1.题目描述 2.问题分析 按照手算乘法的过程进行计算,首先计算乘法,然后计算加法. 3.代码 string multiply(string num1, string num2) { string small ; string big; if( num1.size() < num2.size() ){ small = num1; big = num2; }else if( num2.size() < num1.size() ){ small = num2; big = num1; }else{…

1 题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 接口: public String multiply(String num1, String num2); 2 思路 大整数的乘法,不能够简单用Integer.valueOf(…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 43: Multiply Stringshttps://leetcode.com/problems/multiply-strings/ Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbit…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题目意思: 给两个string,计算string的乘积. string中的数可以非常大并且是非负数. (就是大数的乘法运算嘛...) 解题思路: 由于之…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 将乘积逐位逆序存放在int数组result中. 记num1当前为第i位,num2当前为第j位,则乘积存放在result[(n1-1-i)+(n2-1-j…

思路:高精度乘法就可以了. 有两个错误以前没在意,1.成员属性定义时候不能进行初始化, vector<); 这样隐性调用了函数进行初始化的形式特别要注意,也是错误的: 2.容器类只有分配了空间时才能用=赋值,否则要用push_back之类函数插入元素. class Solution { public: void add(vector<int>& res, vector<int>& ans, int shift) { ; int i; ;j < shift…

一天一道LeetCode系列 (一)题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT us…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/multiply-strings/description/ 题目描述 Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and nu…

1. 原题链接 https://leetcode.com/problems/multiply-strings/description/ 2. 题目要求 给定两个String类型的正整数num1.num2,返回它们的String类型乘积 (1)num1和num2的长度都小于110: (2)num1.num2都只包含0-9之间的字符: (3)num1.num2的首位都不为0: (4)不能使用BigInteger,也不能字符串转直接换成整数类型 3. 解题思路 首先题目要求不能直接将String转换成…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 给出两个字符串,返回对应数字想乘后的字符串,由于这个字符串可能很大,所以不能采用一般的乘法,这里用的方法是模拟手工的乘法运算,算法 本身很简单,就是当时写的时候有些很小的细节搞错了,找了…