problem 720. Longest Word in Dictionary 题意: solution1: BFS; class Solution { public: string longestWord(vector<string>& words) { string res = ""; unordered_set<string> s(words.begin(), words.end()); queue<string> q; for(aut…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

［抄题］: Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smal…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力查找 排序 日期 题目地址:https://leetcode.com/problems/longest-word-in-dictionary/description/ 题目描述 Given a list of strings words representing an English Dictionary, find the longest wo…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: string longestWord(vector<string>& words) { unordered_set<string> siset(words.begin(),words.end()); string res; for(string s:words) { i…

b.compareTo(a) 这个函数是比较两个值得大小,如果b比a大,那么返回1 如果小,那么返回-1,相等返回0 如果比较的是字符串,那么比较字典编纂顺序,b靠前返回-1,靠后返回1 这个题的核心虽然是hashtable,但是这个方法还是很重要的,因为自己实现比较字符串很麻烦 /* 用一个Hashset来判断子串是不是在集合里 然后遍历出最长的就行 长度相同的用compareTo方法判断谁的字典顺序靠前 这个题最难的感觉其实是不知道compareTo方法,自己实现还挺麻烦的 */ publi…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

目录 题目链接 注意点 解法 小结 题目链接 Longest Word in Dictionary through Deleting - LeetCode 注意点 长度一样的字符串要按字典序返回较小的 解法 解法一:遍历字典中的单词,用一个变量i来记录单词中的某个字母的位置,我们遍历给定字符串,如果遍历到单词中的某个字母来,i自增1,如果没有,就继续往下遍历.这样如果最后i和单词长度相等,说明单词中的所有字母都按顺序出现在了字符串s中.如果能得到,而且单词长度大于等于结果ret的长度,我们再看是…