大匹配值,因为总有人把位置补上.那什么样的王妃才是可以交换的王妃呢?我们在这个王子已经匹配的王妃match[i]与他喜欢的王妃v连一条有向边,那样处在一个强联通分量的两个王妃就是可以相互交换的. 下面处理没有…

题意见大佬:https://www.cnblogs.com/gj-Acit/archive/2013/08/17/3265502.html 题目大意很明确,交换图的某些行或者是某些列(可以都换),使得这个N*N的图对角线上全部都是1. 这里有一点需要说明,就是说题目的交换,其实是将原来图的某一行移到最后图的某一行,而不是指先交换两行,得到一个新图,再交换新图的两行.感觉这里比较坑. 这里先说明的一点就是,如果通过交换某些行没有办法的到解的话,那么只交换列 或者 既交换行又交换列 那也没办法得到解…

http://acm.hdu.edu.cn/showproblem.php?pid=2444 [DFS染色] #include<iostream> #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<algorithm> using namespace std; ; const int maxm=maxn*maxn; struct e…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5090 Problem Description Tom and Jerry are playing a game with tubes and pearls. The rule of the game is: 1) Tom and Jerry come up together with a number K.  2) Tom provides N tubes. Within each tube, th…

Description Jimmy is studying Advanced Graph Algorithms at his university. His most recent assignment is to find a maximum matching in a special kind of graph. This graph is undirected, has N vertices and each vertex has degree 3. Furthermore, the gr…

题意:每个人有喜欢的猫和不喜欢的狗.留下他喜欢的猫他就高心,否则不高心.问最后最多有几个人高心. 思路:二分图求最大匹配 #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<cstdlib> #include<string> #include<cmath> #include<vector> #def…

Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5371    Accepted Submission(s): 2658 Problem Description As we all know, machine scheduling is a very classical problem in compu…

Jimmy’s Assignment Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 464    Accepted Submission(s): 224 Problem Description Jimmy is studying Advanced Graph Algorithms at his university. His most…

过山车 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 22693    Accepted Submission(s): 9797 Problem Description RPG girls今天和大家一起去游乐场玩,终于可以坐上梦寐以求的过山车了.可是,过山车的每一排只有两个座位,而且还有条不成文的规矩,就是每个女生必须找个个男生做par…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2426 For any school, it is hard to find a feasible accommodation plan with every student assigned to a suitable apartment while keeping everyone happy, let alone an optimal one. Recently the president of…

题目大意:学生给出其成绩区间,但可能出现矛盾情况,找出合理组合使没有说谎的人尽可能多,并按maximum lexicographic规则输出组合. //用学生去和成绩匹配,成绩区间就是学生可以匹配的成绩 #include <iostream> #include <queue> #include <vector> #define N 100005 using namespace std; struct Node { int f,t; }; Node lis[]; int…

先把代码贴上,其他南京回来再补了.. #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <algorithm> #include <iostream> #include <ctime> #include <vector> #include <list> #include <queu…

二分匹配:二分图的一些性质 二分图又称作二部图,是图论中的一种特殊模型. 设G=(V,E)是一个无向图,如果顶点V可分割为两个互不相交的子集(A,B),并且图中的每条边(i,j)所关联的两个顶点i和j分别属于这两个不同的顶点集(i in A,j in B),则称图G为一个二分图. 1.一个二分图中的最大匹配数等于这个图中的最小点覆盖数 König定理是一个二分图中很重要的定理,它的意思是,一个二分图中的最大匹配数等于这个图中的最小点覆盖数.如果你还不知道什么是最小点覆盖,我也在这里说一下:假如选…