Given the running logs of n functions that are executed in a nonpreemptive single threaded CPU, find the exclusive time of these functions. Each function has a unique id, start from 0 to n-1. A function may be called recursively or by another functio…

Given the running logs of n functions that are executed in a nonpreemptive single threaded CPU, find the exclusive time of these functions. Each function has a unique id, start from 0 to n-1. A function may be called recursively or by another functio…

636. Exclusive Time of Functions 1.Problem Given the running logs of n functions that are executed in a nonpreemptive single threaded CPU, find the exclusive time of these functions. Each function has a unique id, start from 0 to n-1. A function may…

Given the running logs of n functions that are executed in a nonpreemptive single threaded CPU, find the exclusive time of these functions. Each function has a unique id, start from 0 to n-1. A function may be called recursively or by another functio…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 栈 日期 题目地址:https://leetcode.com/problems/exclusive-time-of-functions/description/ 题目描述 Given the running logs of n functions that are executed in a nonpreemptive single threaded…

题目如下: 解题思路:本题和括号匹配问题有点像,用栈比较适合.一个元素入栈前,如果自己的状态是“start”,则直接入栈:如果是end则判断和栈顶的元素是否id相同并且状态是“start”,如果满足这两个条件,则说明这个元素和栈顶的元素是配对的,栈顶元素出栈.但是这个函数的的执行时间却不能简单的用end-start,因为这个函数里面可以还调用了其他函数,需要减去这些内部调用函数的执行时间,这里就需要引入一个新的变量来保存内部调用函数的执行时间.这个时间也很好求,函数完成配对后,栈顶元素出栈,只要…

［抄题］: Given the running logs of n functions that are executed in a nonpreemptive single threaded CPU, find the exclusive time of these functions. Each function has a unique id, start from 0 to n-1. A function may be called recursively or by another f…

// TODO: need improve!!! class Log { public: int id; bool start; int timestamp; int comp; // compasation Log() { id = ; timestamp = ; comp = ; start = false; } }; class Solution { public: vector<int> exclusiveTime(int n, vector<string>& lo…

Given the running logs of n functions that are executed in a nonpreemptive single threaded CPU, find the exclusive time of these functions. Each function has a unique id, start from 0 to n-1. A function may be called recursively or by another functio…

636. 函数的独占时间 给出一个非抢占单线程CPU的 n 个函数运行日志,找到函数的独占时间. 每个函数都有一个唯一的 Id,从 0 到 n-1,函数可能会递归调用或者被其他函数调用. 日志是具有以下格式的字符串:function_id:start_or_end:timestamp.例如:"0:start:0" 表示函数 0 从 0 时刻开始运行."00" 表示函数 0 在 0 时刻结束. 函数的独占时间定义是在该方法中花费的时间,调用其他函数花费的时间不算该函数…